sorting

问题 I have the following dataframe that I would like to sort first by Criticality and then by Name: Name Criticality baz High foo Critical baz Low foo Medium bar High bar Low bar Medium ... I've been trying to do this using the answer provided in this post but I just can't get it to work. The end result should be like this Name Criticality bar High bar Medium bar Low baz High baz Low foo Critical foo Medium 回答1: One approach would be to use a custom dict to create a 'rank' column, we then use to

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 5 years ago . How can i convert these strings in to date format and sort accordingly....please 2010-11-08 18:58:50.0_getCreated_10180 2010-11-09 17:49:42.0_getCreated_10180 2010-11-09 17:49:42.0_getCreated_10180 2010-11-24 19:44:51.0_getCreated_10180 2010-11-09 13:54:46.0_getCreated_10180 2010-11-23 20:06:29.0_getCreated

问题 I was wondering if, in terms of performance and considering a mysql select on a table with very very very many (> 1.000.000) records, is better sorting results with sql "order by" or sorting results after the query with classical programming sort algorithm ... someone has any suggestion? Tanks 回答1: You're comparing a system with methods implemented in optimized C, meant to do exactly this task, with another that you are going to implement in an interpreted scripting language. Basically,

问题 Can I access a list while it is being sorted in the list.sort() b = ['b', 'e', 'f', 'd', 'c', 'g', 'a'] f = 'check this' def m(i): print i, b, f return None b.sort(key=m) print b this returns b [] check this e [] check this f [] check this d [] check this c [] check this g [] check this a [] check this Note that individual items of list b is sent to function m . But at m the list b is empty, however it can see the variable f , which has same scope as list b . Why does function m print b as []

问题 Can I access a list while it is being sorted in the list.sort() b = ['b', 'e', 'f', 'd', 'c', 'g', 'a'] f = 'check this' def m(i): print i, b, f return None b.sort(key=m) print b this returns b [] check this e [] check this f [] check this d [] check this c [] check this g [] check this a [] check this Note that individual items of list b is sent to function m . But at m the list b is empty, however it can see the variable f , which has same scope as list b . Why does function m print b as []

问题 I would like to get your help about this little problem. I have like to order this array depending on the code value but not in alphabetical order. ( I specified this in bold but got eventually flagged anyway, people don't even care about reading the question ) For example I would like to have all the green objects, then all the blue ones and then all the red ones. What is the best way to do that? [ { code: "RED", value: 0}, { code: "BLUE", value: 0}, { code: "RED", value: 0}, { code: "GREEN"

问题 How can I sort this list in descending order? timestamp = [ "2010-04-20 10:07:30", "2010-04-20 10:07:38", "2010-04-20 10:07:52", "2010-04-20 10:08:22", "2010-04-20 10:08:22", "2010-04-20 10:09:46", "2010-04-20 10:10:37", "2010-04-20 10:10:58", "2010-04-20 10:11:50", "2010-04-20 10:12:13", "2010-04-20 10:12:13", "2010-04-20 10:25:38" ] 回答1: In one line, using a lambda : timestamp.sort(key=lambda x: time.strptime(x, '%Y-%m-%d %H:%M:%S')[0:6], reverse=True) Passing a function to list.sort : def

问题 As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references, or expertise, but this question will likely solicit debate, arguments, polling, or extended discussion. If you feel that this question can be improved and possibly reopened, visit the help center for guidance. Closed 7 years ago . my professor has asked to sort a 2d char array by column so the attached array he wants sorted is unsorted sorted last column

问题 Can you please help me sorting the dictionary below with value "Val1". var data = ["key1" : ["val1": 1,"val2": 1], "key2" : ["val1": 5,"val2": 2], "key3" : ["val1": 0,"val2": 9]] I am expecting this dictionary to be sorted like this. Highest values of 'Val1' to be on top (descending order).. var data = [ "key2" : ["val1": 5,"val2": 2], "key1" : ["val1": 1,"val2": 1], "key3" : ["val1": 0,"val2": 9]] 回答1: As @Sulthan correctly pointed out Dictionary cannot be sorted. If you still want to, you

问题 So for this program I need to obtain three strings from a user and sort those strings alphabetically. The caveat is that I cannot use arrays. Also if the string does not start with an alphabetic letter than it is not accepted. So far I have managed to get the three strings from the user and am able to determine if they should be accepted on or not. What I can't figure out is how to sort them alphabetically. The main issue I am having is ignoring the strings that weren't accepted when sorting.