string-matching | 易学教程

Efficient string matching in Apache Spark

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问题 Using an OCR tool I extracted texts from screenshots (about 1-5 sentences each). However, when manually verifying the extracted text, I noticed several errors that occur from time to time. Given the text \"Hello there 😊! I really like Spark ❤️!\", I noticed that: 1) Letters like \"I\", \"!\", and \"l\" get replaced by \"|\". 2) Emojis are not correctly extracted and replaced by other characters or are left out. 3) Blank spaces are removed from time to time. As a result, I might end up with a

A better similarity ranking algorithm for variable length strings

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I'm looking for a string similarity algorithm that yields better results on variable length strings than the ones that are usually suggested (levenshtein distance, soundex, etc). For example, Given string A: "Robert", Then string B: "Amy Robertson" would be a better match than String C: "Richard" Also, preferably, this algorithm should be language agnostic (also works in languages other than English). Simon White of Catalysoft wrote an article about a very clever algorithm that compares adjacent character pairs that works really well for my purposes: http://www.catalysoft.com/articles

How do I check if a string contains a specific word?

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问题 This post is a Community Wiki . Edit existing answers to improve this post. It is not currently accepting new answers. Consider: $a = \'How are you?\'; if ($a contains \'are\') echo \'true\'; Suppose I have the code above, what is the correct way to write the statement if ($a contains \'are\') ? 回答1: You can use the strpos() function which is used to find the occurrence of one string inside another one: $a = 'How are you?'; if (strpos($a, 'are') !== false) { echo 'true'; } Note that the use

How to check whether a string contains a substring in JavaScript?

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问题 This post is a Community Wiki . Edit existing answers to improve this post. It is not currently accepting new answers. Usually I would expect a String.contains() method, but there doesn\'t seem to be one. What is a reasonable way to check for this? 回答1: ECMAScript 6 introduced String.prototype.includes: var string = "foo", substring = "oo"; console.log(string.includes(substring)); includes doesn’t have Internet Explorer support, though. In ECMAScript 5 or older environments, use String