stderr

unable to capture stderr while performing openssh to a variable- perl

Deadly 提交于 2019-12-07 23:25:14
问题 I want to capture the standard error displayed on host machine after (ssh->capture) to a variable. for example when i try: use Net::OpenSSH; my $ssh = Net::OpenSSH->new($host); my $out=$ssh->capture("cd /home/geek"); $ssh->error and die "remote cd command failed: " . $ssh->error; out put is: child exited with code 1 at ./change_dir.pl line 32 i am not able to see what is the error. i get no such file or directory on the terminal. I want to capture the same "no such file or director" in $out.

PowerShell - Capturing STDERR Output for Git Commands

淺唱寂寞╮ 提交于 2019-12-07 21:03:52
问题 Problem I am trying to capture the STDERR outputs into a log file; however, I have been encountering some serious inconsistent issues that are making my task harder. First off, I have my ErrorActionPreference to 'Stop', which is probably part of the problems I am enduring. Second, I have tried two variants for EACH git command in my code displayed below: Variant 01 & git add $path2File 2>&1 | Out-File "$LogPath\$tmpLogName" -Append & git commit -m "Some logical update message" 2>&1 | Out-File

PBSPro qsub output error file directed to path with jobid in name

房东的猫 提交于 2019-12-07 19:15:29
I'm using PBSPro and am trying to use qsub command line to submit a job but can't seem to get the output and error files to be named how I want them. Currently using: qsub -N ${subjobname_short} \ -o ${path}.o{$PBS_JOBID} -e ${path}.e${PBS_JOBID} ... submission_script.sc Where $path=fulljobname (i.e. more than 15 characters) I'm aware that $PBS_JOBID won't be set until after the job is submitted... Any ideas? Thanks The solution I came up with was following the qsub command with a qalter command like so: jobid=$(qsub -N ${subjobname_short} submission_script.sc) qalter -o ${path}.o{$jobid} -e $

Problem redirecting stdout in Ruby script

感情迁移 提交于 2019-12-07 18:32:32
问题 I have the following test Ruby script: require 'tempfile' tempfile = Tempfile.new 'test' $stderr.reopen tempfile $stdout.reopen tempfile puts 'test stdout' warn 'test stderr' `mail -s 'test' my@email.com < #{tempfile.path}` tempfile.close tempfile.unlink $stderr.reopen STDERR $stdout.reopen STDOUT The email that I get has the contents: test stderr Why is stderr redirecting properly but not stdout? Edit: In response to a comment I added a $stdout.flush after the puts line and it printed

difference between communicate() and .stdin.write, .stdout.read or .stderr.read - python

谁说我不能喝 提交于 2019-12-07 17:49:12
问题 I wan to create a pipe between 3 commands: cat = subprocess.Popen("cat /etc/passwd", stdout=subprocess.PIPE) grep = subprocess.Popen("grep '<usernamr>'", stdin=cat.stdout, stdout=subprocess.PIPE) cut = subprocess.Popen("cut -f 3 -d ':'", stdin=grep.stdout, stdout=subprocess.PIPE) for line in cut.stdout: # process each line here But python documentation says: Use communicate() rather than .stdin.write , .stdout.read or .stderr.read to avoid deadlocks due to any of the other OS pipe buffers

Linux 执行命令或脚本的屏幕输出(正常输出、警告、错误等信息)重定向输出到文件

三世轮回 提交于 2019-12-07 17:30:32
系统默认的stdin,stdout,stderr,都是屏幕,所以,当你执行命令,比如make,后,所输出的信息,都是可以在屏幕上看到的 。 所以,想要将对应信息输出到某个文件中,就用对应的数字加上重定向符号'>',实现将这些信息,重新定向到对应的文件中,即可。 用法示例: 1.想要把make输出的全部信息,输出到某个文件中,最常见的办法就是: make xxx > build_output.txt 此时默认情况是没有改变2=stderr的输出方式,还是屏幕,所以,如果有错误信息,还是可以在屏幕上看到的。 2.只需要把make输出中的错误(及警告)信息输出到文件中ing,可以用: make xxx 2> build_output.txt 相应地,由于1=stdout没有变,还是屏幕,所以,那些命令执行时候输出的正常信息,还是会输出到屏幕上,你还是可以在屏幕上看到的。 3.只需要把make输出中的正常(非错误,非警告)的信息输出到文件中,可以用: make xxx 1> build_output.txt 相应地,由于2=stderr没有变,还是屏幕,所以,那些命令执行时候输出的错误信息,还是会输出到屏幕上,你还是可以在屏幕上看到的。 4.想要把正常输出信息和错误信息输出到分别的文件中,可以用: make xxx 1> build_output_normal.txt 2>build

Controlling stderr and stdout output in WildFly

試著忘記壹切 提交于 2019-12-07 09:59:34
问题 In my application I got used to the following debug output: normally it prints a few lines per request to stderr, but logs a lot of information (via log4j) to a file. Typically, most important thing for me is the stderr output (that's why I want it concise), but when something doesn't work as expected, I can investigate the log, which can easily be thousands line per request. Now that I'm migrating the application to WildFly, I found that the server pipes all stderr output through its logging

Redirecting stdout & stderr from background process

↘锁芯ラ 提交于 2019-12-07 07:41:31
问题 I have a script called foo that runs the program a.exe and sends the timing statistics to a file, time.log #!/bin/bash date 1>> time.log (time ./a.exe) 2>> time.log This works if I run the script in the background of my terminal and keep my shell open until a.exe finishes, but if I run the script in the background and exit my terminal (a.exe takes a long time to run) foo & exit when I come back, a.exe has executed but the time statistics do not appear in my log file. Does anyone know why this

Determining whether STDERR is going to terminal

不羁的心 提交于 2019-12-07 06:14:03
问题 I have a suite of Java programs which are used as command-line tools on our Linux servers. Most of them use a class that prints a progress bar on STDERR, similar to Perl's Term::ProgressBar . I'd like to have the progress bar shown whenever STDERR is going to the terminal and automatically disable itself when STDERR is redirected so that there aren't all sorts of progress bar pieces in the redirected data. Checking System.console() == null was my first thought, but redirecting STDOUT is

Delphi - Capture stdout and stderr output from statically linked MSVC++ compiled DLL

落爺英雄遲暮 提交于 2019-12-07 05:18:57
问题 I have been trying to capture stdout and stderr output from a DLL compiled in MSVC++ that my Delphi app statically links to, but so far have been unsuccessful. procedure Test; var fs: TFileStream; begin fs := TFileStream.Create('C:\temp\output.log', fmCreate or fmShareDenyWrite); SetStdHandle(STD_OUTPUT_HANDLE, fs.Handle); SetStdHandle(STD_ERROR_HANDLE, fs.Handle); dllFunc(0); // Writes to stdout in MSVC++ console app, but not here // fs.Length is always zero fs.Free; end; Thought I was on