sqlite

OperationalError: no such table

由 守給你的承諾、 提交于 2020-02-03 08:10:44
问题 So I was working on my app and added a slugfield to my models. Then as normal went ahead to makemigrations , and a massive red wall of errors appeared. Traceback (most recent call last): File "C:\Users\Andreas\ReaderProject\lib\site-packages\django\db\backends\utils.py", line 64, in execute return self.cursor.execute(sql, params) File "C:\Users\Andreas\ReaderProject\lib\site-packages\django\db\backends\sqlite3\base.py", line 337, in execute return Database.Cursor.execute(self, query, params)

How to open sqlite database when app runs in background in ios

由 依然范特西╮ 提交于 2020-02-03 05:49:33
问题 My application captures location data in background and saves in sqlite database. It works well when Device is not locked, but when device is locked I am not able to access sqlite database. It always gives me error code as SQLITE_AUTH(error code:23). I have tried below options: Disable the Data Protection from Capabilities.(Does not work) As per Failed to create SQLite3 database with file protection in iOS, I tried the below code : sqlite3_open_v2([dbPath UTF8String], &myDatabase, SQLITE_OPEN

SQLite进阶-18.事务

由 孤人 提交于 2020-02-03 04:35:24
目录 SQLite事务 事务的属性 事务控制 BEGIN TRANSACTION命令 COMMIT命令 ROLLBACK命令 SQLite事务 事务(Transaction) 是一个对数据库执行工作单元。事务是以逻辑顺序完成的工作单元或序列，可以是由用户手动操作完成，也可以是由某种数据库程序自动完成。 事务是指一个或者多个改变数据库的扩展。例如：如果你正在创建一个记录或者更新一个记录或者从表中删除一个记录，那么你正在该表上执行事务。重要的是要控制事务以确保数据的完整性和处理数据库错误。 实际上，你可以把许多的SQLite查询联合成一组，把所有这些放在一起作为事务的一部分进行执行。 事务的属性 事务(Transaction)具有以下四个标准属性，通常根据首字母缩写为ACID： 原子性(Atomicity) : 确保工作单位内的所有操作都成功完成，否则，事务会在出现故障时终止，之前的操作也会回滚到以前的状态。 一致性(Consistency) : 确保数据库在成功提交的事务上正确的改变状态。 隔离性(Isolation) : 使事务操作相互独立和透明。 持久性(Durability) : 确保已提交事务的结果或效果在系统发生故障的情况下仍然存在。 事务控制 使用下面的命令来控制事务: BEGIN TRANSACTION: 开始事务处理。 COMMIT: 保持更改，或者可以使用END

cannot open SQLite datafile file [.db]

由 梦想的初衷 提交于 2020-02-02 16:02:48
问题 So I'm using SQLite, and I created my test.db For some reason, I can't open this database. Not with Microsoft Excel nor notepad. I tried googling it, but there were way too many results of more advanced matters. 回答1: Your problem is that the sqlite datatype is not a user-readable format. It is compressed and optimised for storing the database, and thus can only be opened by sqlite, or something that uses sqlite. For editing, I'd suggest something like SQLite Browser: http://sourceforge.net

How do I send the data I have in my sqlite database to the server with HTTP and JSON

由 二次信任 提交于 2020-02-02 15:59:38
问题 I'm storing id,lat,lng, and timestamp in sqlite and now need to send it in an JSON object to the server. Here's where I'm inserting the data. NSString *insertStatement = [NSString stringWithFormat:@"INSERT INTO location (latitude, longitude, timeStamp) VALUES (%g, %g, %@)",newLocation.coordinate.latitude, newLocation.coordinate.longitude, newLocation.timestamp]; char *error; if ( sqlite3_exec(databasehandle, [insertStatement UTF8String], NULL, NULL, &error) == SQLITE_OK) { NSLog(@"Location

How do I send the data I have in my sqlite database to the server with HTTP and JSON

由 坚强是说给别人听的谎言 提交于 2020-02-02 15:57:46
问题 I'm storing id,lat,lng, and timestamp in sqlite and now need to send it in an JSON object to the server. Here's where I'm inserting the data. NSString *insertStatement = [NSString stringWithFormat:@"INSERT INTO location (latitude, longitude, timeStamp) VALUES (%g, %g, %@)",newLocation.coordinate.latitude, newLocation.coordinate.longitude, newLocation.timestamp]; char *error; if ( sqlite3_exec(databasehandle, [insertStatement UTF8String], NULL, NULL, &error) == SQLITE_OK) { NSLog(@"Location

SharedPreferences save a text entered in an EditText and display it in a TextView in another activity

由 有些话、适合烂在心里 提交于 2020-02-02 13:56:53
问题 I'm beginner in Android development and I have an issue with save changement with some texts display in some TextViews. But one is more difficult for me. For explain simple, I have 2 activities, Activity1 is the main, Activity2 is the user informations. In Activity1 (Main) the user clic the button ("login") then he go on Activity2 here user can enter his personal informations and he click on a button ("save data") then I add his datas on a database (SQLite), then when the user click on

EF Core 2.1 slow startup

由 烂漫一生 提交于 2020-02-02 06:47:42
问题 After having some experience with EF6 (like this), I wanted to try out EF Core, because I've read some articles and watched some videos saying that it outperforms EF6 by a very large margin. So, I made sample program with class: public interface IEntity { int Id { get; set; } } public class Employee : IEntity { public int Id { get; set; } public string FirstName { get; set; } public string Surname { get; set; } } Then I created a repository pattern with generic repository: public interface

FMDB lastinsertRowID always 0

由 别说谁变了你拦得住时间么 提交于 2020-02-02 06:21:25
问题 Hya. I have implemented FMDB in my app. I am trying to get the last row id from one of my databases with this FMDatabase *bdb=[FMDatabase databaseWithPath:databasePath]; NSString *str; if([bdb open]){ int lastId=[bdb lastInsertRowId]; FMResultSet *s = [bdb executeQuery:[NSString stringWithFormat:@"SELECT budget FROM data WHERE ROWID='%d'",lastId]]; if([s next]) { str= [s stringForColumnIndex:0]; } } the problem i have is that lastId is always 0 , although there are 3 entries currently in the

FMDB lastinsertRowID always 0

由 做~自己de王妃 提交于 2020-02-02 06:19:45
问题 Hya. I have implemented FMDB in my app. I am trying to get the last row id from one of my databases with this FMDatabase *bdb=[FMDatabase databaseWithPath:databasePath]; NSString *str; if([bdb open]){ int lastId=[bdb lastInsertRowId]; FMResultSet *s = [bdb executeQuery:[NSString stringWithFormat:@"SELECT budget FROM data WHERE ROWID='%d'",lastId]]; if([s next]) { str= [s stringForColumnIndex:0]; } } the problem i have is that lastId is always 0 , although there are 3 entries currently in the
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