sqlite

SQLite starting rowid of 0

℡╲_俬逩灬. 提交于 2020-12-13 10:35:37
问题 I'm trying to set up a SQLite table where the rowid starts from 0 instead of the default 1. The end goal is to be able to run the first INSERT statement and have it insert to rowid 0. Explicitly setting rowid to 0 for that first INSERT is not an option. I've tried a few things related to AUTOINCREMENT but am not having any luck getting this to work cleanly. The only successful way I've found is to insert a row with rowid of -1 and then delete it later. This works but it's messy and I'd like

Yii2设计模式——工厂方法模式

心已入冬 提交于 2020-12-13 04:58:43
应用举例 yii\db\Schema抽象类中: //获取数据表元数据 public function getTableSchema($name, $refresh = false) { if (array_key_exists($name, $this->_tables) && !$refresh) { return $this->_tables[$name]; } $db = $this->db; $realName = $this->getRawTableName($name); if ($db->enableSchemaCache && !in_array($name, $db->schemaCacheExclude, true)) { /* @var $cache Cache */ $cache = is_string($db->schemaCache) ? Yii::$app->get($db->schemaCache, false) : $db->schemaCache; if ($cache instanceof Cache) { $key = $this->getCacheKey($name); if ($refresh || ($table = $cache->get($key)) === false) { //通过工厂方法loadTableSchema(

Delete duplicate rows from SELECT query?

非 Y 不嫁゛ 提交于 2020-12-13 03:50:25
问题 I'm working with SQLite and currently attempting to delete certain duplicate rows from a certain user (with ID 12345). I've managed to identify all of the rows I wish to delete, but I'm now unsure how to go about deleting these rows. This is my SELECT query: SELECT t.* from (select t.*, count(*) over (partition by code, version) as cnt from t) t where cnt >= 2 and userID = "12345"; How would I go about deleting the rows matching this result? Can I use the query above in some way to identify

Delete duplicate rows from SELECT query?

扶醉桌前 提交于 2020-12-13 03:50:20
问题 I'm working with SQLite and currently attempting to delete certain duplicate rows from a certain user (with ID 12345). I've managed to identify all of the rows I wish to delete, but I'm now unsure how to go about deleting these rows. This is my SELECT query: SELECT t.* from (select t.*, count(*) over (partition by code, version) as cnt from t) t where cnt >= 2 and userID = "12345"; How would I go about deleting the rows matching this result? Can I use the query above in some way to identify

Delete duplicate rows from SELECT query?

懵懂的女人 提交于 2020-12-13 03:50:05
问题 I'm working with SQLite and currently attempting to delete certain duplicate rows from a certain user (with ID 12345). I've managed to identify all of the rows I wish to delete, but I'm now unsure how to go about deleting these rows. This is my SELECT query: SELECT t.* from (select t.*, count(*) over (partition by code, version) as cnt from t) t where cnt >= 2 and userID = "12345"; How would I go about deleting the rows matching this result? Can I use the query above in some way to identify

代码生成工具更新--快速生成Winform框架的界面项目

泪湿孤枕 提交于 2020-12-13 02:57:24
在之前版本的代码生成工具Database2Sharp中,由于代码生成都是考虑Winform和Web通用的目的,因此Winform界面或者Web界面都是单独生成的,在工具中生成相应的界面后,复制到项目里面去使用即可。由于我们Winform的界面是模块化的方式独立开发,因此对某些表来说,我们可以独立开发模块,那么它的Winform窗体界面也应该是在独立的项目上,开发完毕后,我们在主体框架里面通过菜单动态配置即可加入到系统中使用的。 1、框架插件化回顾 在Winform开发框架的程序中,实现基于插件化的应用,如下所示。 通过在权限系统中的预先的配置,独立模块的窗体可以进行动态加载解析,就能实现插件模块的热插拔功能了。实际插件化框架的菜单配置界面效果如下所示。 下图是菜单管理里面的 “Winform窗体类型” 信息的具体内容。 通过动态的配置,可以实现模块的独立开发,动态整合的插件化特性,非常适合我们企业的分工开发,从而提高开发效率。 2、快速生成Winform框架的界面项目 前面我们介绍了,通过模块化的独立来发,动态整合,可以提高开发效率。 其实就是我们对大型项目的横向切割,把大型项目分为各个独立的模块,给不同的开发人员或者团队进行开发,可以极大提高效率,也减少对某个人的过度依赖,也同时可以极大提高开发效率。 在实际使用中

Jetpack系列:Paging组件帮你解决分页加载实现的痛苦

China☆狼群 提交于 2020-12-12 20:37:37
相信很多小伙伴们在项目实战中,经常会用到界面的<b> 分页显示 、 加载更多 </b>等功能。需要针对具体功能做针对性开发和调试,耗时耗力。 Paging组件的使用将这部分的工作简化,从而让开发者更专注于业务的具体实现。下面我们一起来学习下Paging组件的使用方法。 <hr> 首先来看下使用Paging组件实现的分页加载和刷新效果: <center> ![](https://img2018.cnblogs.com/blog/1820853/201910/1820853-20191010103258092-718449477.gif) </center> <br> <center><font size='1' color='orange'>数据库读取分页加载</font></center> <br> <br> <center>![](https://img2018.cnblogs.com/blog/1820853/201910/1820853-20191010103309867-715023857.gif)</center> <br> <center><font size='1' color='orange'>网络端分页请求数据</font></center> <br> 下面我们针对这两个使用Paging组件的例子进行分析。 数据库读取分页加载示例中,数据一次性获取完成

Can't put rows into array using sqlite3 on Node.js

我与影子孤独终老i 提交于 2020-12-12 18:18:58
问题 I have a code in Node.js that selects everything from a SQLite Database and print every row and it works, here's the code: var sqlite3=require('sqlite3').verbose(); var db=new sqlite3.Database('./database.db',(err)=>{ if(err){ return console.error(err.message); } console.log('Connected...'); }); db.all('SELECT * FROM langs ORDER BY name',[],(err,rows)=>{ if(err){ return console.error(err.message); } rows.forEach((row)=>{ console.log(row.name); }); }); db.close((err) => { if (err) { return

Can't put rows into array using sqlite3 on Node.js

夙愿已清 提交于 2020-12-12 18:16:27
问题 I have a code in Node.js that selects everything from a SQLite Database and print every row and it works, here's the code: var sqlite3=require('sqlite3').verbose(); var db=new sqlite3.Database('./database.db',(err)=>{ if(err){ return console.error(err.message); } console.log('Connected...'); }); db.all('SELECT * FROM langs ORDER BY name',[],(err,rows)=>{ if(err){ return console.error(err.message); } rows.forEach((row)=>{ console.log(row.name); }); }); db.close((err) => { if (err) { return

Python学生信息管理系统(数据库版)

旧街凉风 提交于 2020-12-12 13:26:55
该程序主要用到sqlite3 #数据库sqlite import sqlite3 #存放学生信息 #student = list() #展示菜单 def showMenu ( ) : print ( "1.增加学生信息" ) print ( "2.删除学生信息" ) print ( "3.修改学生信息" ) print ( "4.显示学生信息" ) print ( "0.退出系统" ) select = eval ( input ( "操作:" ) ) return select #添加学生信息 def addStudent ( ) : print ( "-----增加学生信息-----" ) name = input ( "姓名:" ) sex = input ( "性别:" ) age = input ( "年龄:" ) phone = input ( "电话:" ) conn = sqlite3 . connect ( "student.db" ) cur = conn . cursor ( ) cur . execute ( "insert into info (id,name,sex,age,phone)values (null,?,?,?,?)" , ( name , sex , age , phone ) ) conn . commit ( ) cur . close