strtotime

//获取相应周的开始时间（星期日）到（周六） function getWeekDate($year,$mon,$day){ $date1=$year.'-'.$mon.'-'.$day; $sun=$date1; $mon=date('Y-m-d',strtotime("$date1 +1 day")); $tues=date('Y-m-d',strtotime("$date1 +2 day")); $wed=date('Y-m-d',strtotime("$date1 +3 day")); $thurs=date('Y-m-d',strtotime("$date1 +4 day")); $fri=date('Y-m-d',strtotime("$date1 +5 day")); $sat=date('Y-m-d',strtotime("$date1 +6 day")); return array($sun,$mon,$tues,$wed,$thurs,$fri,$sat); } 代码的参数为年月日三项，可以更改成一个参数(周日的日期) 来源： https://www.cnblogs.com/leaf-blog/p/11731570.html

function getMonDate($start,$end){ $monArr=array(); $dt_start = strtotime($start); $dt_end = strtotime($end); while ($dt_start<=$dt_end){ $monArr[]=date('Y-m-d',$dt_start); $dt_start = strtotime('+1 day',$dt_start); } return $monArr; } 来源： https://www.cnblogs.com/leaf-blog/p/11731571.html

时间参数详解 　　a - "am" 或是 "pm" 　　 A - "AM" 或是 "PM" 　　 d - 几日，二位数字，若不足二位则前面补零; 如: "01" 至 "31" 　　 D - 星期几，三个英文字母; 如: "Fri" 　　 F - 月份，英文全名; 如: "January" 　　 h - 12 小时制的小时; 如: "01" 至 "12" 　　 H - 24 小时制的小时; 如: "00" 至 "23" 　　 g - 12 小时制的小时，不足二位不补零; 如: "1" 至 12" 　　 G - 24 小时制的小时，不足二位不补零; 如: "0" 至 "23" 　　 i - 分钟; 如: "00" 至 "59" 　　 j - 几日，二位数字，若不足二位不补零; 如: "1" 至 "31" 　　 l - 星期几，英文全名; 如: "Friday" 　　 m - 月份，二位数字，若不足二位则在前面补零; 如: "01" 至 "12" 　　 n - 月份，二位数字，若不足二位则不补零; 如: "1" 至 "12" 　　 M - 月份，三个英文字母; 如: "Jan" 　　 s - 秒; 如: "00" 至 "59" 　　 S - 字尾加英文序数，二个英文字母; 如: "th"，"nd" 　　 t - 指定月份的天数; 如: "28" 至 "31" 　　 U - 总秒数 　　

Not really an issue (although it is conflicting with an if() statement we have), but when you type in strtotime('cast'), it returns an actual value that defaults to today's date. I was just wondering if anyone knew what significance the word cast has when it comes to time functions Thanks! It maps to the timezone offset for "Australia/Adelaide" . Example: echo date('Y-m-d H:i:s'), "\n", date('Y-m-d H:i:s', strtotime("cast")), "\n", date('Y-m-d H:i:s', strtotime("Australia/Adelaide")); Prints: 2016-08-25 10:48:44 2016-08-25 01:18:44 2016-08-25 01:18:44 来源： https://stackoverflow.com/questions

I'm working on a PHP function which calculates holidays: function holidays($country = 1, $timespan_start = 0, $timespan_end = 0) The holidays are returned as timestamps in an array. Since I have to calculate dates like the first Monday of February, I tried strtotime("first monday february $year") and I've discovered that this does not work for 2010, since 02/01/2010 is a Monday - I get February 8th instead. This bug is actually mentioned in the change log: In PHP 5 prior to 5.2.7, requesting a given occurrence of a given weekday in a month where that weekday was the first day of the month

环境php本地写接口 1.PHP工具箱配置好相应的本地域名 2.下载一个客户端postman 　　1.按日查询.接口传过来 $page $uid $time /* * 2019.10.15 *订单统计 * & 骑手的id * orderstatistics 按日查询 * */public function orderstatistics(){ $res = []; $param = input(''); $page = input('page'); $uid = $param['uid'];//骑手的id $time = $param['time'];//查询的时间 $data = $this-> order -> statistics($uid,$time,$page);//获取订单的列表 foreach ($data['data'] as $k=>&$v){ // status = 1：已接单 2：取货中 3：已取消 4：配送中 5：已完成 6：已评价', switch ($v['status']){ case 1: $v['status_name'] = '已接单';break; case 2: $v['status_name'] = '取货中';break; case 3: $v['status_name'] = '已取消';break; case 4: $v[

I have a string with a date which is in this format MMDDYYYY (ie. 01132012, 01142012 etc.) I need to do something on a page, if that string is 14 days or less from the current date. ie. Today is 01132012, so any strings with 12312011 or a less date are going to be showing something on a page. Can anyone help with this? I've tried echo date("d/m/Y", strtotime('01142012')); But to no avail. You can use the DateTime class of PHP <? // current date $now = new DateTime(); //your date $date = DateTime::createFromFormat('mdY', '01142012'); // calculate difference $diff = $now->diff($date); ... //

今天 $mapday = array(); $today = strtotime(date('Y-m-d', time())); //当前时间 $start_today = $today; $end_today = $today + 86400; //,获取明天，一天是86400(时间戳) $mapday['create_time'] = array( //数据表字段create_time进行条件判断 array('egt', $start_today), array('lt', $end_today), ); 本周 //查询周日至周六数据记录 $mapweek['create_time'] = array( array('egt', strtotime(date('Y-m-d', time()).'-'.date('w', time()).' day')), array('lt', strtotime(date('Y-m-d', time()).'+1 week -'.date('w', time()).' day')),//一周内 ); //查询周一至周日记录 $mapweek['create_time'] = array( array('egt', strtotime(date('Y-m-d', time()).'+1 day -'.date('w', time()).'

I want to get the timestamp of a day/time for eg 17/12/2014 8pm Currently I am doing $curtime = strtotime(date("Y-m-d H:i:s")); which is giving me the current timestamp but I need to be of 8pm. Any help is highly appreciated. Thanks in advance. If you're trying to get a timestamp of today at 8pm, it's actually much more simple than using date since you can use relative times in a strtotime : $curtime = strtotime('today 8pm'); If you test this with date : echo date('Y-m-d H:i:s', $curtime); // Returns 2014-12-17 20:00:00 Here's a whole writeup on relative date formats that explains how you can