sorting

For C++ sort(), how to pass a parameter to custom compare function?

孤街醉人 提交于 2021-01-28 07:55:22
问题 I want to use the standard sort function for sorting points in respect to their distance of another point (e.g. their barycenter). I know I can write a custom compare function, but I don't know how to pass a parameter to it. I want to have it thread-safe, so I do not want to store the parameter at one central location. Is there a way how to pass additional parameters to a custom compare function? // Here is a compare function without a parameter for sorting by the x-coordinate struct

How to implement a k-way merge sort?

寵の児 提交于 2021-01-28 07:25:19
问题 I need to implement a function which does a k-way merge sort on an unsorted array or integers. The function takes in two parameters, an integer K, which is the "way" of the sort and always a power of 2. The second parameter is the array of integers to be sorted, whose length is also a power of 2. The function is to return an array containing the sorted elements. So far, I know how to implement a regular merge sort. How would I modify this code so that it implements a K-way merge sort? (Note:

Insertion Sort of O(n^2) complexity and using Binary Search on previous values to improve complexity

五迷三道 提交于 2021-01-28 06:04:04
问题 How would the algorithm's (of Insertion Sort of O(n^2) ) complexity change if you changed the algorithm to use a binary search instead of searching previous values until you found where to insert your current value. Also, When would this be useful? 回答1: Your new complexity is still quadratic , since you need to move all of the sorted parts rightward. Therefore, using binary search is only marginally better. I would recommend a fast sorting algorithm (in O(n log n) time) for large arrays, the

Insertion Sort of O(n^2) complexity and using Binary Search on previous values to improve complexity

|▌冷眼眸甩不掉的悲伤 提交于 2021-01-28 05:56:05
问题 How would the algorithm's (of Insertion Sort of O(n^2) ) complexity change if you changed the algorithm to use a binary search instead of searching previous values until you found where to insert your current value. Also, When would this be useful? 回答1: Your new complexity is still quadratic , since you need to move all of the sorted parts rightward. Therefore, using binary search is only marginally better. I would recommend a fast sorting algorithm (in O(n log n) time) for large arrays, the

Sort GameObjects from an array to a reference point in space

夙愿已清 提交于 2021-01-28 05:35:12
问题 I have some GameObject in an array and I'd like to sort them by distance based on a point in space. So basically I'm searching for an point sorting by distance algorithm. I'm sure this is basic sorting algorithm stuff but I couldn't find a valid answer on Google so far. Thanks for the help ! 回答1: This should get you started: System.Array.Sort<GameObject>(arrayOfGameObjects, (g1, g2) => (Vector3.Distance(target,g1.transform.position) < Vector3.Distance(target,g2.transform.position))?-1:1); 回答2

Sets are sorted from 0-9 every single time in python?! Not unordered

99封情书 提交于 2021-01-28 05:10:13
问题 I thought it was a coincidence at first so I wrote up a test to try it out and it's true, I ran it 1 million times and every single time the set came back ordered and sorted. This only occurs when you use integers from 0-9 as soon as an integer > 9 is inserted then any integers inserted after will not be sorted. Why is this? Also for floats it kind of sorts it but isn't right all the time, so weird I thought they were completely unordered. Any advice on why 0-9 is sorted every time would be

Does sort -n handle ties predictably when the --stable option is NOT provided? If it does, how?

烈酒焚心 提交于 2021-01-28 04:50:48
问题 Here it looks like the space after the 3 in both rows breaks the numerical sorting and lets the alphabetic sorting kick in, so that 11 < 2 : $ echo -e '3 2\n3 11' | sort -n 3 11 3 2 In man sort , I read -s, --stable stabilize sort by disabling last-resort comparison which implies that without -s a last-resort comparison is done (between ties, because -s does not affect non-ties). So the question is: how is this last-resort comparison accomplished? A reference to the source code would be

JS sort array of objets by specific string property (not ascending or descending)

冷暖自知 提交于 2021-01-28 04:20:27
问题 do you know if there is a way to sort an array of objects using the sort() method for a specific property? In my case I'd like to sort my array first for "bananas", then for "pears", and then the rest. const initialData = [ { name: "strawberries", value: 12 }, { name: "bananas", value: 3 }, { name: "pears", value: 8 }, { name: "pears", value: 7 }, { name: "bananas", value: 10 }, { name: "apples", value: 6 }, { name: "bananas", value: 13 }, { name: "bananas", value: 5 } ] This is how I'd like

Merge array with common value

£可爱£侵袭症+ 提交于 2021-01-28 03:30:23
问题 I have two arrays namely arr and arr2. var arr=[{"month":"January","url":1},{"month":"February","url":102},{"month":"March","url":192}]; var arr2=[{"month":"January","ip":12},{"month":"June","ip":10}]; Is it possible to get array below shown from above two arrays? result=[{"month":"January","url":1,"ip":12},{"month":"February","url":102},{"month":"March","url":192},{"month":"June","ip":10}]; If i use array_merge then i get answer as result=[{"month":"January","url":1},{"month":"February","url

MongoDB find subdocument and sort the results

一世执手 提交于 2021-01-28 02:56:13
问题 I have a collection in MongoDB with a complex structure and subdocuments. The document have an structure like this: doc1 = { '_id': '12345678', 'url': "http//myurl/...", 'nlp':{ "status": "OK", "entities": { "0": { "type" : "Person", "relevance": "0.877245", "text" : "Neelie Kroes" }, "1": { "type": "Company", "relevance": "0.36242", "text": "ICANN" }, "2": { "type": "Company", "relevance": "0.265175", "text": "IANA" } } } } doc2 = { '_id': '987456321', 'url': "http//myurl2/...", 'nlp':{