sorting

how to find complete sorting of elements by frequency?

二次信任 提交于 2021-01-29 05:20:59
问题 Here is the problem: Given an array of integers, sort the array according to frequency of elements. For example, if the input array is {2, 3, 2, 4, 5, 12, 2, 3, 3, 3, 12}, then modify the array to {3, 3, 3, 3, 2, 2, 2, 12, 12, 4, 5}. if 2 numbers have same frequency then print the one which came 1st. I know how to do it partially. Here is my approcach. I will create a struct which will be like: typedef struct node { int index; // for storing the position of the number in the array. int count;

Remove null from old 2d array and put the not null elements in a new 2d array

ぃ、小莉子 提交于 2021-01-29 05:06:41
问题 I am trying to remove the null elements from the old 2d array and put it in a new 2d array, but the new 2d array is outputting all null elements. String[][] status = new String[P][M]; String[][] newStatus = new String[P][M]; for (int i = 0; i < status.length; i++) { for (int j = 0; j < status.length; j++) { if (status[i][j] != null) { newStatus[i][j] = status[i][j]; } } } Original 2d array: [[O, X, null, O, O, null, null], [null, null, O, null, null, O, O]] I want it to look like this: [[O, X

How to do uniq -d without presorting (or something similar)

…衆ロ難τιáo~ 提交于 2021-01-29 03:54:13
问题 I am aware that I can remove duplicated lines without presorting, for example: awk '!x[$0]++' file However, my goal is to only print lines which are duplicated and only once. If it were not for the presorting problem sort | uniq -d would be perfect. BUT the order is of great importance to me. Is there a way to do this with awk, grep or something similar? I am looking for a one liner which does not require writing a script if possible. 回答1: Just check the value of x[$0] : awk 'x[$0]++ == 1'

sorting a python list by frequency of elements

自作多情 提交于 2021-01-29 03:42:36
问题 I have this code which sorts python list by frequency of elements. It works for all other cases except when frequency of two elements are same. If the frequency is same then I want to place smaller value first before higher value: counts = collections.Counter(arr) new_list = sorted(arr, key=lambda x: counts[x]) for item in new_list: print item In case of [3,1,2,2,4] the output should be [1,3,4,2,2] but I get [3,1,4,2,2] . How do I resolve this error? 回答1: You can set your key lambda function

mixitup counting visible items on initial start after page loading

梦想与她 提交于 2021-01-29 03:26:50
问题 I am playing with mixitup to sort items. I can count items visible after I press a sort or filter buttons: $('#collection').on('mixEnd', function(e, state){ var countvisible = $("#container> tr[style='']").length; console.log('Sorted! ' + countvisible ); $('#current_count').text(countvisible); }); What I need: get a count of visible items on page load but the `on('mixEnd') does NOT ignite during the initialization of the mixitup on page load. How to do it? I can just use on PageLoad sit some

mixitup counting visible items on initial start after page loading

风格不统一 提交于 2021-01-29 03:18:34
问题 I am playing with mixitup to sort items. I can count items visible after I press a sort or filter buttons: $('#collection').on('mixEnd', function(e, state){ var countvisible = $("#container> tr[style='']").length; console.log('Sorted! ' + countvisible ); $('#current_count').text(countvisible); }); What I need: get a count of visible items on page load but the `on('mixEnd') does NOT ignite during the initialization of the mixitup on page load. How to do it? I can just use on PageLoad sit some

I know how Merge Sort works, but How Merge Sort Code Works?

旧巷老猫 提交于 2021-01-29 02:30:31
问题 You can read this on Wikipedia: function merge_sort(list m) // Base case. A list of zero or one elements is sorted, by definition. if length(m) <= 1 return m // Recursive case. First, *divide* the list into equal-sized sublists. var list left, right var integer middle = length(m) / 2 for each x in m before middle add x to left for each x in m after or equal middle add x to right // Recursively sort both sublists left = merge_sort(left) right = merge_sort(right) // Then merge the now-sorted

I know how Merge Sort works, but How Merge Sort Code Works?

旧巷老猫 提交于 2021-01-29 02:23:54
问题 You can read this on Wikipedia: function merge_sort(list m) // Base case. A list of zero or one elements is sorted, by definition. if length(m) <= 1 return m // Recursive case. First, *divide* the list into equal-sized sublists. var list left, right var integer middle = length(m) / 2 for each x in m before middle add x to left for each x in m after or equal middle add x to right // Recursively sort both sublists left = merge_sort(left) right = merge_sort(right) // Then merge the now-sorted

sort an ArrayList with multiple conditions

丶灬走出姿态 提交于 2021-01-29 00:02:35
问题 say i have an array list MyArrayList<MYObject> myObject class looks like : public class myObject { String name; Int age; String : city; } and my dummy data looks like this : name : martin , age : 20 , city : NY name : felix , age : 19 , city : LA name : brian , age : 21 , city : NY name : brian , age : 19 , city : NY now i wanna sort myArraylist (which have the above data in it) in this order - name : felix , lastname : 19 , city : LA name : brian , lastname : 21 , city : NY name : martin ,

sort an ArrayList with multiple conditions

浪子不回头ぞ 提交于 2021-01-28 23:58:48
问题 say i have an array list MyArrayList<MYObject> myObject class looks like : public class myObject { String name; Int age; String : city; } and my dummy data looks like this : name : martin , age : 20 , city : NY name : felix , age : 19 , city : LA name : brian , age : 21 , city : NY name : brian , age : 19 , city : NY now i wanna sort myArraylist (which have the above data in it) in this order - name : felix , lastname : 19 , city : LA name : brian , lastname : 21 , city : NY name : martin ,