string-concatenation

How can I use += operator in PHP for String [duplicate]

杀马特。学长 韩版系。学妹 提交于 2019-12-02 05:01:37
问题 This question already has answers here : How to combine two strings together in PHP? (17 answers) Closed 5 years ago . I am new to PHP. I need to know how to use += operator for string in PHP. Below is Java example: String str = ""; str += "some value"; str += "some more values"; the above example concatenates and assign all values to str object. Can somebody tell me how to achieve this in PHP? 回答1: You are searching for .=: $str = ""; $str .= "some value"; 回答2: $str .= "some value"; $str .=

What does ## mean in the #define directive in the code here

杀马特。学长 韩版系。学妹 提交于 2019-12-02 02:03:16
问题 Please tell me the answer with explanation: #define f(g,h) g##h main(){ printf("%d",f(100,10)); } 回答1: ## is used to concatenate whatever is before the ## with whatever is after it. It is used for concatenation. You can check the reference for details A ## operator between any two successive identifiers in the replacement-list runs parameter replacement on the two identifiers (which are not macro-expanded first) and then concatenates the result. This operation is called "concatenation" or

What does ## mean in the #define directive in the code here

笑着哭i 提交于 2019-12-02 00:48:39
Please tell me the answer with explanation: #define f(g,h) g##h main(){ printf("%d",f(100,10)); } ## is used to concatenate whatever is before the ## with whatever is after it. It is used for concatenation. You can check the reference for details A ## operator between any two successive identifiers in the replacement-list runs parameter replacement on the two identifiers (which are not macro-expanded first) and then concatenates the result. This operation is called "concatenation" or "token pasting". 来源: https://stackoverflow.com/questions/29577775/what-does-mean-in-the-define-directive-in-the

Where is the new Object of String created when we concat using + operator

喜夏-厌秋 提交于 2019-12-01 22:58:52
I know this might be quite basic and probably pretty straight forward but i cannot clearly understand what will happen in this situation, so, here it goes. In the following code: String str1 = "Hello"; String str2 = "World"; String str3 = new String("HelloWorld"); String str4 = str1 + str2; i know that str1 and str2 will create an object "Hello" and "World" respectively inside the String Constant Pool . While for str3 a new object is created outside the String Constant Pool which is pointing to "HelloWorld" that is created inside String Constant Pool . My question is, what will happen if i

Difference between c++ string append and operator +=

不羁的心 提交于 2019-12-01 17:09:22
Is there any noticeable difference between the two lines? My coworker says that using += is "faster" but I don't see why they should be any different: string s1 = "hello"; string s2 = " world"; // Option 1 s1 += s2; // Option 2 s1.append(s2); To clarify, I am not asking about the usage differences between the two functions - I am aware that append() can be used for a wider variety of uses and that operator += is somewhat more specialized. What I care about is how this particular example gets treated. According to the standard concerning string::op+= / online c++ standard draft , I wouldn't

Concatenating strings in VBA

喜欢而已 提交于 2019-12-01 16:58:42
I'm maintaining an application written in Microsoft Access with VBA. I'm glancing over my code and have just noticed I have subconsciously been concatenating strings together with the plus (+) symbol instead of the ampersand. It's been a few years since I've coded in VB6. Could this cause any issues? Everything seems fine and it will only take a few minutes to fix, I'm just curious as to whether I'm technically doing anything wrong. The ampersand is explicitly a string operation, while the plus is overloaded: Dim num1 As Integer num1 = RandomNumberBetween(1, 9) Dim num2 As Integer num2 =

Concatenation of two strings does not work [duplicate]

空扰寡人 提交于 2019-12-01 16:56:38
问题 This question already has an answer here : Apparently not able to append a string to another (1 answer) Closed 2 years ago . I have the following code, but it doesn't work: CHARACTER*260 xx, yy, zz xx = 'A' yy = 'B' zz = xx // yy When I debug my code in Visual Studio the variable xx contains 'A' variable yy contains 'B' variable zz contains 'A' Why doesn't zz contain 'AB'? 回答1: You defined xx to be 260 characters long. Assigning a shorter character literal will result in a padding with blanks

Read content from text file formed in Windows in Linux bash [duplicate]

坚强是说给别人听的谎言 提交于 2019-12-01 16:51:29
This question already has an answer here: How to concatenate string variables in Bash 30 answers I am trying to download files from a database using wget and url. E.g. wget " http://www.rcsb.org/pdb/files/1BXS.pdb " So format of the url is as such: http://www.rcsb.org/pdb/files/ ($idnumber).pdb" But I have many files to download; so I wrote a bash script that reads id_numbers from a text file, forms url string and downloads by wget. !/bin/bash while read line do url="http://www.rcsb.org/pdb/files/$line.pdb" echo -e $url wget $url done < id_numbers.txt However, url string is formed as .pdb:/

Concatenation of two strings does not work [duplicate]

感情迁移 提交于 2019-12-01 16:34:17
This question already has an answer here: Apparently not able to append a string to another 1 answer I have the following code, but it doesn't work: CHARACTER*260 xx, yy, zz xx = 'A' yy = 'B' zz = xx // yy When I debug my code in Visual Studio the variable xx contains 'A' variable yy contains 'B' variable zz contains 'A' Why doesn't zz contain 'AB'? Alexander Vogt You defined xx to be 260 characters long. Assigning a shorter character literal will result in a padding with blanks. Thus, xx contains A and 259 blanks. yy contains B and 259 blanks. So the concatenated string would be 'A' + 259

primitive-boolean To String concatenation/conversion

こ雲淡風輕ζ 提交于 2019-12-01 15:25:01
问题 how does this work? I can't seem to find an answer. boolean bool=true; System.out.println("the value of bool is : " + true); //or System.out.println("the value of bool is : " + bool); What are the things that are going on behind the scene? how does the boolean gets casted to the String as a boolean cannot be implicitly type casted? Is Autoboxing/Unboxing involved? Are methods like toString() or String.valueOf() are involved in some way? 回答1: The exact rules are spelled out in the Java