sorting

问题 I have written this program to compare the number of operations needed to sort a random numbers using both selection and bubble sort. However, these numbers keep coming up the same and I can't figure out where my code went wrong. static int num_comps; public static void main(String[] args) { Random rnd = new Random(); // max size of array // number of N inputs int array_size = 32768; int num_datasets = 12; // allocate array once to the max size int[] vals = new int[array_size]; // temp array

问题 I would like to sort the values in the following file numbers.txt, below is an example 1.1 1.2 10.0 2.2 1000.0 However when I execute the following cmd sort numbers.txt I get the following: 1.1 1.2 10.0 1000.0 2.2 What cmd to I need to sort the numeric values appropriately? 回答1: Use the -n flag to sort numerically, instead of lexicographically: sort -n numbers.txt 来源： https://stackoverflow.com/questions/12764690/sorting-numbers-with-the-sort-command

问题 I have two THREE.ParticleSystem systems with particles that have textures with alpha transparency, one is using AdditiveBlending (fire texture), the other uses NormalBlending (smoke texture) and they use simple custom vertex and fragment shaders. Each ParticleSystem has "sortParticles = true" and independently they work perfectly, however when both types of particles overlap the first particle system (fire texture) has a similar transparency depth error that is normally associated with

问题 I am looking to randomly shuffle a list/array using a key. I want to be able to repeat the same random order using the key. So I will randomly generate a numeric key from say 1 to 20 then use that key to try and randomly shuffle the list. I first tried just using the key to keep iterating through my list, decrementing the key until=0, then grabbing whatever element I am on, removing it and adding it to my shuffled array. The result is kind of random but when the arrays are small (which most

问题 I am used following bubble sort algorithm for making sorting . Is this algorithm correct? for (int a = itemWiseBidderList.size() - 1; a > 1; a--) { for (int j = 0; j < a; j++) { if ((itemWiseBidderList.get(j).getRankInInt()) > (itemWiseBidderList.get(j + 1).getRankInInt())) { Collections.swap(itemWiseBidderList, j, j + 1); } } } 回答1: If bubble sorting is not a requirement (by homework?), then the correct way to implement sorting in Java is by calling Collections.sort(itemWiseBidderList); If

问题 I have a mixed array that I need to sort by alphabet and then by digit [A1, A10, A11, A12, A2, A3, A4, B10, B2, F1, F12, F3] How do I sort it to be: [A1, A2, A3, A4, A10, A11, A12, B2, B10, F1, F3, F12] I have tried arr.sort(function(a,b) {return a - b}); but that only sorts it alphabetically. Can this be done with either straight JavaScript or jQuery? 回答1: var reA = /[^a-zA-Z]/g; var reN = /[^0-9]/g; function sortAlphaNum(a, b) { var aA = a.replace(reA, ""); var bA = b.replace(reA, ""); if

问题 I'm trying to sort a dictionary by value with LINQ but I can't figure how the ToDictionary() method works. All the examples I can find are in c#. here's my code Dim f As Dictionary(Of String, String) = (From value In projectDescriptions.Values Order By value Ascending Select value).ToDictionary(???) UPDATE Finally, I just realized that was stupid. Sorry I did a list (of keyValuePair(of string,string)) And to sort my list, I do mylist.OrderBy(Function(x) x.Value).ToList() hope it will help

问题 Basically I'm trying to get a "rankings" between 4 people. I have an array of player scores which contains the scores of each person such that person 1's score is at index 0, person 2's score is at index 1, etc... I want to obtain the index of the top scorer in the list and get the second, and the third, and the last. My attempt at the solution: I made a list out of the array playerScores (I feel like it might not be necessary, but due to what I'm about to do, I didn't want to ruin the

问题 I am allowed to use an extra array to perform a stable quicksort unlike the general quicksort algorithm. I know how to select the pivot at random and partition accordingly but I'm not able to figure out how to make use of the additional array to make it stable. 回答1: The most trivial way that comes to mind is to store the initial indices in the array (1, 2, 3, etc) and swap them around as you swap the data. Then in the comparison, if the two elements are equal, compare their indices too, thus

问题 I have a class Segment and an array of segments like this: private static class Segment { int number, type; Segment(int number, int type) { this.number = number; this.type = type; } } Segment[] points = new Segment[n]; points={(0,-1),(1,0),(5,1),(6,0),(6,-1),(10,1),(11,0)} The element of the left is a list of points, and the list of the right is the type of point: -1 opens a segment, 1 closes a segment and 0 intersects the segment. As you can see, this array is already sorted according to