string

问题 I am going to extract the bbcode with the quotes but to no avail when the actual output is coming. I would like to implement the bbcode parsing module for extracting the quotes as desired output . The number of quotes shall be a recursive method or some else.. INput : Testing [quote]http://www.yourube.com?watch?v=asasdsadsa [url] aisa [/url] [/quote] Testing Desired Output Testing http://www.yourube.com?watch?v=asasdsadsa [url] aisa [/url] aisa Testing Actual Output: http://www.yourube.com

问题 String is a class in java. While declaring and assigning string, it is correct to say String name = "Paul" though to instantiate an object from a java class we do String name = new String(); Taking name as an object, I'm wondering why we can assign a series of characters "Paul" to the object. Under what concept does this one works and how does it? 回答1: That's because implicitly Strings - "..." are treated as objects as well. Under the cover JVM looks for similar "objects" in so called String

问题 I'm looking for a simple method of identifying the last position of a string inside another string ... for instance. If I had: file = C:\Users\User\Desktop\go.py and I wanted to crop this so that file = go.py Normally I would have to run C:\Users\User\Desktop\go.py through a loop + find statement, and Evey time it encountered a \ it would ask ... is the the last \ in the string? ... Once I found the last \ I would then file = file[last\:len(file)] I'm curious to know if there is a faster

问题 I'm looking for a simple method of identifying the last position of a string inside another string ... for instance. If I had: file = C:\Users\User\Desktop\go.py and I wanted to crop this so that file = go.py Normally I would have to run C:\Users\User\Desktop\go.py through a loop + find statement, and Evey time it encountered a \ it would ask ... is the the last \ in the string? ... Once I found the last \ I would then file = file[last\:len(file)] I'm curious to know if there is a faster

问题 This question already has answers here : How do I compare strings in Java? (23 answers) Closed 5 years ago . I ave a code where I want to use != sign. But since I am using String, How do I not equals Sign. Hers is my code. So I want all this statement not to equal to each other so it can print Tie Game. if (Array[0] == Array[currentPlayer] && Array [1] == Array[currentPlayer] && !Array [2] == Array[currentPlayer]) The above code is when everything equals to each other. But I want this

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 8 years ago . I want to get the particular part of String from a complete word. For example: I have the following String. # STRING_VALUES # and a sentence is as follows <p># STRING_VALUE #<br /># CMESSAGE #<br />#

问题 For comparing any strings without considering their case, there are various C library functions such as strcasecmp() , stricmp() and stricmpi() . What is the difference between these? 回答1: There are multiple ways to do many things primarily because the standards process lags behind implementations. People see the need for a function (in this case, case insensitive string comparison) and some compiler writers/library writers implement a function called strcmpi , while another group implements

问题 I know there is strings.Index and strings.LastIndex , but they just find the first and last. Is there any function I can use, where I can specify the start index? Something like the last line in my example. Example: s := "go gopher, go" fmt.Println(strings.Index(s, "go")) // Position 0 fmt.Println(strings.LastIndex(s, "go")) // Postion 11 fmt.Println(strings.Index(s, "go", 1)) // Position 3 - Start looking for "go" begining at index 1 回答1: It's an annoying oversight, you have to create your

问题 I'm trying to tokenize a number of strings using a capital letter as a delimited. I have landed on the following code: token = ([a for a in re.split(r'([A-Z][a-z]*)', "ABCowDog") if a]) print token And I get this, as expected, in return: ['A', 'B', 'Cow', 'Dog'] Now, this is just an example string to make life easier, but in my case I want to go through this list and find individual characters (easy enough with checking len()) and putting the individual letters together, provided they meet a

问题 i have a requirement where a input field which takes strings can have only one of these formats, what is the best way to implement this using javascript or jsf validator: N/A-N-N-N or N/A-N-N-N-N There can be any alphabet in pattern above in place of A. there can be any numeric in pattern above in place of N other than 0. 回答1: First of all, there is no "best" way. There's just the "right" way which depends on the concrete functional requirements. The normal approach to validate in JSF is to