sorting

问题 How can I ignore "The" when the user sorts a view in a Drupal site ? 回答1: Have you tried looking into the Views Natural Sort Module ? taken from module page linked above.. Provides a views filter that sorts titles by a more natural manner by ignoring articles like "The" and "A." 来源： https://stackoverflow.com/questions/3189092/ignore-the-when-sorting-a-view-in-drupal

问题 I have a collection following this "schema" : { _id: ObjectId, order: Number, fieldA: ObjectId, fieldB: Array[ObjectId] } And an index defined like this : { fieldA: 1, fieldB: 1, order: 1 } When running a find query like this one : { $and: [ {fieldA: {$in: [{"$oid":"592edae196232608d00f78f5"},{"$oid":"592edadc96232608d00f5614"}]}}, {fieldB: {$in:[{"$oid":"592edace96232608d00ef77f"},{"$oid":"592edacd96232608d00ef34b"}]}} ] } with sort defined as { order: 1 } The query runs fine, the index

问题 How do I remove element from a list of tuple if the 2nd item in each tuple is a duplicate? For example, I have a list sorted by 1st element that looks like this: alist = [(0.7897897,'this is a foo bar sentence'), (0.653234, 'this is a foo bar sentence'), (0.353234, 'this is a foo bar sentence'), (0.325345, 'this is not really a foo bar'), (0.323234, 'this is a foo bar sentence'),] The desired output leave the tuple with the highest 1st item, should be: alist = [(0.7897897,'this is a foo bar

问题 first of all, thank you for your help in forward. I'm using Python and I'm trying to search a .py file for all of its functions starting with the name "test_" and all of the variables included. The variables I search for are formatted like this: "var["blabla"]". So here I have an example: def test_123: init = var["blabla1"] init2 = var["blabla2"] *somecode* def test_456: init3 = var["blabla3"] init4 = var["blabla4"] *somecode* What I already wrote is a script, that returns all my functions

问题 I have a couple of classes that implement an interface, IFoo. I need to display a list of objects of these classes in a table, which I'd like to be able to sort by any arbitrary column in the table. So, the data source for the table is a List<IFoo> . The problem I've run into is that the standard way of implementing IComparable or IComparer for objects that are used in a list requires a static method, but static methods aren't allowed in interfaces. So, the question boils down to this: how

问题 var listOne = new string[] { "dog", "cat", "car", "apple"}; var listTwo = new string[] { "car", "apple"}; What I need is to order listOne by the order of items in listTwo (if present). So the new list would be in this order; "car", "apple", "dog", "cat" I would like to do this in LINQ and have tried this; var newList = from l1 in listOne join l2 in listTwo on l1 equals l2 in temp from nl temp.DefaultIfEmpty() select nl; But it returns null so evidently my Linq-Fu is weak. Any advise is

问题 var listOne = new string[] { "dog", "cat", "car", "apple"}; var listTwo = new string[] { "car", "apple"}; What I need is to order listOne by the order of items in listTwo (if present). So the new list would be in this order; "car", "apple", "dog", "cat" I would like to do this in LINQ and have tried this; var newList = from l1 in listOne join l2 in listTwo on l1 equals l2 in temp from nl temp.DefaultIfEmpty() select nl; But it returns null so evidently my Linq-Fu is weak. Any advise is

问题 I have a function that I wrote below. This function is essentially a merge-sort. public static long nlgn(double[] nums) { if(nums.length > 1) { int elementsInA1 = nums.length/2; int elementsInA2 = nums.length - elementsInA1; double[] arr1 = new double[elementsInA1]; double[] arr2 = new double[elementsInA2]; for(int i = 0; i < elementsInA1; i++) arr1[i] = nums[i]; for(int i = elementsInA1; i < elementsInA1 + elementsInA2; i++) arr2[i - elementsInA1] = nums[i]; nlgn(arr1); nlgn(arr2); int i = 0

问题 I have a function that I wrote below. This function is essentially a merge-sort. public static long nlgn(double[] nums) { if(nums.length > 1) { int elementsInA1 = nums.length/2; int elementsInA2 = nums.length - elementsInA1; double[] arr1 = new double[elementsInA1]; double[] arr2 = new double[elementsInA2]; for(int i = 0; i < elementsInA1; i++) arr1[i] = nums[i]; for(int i = elementsInA1; i < elementsInA1 + elementsInA2; i++) arr2[i - elementsInA1] = nums[i]; nlgn(arr1); nlgn(arr2); int i = 0

问题 I have a function that I wrote below. This function is essentially a merge-sort. public static long nlgn(double[] nums) { if(nums.length > 1) { int elementsInA1 = nums.length/2; int elementsInA2 = nums.length - elementsInA1; double[] arr1 = new double[elementsInA1]; double[] arr2 = new double[elementsInA2]; for(int i = 0; i < elementsInA1; i++) arr1[i] = nums[i]; for(int i = elementsInA1; i < elementsInA1 + elementsInA2; i++) arr2[i - elementsInA1] = nums[i]; nlgn(arr1); nlgn(arr2); int i = 0