sorting

问题 I am a C student in VBScript coding and need a little help. My code executes a split command as follows: outputArray = split(Description," ") With the individual words from Description now in an array, I want to sort the array based on the string length for each word. So, for example, if Description is equal to "this is an example of a description" then my array values are [this, is, an, example, of, a, description], right? But I want to resort the array so that the longest words are first, i

问题 I have tried to get an XML file to sort and have had no luck. After a day and a-half, I need some help from an expert. Thanks. My XML File (shortened for the example): <?xml version="1.0" encoding="iso-8859-1"?> <deadlines> <deadline> <date>2010-06-01</date> <text>Application for Summer Due</text> </deadline> <deadline> <date>2010-07-01</date> <text>Application for Fall Due</text> </deadline> <deadline> <date>2010-07-31</date> <text>Summer Bill Due</text> </deadline> </deadlines> My PHP: <

问题 I have been trying to understand es6 arrow function. I read some articles introducing it. But I'am still not getting it fully. For example I have this code: sortedArticles(): Article[] { return this.articles.sort((a: Article, b: Article) => b.votes - a.votes); } It sorts the below array: [ new Article('Angular 2', 'http://angular.io', 3), new Article('Fullstack', 'http://fullstack.io', 2), new Article('Angular Homepage', 'http://angular.io', 1), ]; How would the same code look in plain old js

问题 For lists, we use the Collections.sort(List) method. What if we want to sort a HashSet ? 回答1: A HashSet does not guarantee any order of its elements. If you need this guarantee, consider using a TreeSet to hold your elements. However if you just need your elements sorted for this one occurrence, then just temporarily create a List and sort that: Set<?> yourHashSet = new HashSet<>(); ... List<?> sortedList = new ArrayList<>(yourHashSet); Collections.sort(sortedList); 回答2: Add all your objects

问题 I have a list of elements, each one identified with a type, I need to reorder the list to maximize the minimum distance between elements of the same type. The set is small (10 to 30 items), so performance is not really important. There's no limit about the quantity of items per type or quantity of types, the data can be considered random. For example, if I have a list of: 5 items of A 3 items of B 2 items of C 2 items of D 1 item of E 1 item of F I would like to produce something like: A , B

问题 I want to show a list of categories in my Virtuemart webshop vertically sorted the same way as shown in this demonstration: http://www.inkplant.com/code/mysql-vertical-sort.php So I borrowed the code: <?php $cols = 4; //number of columns, you can set this to any positive integer $values = array(); $result = mysql_query("SELECT * FROM states ORDER BY name"); $numrows = mysql_num_rows($result); $rows_per_col = ceil($numrows / $cols); for ($c=1;$c<=$cols;$c++) { $values['col_'.$c] = array(); }

问题 var Bible = JSON.parse( fs.readFileSync(bible.json, 'utf8') ); _.each(Bible, function (b, Book) { return Book; }); This outputs each book name from the Bible (ex. Genesis, Exodus, Leviticus, etc.). The problem is that the books from the JSON file are not in order. I have tried to sort them in various ways, but nothing seems possible inside of the _.each loop. When I did this: correctlyOrderedList.indexOf(Book) - correctlyOrderedList.indexOf(b); It returned the index of each one correctly, but

问题 var Bible = JSON.parse( fs.readFileSync(bible.json, 'utf8') ); _.each(Bible, function (b, Book) { return Book; }); This outputs each book name from the Bible (ex. Genesis, Exodus, Leviticus, etc.). The problem is that the books from the JSON file are not in order. I have tried to sort them in various ways, but nothing seems possible inside of the _.each loop. When I did this: correctlyOrderedList.indexOf(Book) - correctlyOrderedList.indexOf(b); It returned the index of each one correctly, but

问题 If there is an array array A = ["a","b","c","d"] #Index is [0,1,2,3] And it's sorted to. array A = ["d","c","b","a"] I need an array that returns me the updated index based on the sorted order [3,2,1,0] I'm trying to find a solution to this ruby UPDATE to the question If a is sorted to array A = ["d","b","c","a"] #not a pure reverse Then the returned index array should be [3,1,2,0] 回答1: You need to create a mapping table that preserves the original order, then use that order to un-map the re

问题 I am using Google Datastore and will need to query it to retrieve some entities. These entities will need to be sorted by newest to oldest. My first thought was to have a date_created property which contains a timestamp. I would then index this field and sort on this field. The problem with this approach is it will cause hotspots in the database (https://cloud.google.com/datastore/docs/best-practices). Do not index properties with monotonically increasing values (such as a NOW() timestamp).