sql-like

I can't figure out what the underscore character does in an SQLite like statement. The wildcard character, % , is probably the same as in most other SQL databases. So, what does the damn _ character do? The underscore is also the same as in most other SQL databases and matches any single character (i.e. it is the same as . in a regular expression). From the fine manual : An underscore ("_") in the LIKE pattern matches any single character in the string. For example: -- The '_' matches the single 'c' sqlite> select 'pancakes' like 'pan_akes'; 1 -- This would need '__' to match the 'ca', only

I have a column of type bigint (ProductSerial) in my table. I need to filter the table by the Product serial using like operator. But I found that, like operator can't be used for integer type. Is there any other method for this (I don't want to use the = operator). If you must use LIKE , you can cast your number to char / varchar , and perform the LIKE on the result. This is quite inefficient, but since LIKE has a high potential of killing indexes anyway, it may work in your scenario: ... AND CAST(phone AS VARCHAR(9)) LIKE '%0203' If you are looking to use LIKE to match the beginning or the

I'm trying to find records that contain a string of 6 or more alpha-numeric characters in uppercase. Some examples: PENDING 3RDPARTY CODE27 I'm using the following statement: SELECT Details FROM MyTable WHERE Details LIKE '%[0-9A-Z][0-9A-Z][0-9A-Z][0-9A-Z][0-9A-Z][0-9A-Z]%'; This is returning all records that contain any 6-or-more-letter word, regardless of case. I've added a COLLATE statement: SELECT Details FROM MyTable WHERE Details COLLATE Latin1_General_CS_AS LIKE '%[0-9A-Z][0-9A-Z][0-9A-Z][0-9A-Z][0-9A-Z][0-9A-Z]%'; This changes nothing. It still returns records with 6-or-more-letter

I'm using a Derived Column Task to change column data using a CASE WHEN statement. However, I need to be able to say.. SQL CODE WOULD BE: CASE WHEN Column01 LIKE '%i%' THEN '0' ELSE '1' END In SSIS Expression Language that would be: [Column01] == "i" ? "0" : "1" (that's for equals i, not, LIKE %i%. Is it possible to use a LIKE operator? I believe you'll want to use the FINDSTRING function . FINDSTRING(character_expression, searchstring, occurrence) ... FINDSTRING returns null if either character_expression or searchstring are null. Guilherme de Jesus Santos I know it is an old question, but

This question already has an answer here: Leading wildcard character throws error in Lucene.NET 3 answers The wildcard * can only be used at the end of a word, like user* . I want to query with a like %user% , how to do that? Lucene provides the ReverseStringFilter that allows to do leading wildcard search like *user. It works by indexing all terms in reverse order. But I think there is no way to do something similar to 'LIKE %user%'. The trouble with LIKE queries is that they are expensive in terms of time taken to execute. You can set up QueryParser to allow leading wildcards with the

What is the regular expression to match strings (in this case, file names) that start with 'Run' and have a filename extension of '.py'? The regular expression should match any of the following: RunFoo.py RunBar.py Run42.py It should not match: myRunFoo.py RunBar.py1 Run42.txt The SQL equivalent of what I am looking for is ... LIKE 'Run%.py' ... . For a regular expression, you would use: re.match(r'Run.*\.py$') A quick explanation: . means match any character. * means match any repetition of the previous character (hence .* means any sequence of chars) \ is an escape to escape the explicit dot

I've got a database table mytable with a column name in Varchar format, and column date with Datetime values. I'd like to count names with certain parameters grouped by date. Here is what I do: SELECT CAST(t.date AS DATE) AS 'date', COUNT(*) AS total, SUM(LENGTH(LTRIM(RTRIM(t.name))) > 4 AND (LOWER(t.name) LIKE '%[a-z]%')) AS 'n' FROM mytable t GROUP BY CAST(t.date AS DATE) It seems that there's something wrong with range syntax here, if I just do LIKE 'a%' it does count properly all the fields starting with 'a'. However, the query above returns 0 for n, although should count all the fields