strtotime

1、获取当前时间方法date() 很简单，这就是获取时间的方法，格式为：date(format,format,timestamp)，format为格式、timestamp为时间戳–可填参数。 2、获取时间戳方法time()、strtotime() 这两个方法，都可以获取php中unix时间戳，time()为直接获取得到，strtotime(time,time,now)为将时间格式转为时间戳，$time为必填。清楚了这个，想了解更多，请继续往下看。 3、 date($format)用法 比如： echo date(‘Y-m-d’) ，输出结果：2012-03-22 echo date(‘Y-m-d H:i:s’)，输出结果：2012-03-22 23:00:00 echo date(‘Y-m-d’, time())，输出结果：2012-03-22 23:00:00（结果同上，只是多了一个时间戳参数）（时间戳转换为日期格式的方法） echo date(‘Y’).’年’.date(‘m’).’月’.date(‘d’).’日’，输出结果：2012年3月22日 举例就这几个，只是格式的变通而已，下面是格式中各个字母的含义： /****格式中可使用字母的含义****/ a - “am” 或是 “pm” A - “AM” 或是 “PM” d - 几日，二位数字，若不足二位则前面补零; 如:

I am using the following code to get a Y-m-d format of weekdays: $monday = date('Y-m-d', strtotime('Monday')); $tuesday = date('Y-m-d', strtotime('Tuesday')); $wednesday = date('Y-m-d', strtotime('Wednesday')); $thursday = date('Y-m-d', strtotime('Thursday')); $friday = date('Y-m-d', strtotime('Friday')); Today is 2012-08-01 (week 31) the Monday value I need should be 2012-07-30. How come strtotime('Monday') makes it next monday? Because date('Y-m-d') returns today's date i.e.., month of august. And you are converting monday to time . now that time is represented in terms of date(Y-m-d)

I' m trying to make a ajax calendar with multiple tabs for a date range previously entered. But for example: I want get the next month, it prints march instead of february $start= "2013-01-31"; $current = date('n', strtotime("+1 month",$start)) //prints 3 I think thats occurs because february 2014 is 28 and add +31 like base from the start month but why? You're trying to add one month to the date 2013-01-31 . It should give 31th Feburary 2013, but since the date doesn't exist, it moves on to the next valid month (which is March). You can use the following work-around: $current = date('n',

php获取前一个小时的时间： $mtime= date("Y-m-d H:i:s", strtotime("-1 hour")); php获取前一天的时间： $mtime= date("Y-m-d H:i:s", strtotime("-1 day")); php获取三天前的时间： $mtime= date("Y-m-d H:i:s", strtotime("-3 day")); php获取前一个月的时间： $mtime= date("Y-m-d H:i:s", strtotime("-1 month")); php获取三个月前的时间： $mtime= date("Y-m-d H:i:s", strtotime("-3 month")); php获取前一年的时间： $mtime= date("Y-m-d H:i:s", strtotime("-1 year")); 来源： https://www.cnblogs.com/pcx105/p/11933345.html

I encountered with this question today on StackOverflow but didn't get answer. My question is echo date('Y-m-d',strtotime('2012-september-09')); // output - 2012-09-01 echo date('Y-m-d',strtotime('09-september-2012')); // output - 2012-09-09 Codepad I am confused that why the first format don't produce correct answer. Any Help? From the manual : if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed . This is not behavior of the date function but of the strtotime . strtotime can handle

若当前时间戳为$timeStamp=1467894352，对应的时间为2016年7月7日20点42分 如何获得本月第一天零点的时间戳？ date('Y-m-01 00:00',$timeStamp); 类似的，可以获得本月任何一天的任何一点时间。或者本年的。或者今日的。或者该小时内的。等等…… +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 如何获得两天后这个时间的时间戳 $timeStr=date('Y-m-d hh:ii',$timeStamp); strtotime("$timeStr + 2day"); 类似的，可以获得两天前（-2day）。两个月前（-2month）。两年前（-2year）。加也行。 +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 如何获得某个时间戳是周几 $week = date("w", strtotime($firstday)); $week的值为0~6 ,表示周日~周六 date()第一个参数还有很多可选值，会在本文最下放一一列出 +++++++++++++++++