string-comparison

is StringComparison.Ordinal the same as InvariantCulture for testing equality?

倖福魔咒の 提交于 2019-11-30 08:13:34
From their brief summary descriptions, it sounds like the string comparison rules StringComparison.Ordinal and StringComparison.InvariantCulture are meant to differ in how they do sorting of strings. Is that all ? i.e., does that mean we can use either string comparison rule when doing an equality comparison? string.Equals(a, b, StringComparison....) And for extra credit: does it make a difference to the answer if we compare OrdinalIgnoreCase and InvariantCultureIgnoreCase ? How? Please provide supporting argument and/or references. It does matter, for example - there is a thing called

How to do advanced string comparison in Ruby?

狂风中的少年 提交于 2019-11-30 07:37:24
I am trying to compare 2 paragraphs of strings the output of which has to be the percentage of similarity. I have tried doing this using the diff method and some Natural Language Processing tools Is there a better way of doing this in ruby? You may want to try the Levenshtein string distance algorithm for this. http://rubygems.org/gems/text has an implementation of this along with other helpful string comparison utils. Paul Whelan See my similar Question here what I needed but did not know what it was called was a Levenshtein distance algorithm 来源: https://stackoverflow.com/questions/4761793

Why is “ss” equal to the German sharp-s character 'ß'?

不羁的心 提交于 2019-11-30 06:05:49
Coming from this question I'm wondering why ä and ae are different(which makes sense) but ß and ss are treated as equal. I haven't found an answer on SO even if this question seems to be related and even mentions "that ß will compare equal to SS in Germany, or similar" but not why. The only resource on MSDN I found was this: How to: Compare Strings Here is mentioned following but also lacks the why : // "They dance in the street." // Linguistically (in Windows), "ss" is equal to // the German essetz: 'ß' character in both en-US and de-DE cultures. ..... So why does this evaluate to true , both

How to compare strings with case insensitive and accent insensitive

為{幸葍}努か 提交于 2019-11-30 03:58:14
问题 How to compare strings with case insensitive and accent insensitive Alright this is done easily at SQL server However I would like to do the same at C# .NET 4.5.1. How can I do that with most proper way? I mean these 3 strings should return equal when compared http://www.buroteknik.com/metylan-c387c4b0ft-tarafli-bant-12cm-x25mt_154202.html http://www.buroteknik.com/METYLAN-C387C4B0FT-TARAFLI-BANT-12cm-x25mt_154202.html http://www.buroteknik.com/METYLAN-C387C4B0FT-TARAFLı-BANT-12cm-x25mt

string1 >= string2 not implemented in Linq to SQL, any workarround?

女生的网名这么多〃 提交于 2019-11-30 03:25:18
问题 anyones knows how to do this? Edit: I am trying to do >=. I correct the Title. 回答1: string1 >= string2 is not supported in C# Linq To Sql. The String class does not override the >= operator at all. It only overrides the != and == operators. You can verify this by trying to compile the following method public static void Example() { int val = "foo" >= "bar"; } If you want to compare to Strings in LinqToSql you should be able to use the static String.Compare(string,string) method. 回答2: If you

Check if one string is a prefix of another

拜拜、爱过 提交于 2019-11-29 22:50:32
I have two strings which I'd like to compare: String and String: . Is there a library function that would return true when passed these two strings, but false for say String and OtherString ? To be precise, I want to know whether one string is a prefix of another. Use std::mismatch . Pass in the shorter string as the first iterator range and the longer as the second iterator range. The return is a pair of iterators, the first is the iterator in the first range and the second, in the second rage. If the first is end of the first range, then you know the the short string is the prefix of the

Best machine learning technique for matching product strings

人走茶凉 提交于 2019-11-29 20:26:27
Here's a puzzle... I have two databases of the same 50000+ electronic products and I want to match products in one database to those in the other. However, the product names are not always identical. I've tried using the Levenshtein distance for measuring the string similarity however this hasn't worked. For example, -LG 42CS560 42-Inch 1080p 60Hz LCD HDTV -LG 42 Inch 1080p LCD HDTV These items are the same, yet their product names vary quite a lot. On the other hand... -LG 42 Inch 1080p LCD HDTV -LG 50 Inch 1080p LCD HDTV These are different products with very similar product names. How

How to compare version numbers in C++ [duplicate]

假装没事ソ 提交于 2019-11-29 14:37:50
This question already has an answer here: Compare versions as strings 4 answers Our professor want us to write a program to compare two version numbers, like 0.1 < 0.2 or 1 < 1.1. Also there are some trick ones like .0.4 < .1. So, my idea is first judge if the number start as a dot, if it does, I add a 0 to it. After that I remove other dots except the first one. Then I convert string to number and compare them. Here's what I do in the first step. string numb1,numb2; if(numb1[0]=='.') { numb1 ="0"+ numb1; } I do the same thing to the second number. And now I need help to show me how to remove

Find a common string within a list of strings

点点圈 提交于 2019-11-29 13:43:12
I'm very close on this. I got a question posed to me yesterday by a developer if I could have a look at this. I feel close, but I think some people here would appreciate the challenge too and I am lost. If I have a List<string> which has the following members: Today Monday Tuesday Wednesday I want to get a return string day because this is the largest common string in the List<string> . This should be done irrespective of position and string length, just want to find the largest length common string in a host of strings. My attempt failed a bit miserably, I selected: Monday - Tuesday Monday -

equal() and equalsIgnoreCase() return false for equal strings

与世无争的帅哥 提交于 2019-11-29 13:14:00
I'm working with eclipse IDE (Version: 3.4.2) on a mac and I have met the following issue. When comparing between strings using equal() or equalsIgnoreCase() methods I receive false even when the string are equal. For example, the code below consider the following condition as false, even when values[0] = "debug_mode" if (values[0].equalsIgnoreCase("debug_mode")) debug_mode = true; which is part of the following loop: String value = dis.readLine(); String values[] = value.trim().split("="); if (values.length >= 2) { Config.prnt_dbg_msg(values[0] + "\t" + values[1]); if (values[0]