spaces

问题 Quick little question... I need to count the length of a string, but WITHOUT the spaces inside of it. E.g. for a string like "I am Bob", string.Length would return 8 (6 letters + 2 spaces). I need a method, or something, to give me the length (or number of) just the letters (6 in the case of "I am Bob") I have tried the following s.Replace (" ", ""); s.Replace (" ", null); s.Replace (" ", string.empty); to try and get "IamBob", which I did, but it didn't solve my problem because it still

问题 Quick little question... I need to count the length of a string, but WITHOUT the spaces inside of it. E.g. for a string like "I am Bob", string.Length would return 8 (6 letters + 2 spaces). I need a method, or something, to give me the length (or number of) just the letters (6 in the case of "I am Bob") I have tried the following s.Replace (" ", ""); s.Replace (" ", null); s.Replace (" ", string.empty); to try and get "IamBob", which I did, but it didn't solve my problem because it still

问题 Quick little question... I need to count the length of a string, but WITHOUT the spaces inside of it. E.g. for a string like "I am Bob", string.Length would return 8 (6 letters + 2 spaces). I need a method, or something, to give me the length (or number of) just the letters (6 in the case of "I am Bob") I have tried the following s.Replace (" ", ""); s.Replace (" ", null); s.Replace (" ", string.empty); to try and get "IamBob", which I did, but it didn't solve my problem because it still

问题 Is this possible? So if I were to print a value, I could print it with, say, 3 spaces before the actual output instead of four? 回答1: printf has a * format for dynamically specifying a minimum field width: #include <stdio.h> int main(int argc, char *argv[]) { int value = 5; const char *name = "LaDonna"; double value2 = 200.55; const char *space = " "; for (int width = 0; width < 10; width++) printf("%*d %*.2f %*s\n",width,value,width,value2,width + 5,name); for (int width=1; width < 5; width++

问题 I'm running Eclipse Juno Service Release 2 (20130225-0426) in Windows and I'm finding that auto-indent (Ctrl-I) ignores both the General/Editors/Text Editors/Insert spaces for tabs and Java/Code Style/Formatter/Indentation/Tab policy="Spaces only" settings. With both of those set, Ctrl-I indents the code with a combination of tabs and spaces, even though Ctrl-Shift-F uses spaces only. The problem is I don't want Eclipse to reformat my code -- just correct the indentation with spaces. Is this

问题 Is there any way to convert all spaces to tabs, not file by file? If I open a file and go through View => Indentation => Convert Indentation to Tabs , it only changes this file. I want to convert indentations to tabs in a whole project. 回答1: Use search and replace in multiple files to convert n spaces to tabs in select files. First open find in files panel, cmd + shift + f , by default to find and replace in multiple files. Next define a regular expression to match spaces as tabs eg {4} (make

问题 I am struggling to make a javascript regex to satisfy the following: The first character has to be alphabetical ( [a-zA-Z] ) The rest can be any letters, any numbers, hyphen, dot, underscore and spaces BUT no consecutive spaces, e.g: two or more spaces in a row The length has to be between 3 and 25 (inclusive) So here is what I found Regex: /^[a-z][\s\w.-]{3,24}$/i My current regex works, but won't be able to test whether the user has written consecutive spaces. How can I test for that? 回答1:

问题 I am struggling to make a javascript regex to satisfy the following: The first character has to be alphabetical ( [a-zA-Z] ) The rest can be any letters, any numbers, hyphen, dot, underscore and spaces BUT no consecutive spaces, e.g: two or more spaces in a row The length has to be between 3 and 25 (inclusive) So here is what I found Regex: /^[a-z][\s\w.-]{3,24}$/i My current regex works, but won't be able to test whether the user has written consecutive spaces. How can I test for that? 回答1:

问题 In the first yaml below, the second podSelector clause (under to ) seems correctly formatted, with two spaces indent for matchLabels , consistent with standards and the rest of the yaml. The second yaml is identical, but matchLabels has four spaces. This format follows the Kubernetes documentation. (There are no tabs.) Yet the first yaml fails kubectl validation with error validating "p.yaml": error validating data: ValidationError(NetworkPolicy.spec.egress[0].to[0]): unknown field

问题 I'm managing a JDBC database with Servlets/JSPs and one of the attributes I have in a table is a string which may or may not have spaces in between words. I have one JSP to display all the information and another one to edit it, on both I perform getString to a ResultSet and when I'm just displaying it it works fine, but on the edit JSP it only "grabs" the first word before the space and the rest of the string disappears. Here's part of the code: PerfilUsuarioConectado.jsp (the one I use to