string-matching

Regex substring one mismatch in any location of string

孤人 提交于 2020-01-15 07:08:07
问题 Can someone explain why the code below returns an empty list: >>> import re >>> m = re.findall("(SS){e<=1}", "PSSZ") >>> m [] I am trying to find the total number of occurrences of SS (and incorporating the possibility of up to one mismatch ) within PSSZ . I saw a similar example of code here: Search for string allowing for one mismatch in any location of the string 回答1: You need to remove e<= chars present inside the range quantifier. Range quantifier must be of , {n} . Repeats the previous

Excel MATCH range without specific CELL

拜拜、爱过 提交于 2020-01-14 22:46:07
问题 after a deep search on the internet i gave up. My "simple" question would be: How can I add two ranges in a formula, preferably in MATCH? I want to search a range like A1:A7 + A9:A20 and thus not include A8 in my range. Is this possible? Please help me out 回答1: Natively you can't but you could try to bypass it with either: Exclude a single cell: If you want to exclude a certain cell from a MATCH you can exclude it's certain row number like so: =MATCH(1,(A1:A20="X")*(ROW(A1:A20)<>8),0) Or

Python Fuzzy matching strings in list performance

二次信任 提交于 2020-01-13 20:28:47
问题 I'm checking if there are similar results (fuzzy match) in 4 same dataframe columns, and I have the following code, as an example. When I apply it to the real 40.000 rows x 4 columns dataset, keeps running in eternum. The issue is that the code is too slow. For example, if I limite the dataset to 10 users, it takes 8 minutes to compute, while for 20, 19 minutes. Is there anything I am missing? I do not know why this take that long. I expect to have all results, maximum in 2 hours or less. Any

Python search text file and count occurrences of a specified string

别等时光非礼了梦想. 提交于 2020-01-06 18:33:08
问题 I am attempting to use python to search a text file and count the number of times a user defined word appears. But when I run my code below instead of getting a sum of the number of times that unique word appears in the file, I am getting a count for the number lines within that file contain that word. Example: the word 'bob' exists 56 times in the text file, appearing in 19 of the total 63 lines of text. When I run my code the console prints '19'. I am guessing I need to do something

match two strings and print the missing words in java

心不动则不痛 提交于 2020-01-06 13:54:32
问题 I want to make an application to find differences between two strings. How do I solve this? st = "this is a cat.this is my cat." st1 = "this is cat. this my cat." The output should be "a is" as the missing words. Here is my code @SuppressLint("DefaultLocale") @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); String st="this is a cat. this is my cat."; TextView tv1=(TextView) findViewById(R.id.textView2);

match two strings and print the missing words in java

守給你的承諾、 提交于 2020-01-06 13:54:06
问题 I want to make an application to find differences between two strings. How do I solve this? st = "this is a cat.this is my cat." st1 = "this is cat. this my cat." The output should be "a is" as the missing words. Here is my code @SuppressLint("DefaultLocale") @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); String st="this is a cat. this is my cat."; TextView tv1=(TextView) findViewById(R.id.textView2);

match two strings and print the missing words in java

南笙酒味 提交于 2020-01-06 13:51:52
问题 I want to make an application to find differences between two strings. How do I solve this? st = "this is a cat.this is my cat." st1 = "this is cat. this my cat." The output should be "a is" as the missing words. Here is my code @SuppressLint("DefaultLocale") @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); String st="this is a cat. this is my cat."; TextView tv1=(TextView) findViewById(R.id.textView2);

Python pandas, build a dataframe from 2 dataframes with these properties [duplicate]

空扰寡人 提交于 2020-01-06 05:06:39
问题 This question already has answers here : Pandas left outer join multiple dataframes on multiple columns (2 answers) Closed 2 years ago . i'm in need to solve this issue. I need to build a whole dataframe from two dataframes, but include only certain info from a second Dataframe if required. EXAMPLE: DF1: MATERIAL_N° Description DATE DUE 0 123123300 Lightbulb X 01/05/2018 1 220466 Lightbulb Y 04/04/2018 2 220000 Lightbulb Z 07/07/2018 3 1241241 Lightbulb A 02/01/2019 4 7775447 Lightbulb B 02

how to generate a set of similar strings in python

ぃ、小莉子 提交于 2020-01-04 13:35:55
问题 I am wondering how to generate a set of similar strings based on Levenshtein distance (string edit distance). Ideally, I like to pass in, a source string (i.e. a string which is used to generate other strings that are similar to it), the number of strings need to be generated and a threshold as parameters, i.e. similarities among the strings in the generated set should be greater than the threshold. I am wondering what Python package(s) should I use to achieve that? Or any idea how to

Possible bug in VB.NET 'Like' operator?

大兔子大兔子 提交于 2020-01-01 08:36:06
问题 Why is it that the following evaluates as True ? Dim result = "b" Like "*a*b" Thanks. EDIT: To generalize this a bit, the following returns True : "String1" Like "*AnyText1*AnyText2*AnyText???******????*String1" VBA works correctly, returning False . PowerShell works correctly, returning False : PS C:\Users\XXX> "b" -Like "*a*b" False EDIT2: The link to the bug report: https://connect.microsoft.com/VisualStudio/feedback/details/748415/a-bug-in-net-like-operator 回答1: I decided, for fun, to