street-address | 易学教程

Regex for splitting a german address into its parts

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Good evening, I'm trying to splitting the parts of a german address string into its parts via Java. Does anyone know a regex or a library to do this? To split it like the following: Name der Straße 25a 88489 Teststadt to Name der Straße|25a|88489|Teststadt or Teststr. 3 88489 Beispielort (Großer Kreis) to Teststr.|3|88489|Beispielort (Großer Kreis) It would be perfect if the system / regex would still work if parts like the zip code or the city are missing. Is there any regex or library out there with which I could archive this? EDIT: Rule for german addresses: Street: Characters, numbers and

What does each Android's location.Address method return?

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I am trying to figure out exactly how to get address component with the Android SDK with the class android.location.Address. Some of the methods are very straightforward, other are easily understood with the examples in the documentation , but some of them are completely unclear to me. Either because there's no example in the documentation or because the example refers to the US, which does not have the same political organization as other countries may have. I've been looking for their meaning, but most of tutorials on the web simply use the method getAddressLine(int index) to teach and then

Compare 5000 strings with PHP Levenshtein

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问题 I have 5000, sometimes more, street address strings in an array. I'd like to compare them all with levenshtein to find similar matches. How can I do this without looping through all 5000 and comparing them directly with every other 4999? Edit: I am also interested in alternate methods if anyone has suggestions. The overall goal is to find similar entries (and eliminate duplicates) based on user-submitted street addresses. 回答1: I think a better way to group similar addresses would be to:

Place Markers from Name, Address and Post Code

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问题 In my domain model, for the entities in question, I have the: Name of the place (e.g. Waterstones Wakefield) The Street Addresses (e.g. 61-62 Bishopgate Walk) And the Post Code (e.g. WF1 1YB) From the above three pieces of information, how can I get a Marker placed on the Map? I am using Google Maps API 3. Thanks 回答1: Try this example: HERE THE ORIGINAL HTML <body onload="initialize()"> <div> <input id="address" type="text" value="Sydney, NSW"> <input type="button" value="Geocode" onclick=

Is there a library for parsing US addresses?

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问题 I have a list of US addresses I need to break into city,state, zip code,state etc. example address : "16100 Sand Canyon Avenue, Suite 380 Irvine, CA 92618" Does anyone know of a library or a free API to do this? Google/Yahoo geocoder is forbidden to use by the TOS for commercial projects.. It would be awesome to find a python library that preforms this. 回答1: Pyparsing has a bunch of functionality for parsing street addresses, check out an example for this here: http://pyparsing.wikispaces.com

Address Match Key Algorithm

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I have a list of addresses in two separate tables that are slightly off that I need to be able to match. For example, the same address can be entered in multiple ways: 110 Test St 110 Test St. 110 Test Street Although simple, you can imagine the situation in more complex scenerios. I am trying to develop a simple algorithm that will be able to match the above addresses as a key. For example. the key might be "11TEST" - first two of 110, first two of Test and first two of street variant. A full match key would also include first 5 of the zipcode as well so in the above example, the full key

find duplicate addresses in database, stop users entering them early?

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How do I find duplicate addresses in a database, or better stop people already when filling in the form ? I guess the earlier the better? Is there any good way of abstracting street, postal code etc so that typos and simple attempts to get 2 registrations can be detected? like: Quellenstrasse 66/11 Quellenstr. 66a-11 I'm talking German addresses... Thanks! Johannes: @PConroy: This was my initial thougt also. the interesting part on this is to find good transformation rules for the different parts of the address! Any good suggestions? When we were working on this type of project before, our

General Address Parser for Freeform Text

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We have a program that displays map data (think Google Maps, but with much more interactivity and custom layers for our clients). We allow navigation via a set of combo boxes that prefill certain fields with a bunch of data (ie: Country: Canada, the Province field is filled in. Select Ontario, and a list of Counties/Regions is filled in. Select a county/region, and a city is filled in, etc...). While this guarantees accurate addresses, it's a pain for the users if they don't know where a street address or a city are located (ie, which county/region is kitchener in?). So we are looking at

Place Markers from Name, Address and Post Code

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In my domain model, for the entities in question, I have the: Name of the place (e.g. Waterstones Wakefield) The Street Addresses (e.g. 61-62 Bishopgate Walk) And the Post Code (e.g. WF1 1YB) From the above three pieces of information, how can I get a Marker placed on the Map? I am using Google Maps API 3. Thanks grigno Try this example: HERE THE ORIGINAL HTML <body onload="initialize()"> <div> <input id="address" type="text" value="Sydney, NSW"> <input type="button" value="Geocode" onclick="codeAddress()"> </div> <div id="map-canvas" style="height:90%;top:30px"></div> </body> JS <script> var

Is there a library for parsing US addresses?

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I have a list of US addresses I need to break into city,state, zip code,state etc. example address : "16100 Sand Canyon Avenue, Suite 380 Irvine, CA 92618" Does anyone know of a library or a free API to do this? Google/Yahoo geocoder is forbidden to use by the TOS for commercial projects.. It would be awesome to find a python library that preforms this. Karl Barker Pyparsing has a bunch of functionality for parsing street addresses, check out an example for this here: http://pyparsing.wikispaces.com/file/view/streetAddressParser.py Tyler Hayes Quite a few of these answers are a few years old