string

问题 This seems like it should be pretty trivial, but I am new at Python and want to do it the most Pythonic way. I want to find the index corresponding to the n'th occurrence of a substring within a string. There's got to be something equivalent to what I WANT to do which is mystring.find("substring", 2nd) How can you achieve this in Python? 回答1: Mark's iterative approach would be the usual way, I think. Here's an alternative with string-splitting, which can often be useful for finding-related

问题 I'd like to convert a large JSON object to string using the JSON.stringify , but due to the size of the object I got an error of <--- Last few GCs ---> [20817:0x2cc2830] 295727 ms: Scavenge 1335.8 (1423.9) -> 1335.6 (1427.9) MB, 7.7 / 0.0 ms (average mu = 0.255, current mu = 0.170) allocation failure [20817:0x2cc2830] 295966 ms: Mark-sweep 1339.5 (1427.9) -> 1339.3 (1422.9) MB, 227.1 / 0.0 ms (average mu = 0.272, current mu = 0.291) allocation failure scavenge might not succeed [20817

问题 After I scraped a list of names, I have the following name in R: DAPHN\303\211 DE MEULEMEESTER If I use the function tolower, all the letters are set to lowercase, but not the special characters. What is the best way to achieve this? 回答1: The reason is that your locale is C. Non-ASCII special characters and their letter-case classifications are not recognized under that locale. You should be able to get it to work by switching to a UTF-8 locale: Sys.setlocale(locale='C'); ## [1] "C/C/C/C/C/en

问题 After I scraped a list of names, I have the following name in R: DAPHN\303\211 DE MEULEMEESTER If I use the function tolower, all the letters are set to lowercase, but not the special characters. What is the best way to achieve this? 回答1: The reason is that your locale is C. Non-ASCII special characters and their letter-case classifications are not recognized under that locale. You should be able to get it to work by switching to a UTF-8 locale: Sys.setlocale(locale='C'); ## [1] "C/C/C/C/C/en

问题 After I scraped a list of names, I have the following name in R: DAPHN\303\211 DE MEULEMEESTER If I use the function tolower, all the letters are set to lowercase, but not the special characters. What is the best way to achieve this? 回答1: The reason is that your locale is C. Non-ASCII special characters and their letter-case classifications are not recognized under that locale. You should be able to get it to work by switching to a UTF-8 locale: Sys.setlocale(locale='C'); ## [1] "C/C/C/C/C/en

问题 I have a rather difficult problem and I'm not sure how I can do what is needed. I have two string s, text1 and text2 . I need to create a result that is based on both of these. text2 has separator "|" so that if there are three characters in text1 then there will be two separators etc. I need to create a result that is text2 without the separator and with a the corresponding character from text1 replacing the # . Below I have some examples: text1: 間違う text2: ま|ちが|# result: まちがう text1: 立ち上げる

问题 I have a rather difficult problem and I'm not sure how I can do what is needed. I have two string s, text1 and text2 . I need to create a result that is based on both of these. text2 has separator "|" so that if there are three characters in text1 then there will be two separators etc. I need to create a result that is text2 without the separator and with a the corresponding character from text1 replacing the # . Below I have some examples: text1: 間違う text2: ま|ちが|# result: まちがう text1: 立ち上げる

问题 I am trying to split a string into a string array, there might be number of combinations, I tried: String strExample = "A, B"; //possible option are: 1. A,B 2. A, B 3. A , B 4. A ,B String[] parts; parts = strExample.split("/"); //Split the string but doesnt remove the space in between them so the 2 item in the string array is space and B ( B) parts = strExample.split("/| "); parts = strExample.split(",|\\s+"); Any guidance would be appreciated 回答1: To split with comma enclosed with optional

问题 This question already has an answer here : Swift Regex doesn't work (1 answer) Closed 3 years ago . I'm trying to parse out "@mentions" from a user provided string. The regular expression itself seems to find them, but the range it provides is incorrect when emoji are present. let text = "😂😘🙂 @joe " let tagExpr = try? NSRegularExpression(pattern: "@\\S+") tagExpr?.enumerateMatches(in: text, range: NSRange(location: 0, length: text.characters.count)) { tag, flags, pointer in guard let tag =

问题 I have json file like this and i want convert from json to string using org.simple.json { "header": { "IssuerID": "000141", "AuthenticationID": "e07020c0d040a050a0808099", "AuthenticationDateTime": "20151103093035", "AuthenticationDateTimeGMT": "20151103093035", "Signature":