sorting

return the smallest possible join from array javascript

孤街醉人 提交于 2020-01-24 20:03:08
问题 I have this code which works good for this array: ['45', '30', '50', '1']. function penalty(a_list) { return a_list.sort((a, b) => a - b).join(''); } for example: given that a_list is ['45', '30', '50', '1'] the smallest possible string will be '1304550' which is right, but what if a_list is ['32', '3'] given this current code I will get '332' which is not correct because '323' is the smallest possible string. Hope that helps. 回答1: You could take the concatinated values of a and b and the

Sorting an array using two different criteria

别等时光非礼了梦想. 提交于 2020-01-24 19:47:31
问题 I am trying to sort an array using the insertion sort algorithm. The array is filled with WordNode elements that include a word field (inputted from a text file) and a frequency field (to measure the number of times the particular word appears in the text file). I have implemented the sort so that words are sorted by frequency (from lowest to highest), but I also want to sort alphabetically if frequencies are equal. How can I sort using two different criteria at the same time? Below is my

Sorting dictionary keys by value, then those with the same value alphabetically

拥有回忆 提交于 2020-01-24 16:17:40
问题 I know it wasn't well explained in the title so I'll try and do a better job here. I want to sort a dictionary's keys by their respective values, and then sort any keys with the same value alphabetically. What is the best way to do this, ideally without the use of modules? Does python do this automatically with a sort like: sorted(dictionary.items(), key=lambda x: x[1]) I tried the above code and it seemed to work but I couldn't tell if it was just coincidence or not. I couldn't find anything

Changing NULL's position in sorting

倖福魔咒の 提交于 2020-01-24 15:57:05
问题 I am sorting a table. The fiddle can be found here. CREATE TABLE test ( field date NULL ); INSERT INTO test VALUES ('2000-01-05'), ('2004-01-05'), (NULL), ('2008-01-05'); SELECT * FROM test ORDER BY field DESC; The results I get: 2008-01-05 2004-01-05 2000-01-05 (null) However I need the results to be like this: (null) 2008-01-05 2004-01-05 2000-01-05 So the NULL value is treated as if it is higher than any other value. Is it possible to do so? 回答1: Easiest is to add an extra sort condition

Re-ordering df.columns alpha numerically

匆匆过客 提交于 2020-01-24 15:47:28
问题 I have a df as follows: Store Spend_1 Spend_2 Spend_3 Spend_4 Variance_1 Variance_2 Variance_3 Variance_4 0 1 200 230 189 200 -14 16 -6 18 1 2 224 104 240 203 -17 -11 17 -18 2 3 220 168 131 210 10 -9 12 19 3 4 143 187 139 188 -1 -17 -20 -9 4 5 179 121 162 131 6 -25 5 20 5 6 208 158 140 191 16 -14 -22 -6 I'm attempting to apply a custom sort on the column names to order it as so : Store Spend_1 Variance_1 Spend_2 Variance_2 Spend_3 Variance_3 Spend_4 Variance_4 0 1 200 -14 230 16 189 -6 200 18

Two ways of doing Counting Sort

风格不统一 提交于 2020-01-24 15:42:05
问题 Here are my two implementations of Counting Sort In this implementation which is a very simple one, all I do is count the number of occurrences of the element, and insert as many times as the occurrences in the output array. Implementation 1 public class Simple { static int[] a = {5,6,6,4,4,4,8,8,8,9,4,4,3,3,4}; public static void main(String[] args) { fun(a); print(a); } static void fun(int[] a) { int max = findMax(a); int[] temp = new int[max+1]; for(int i = 0;i<a.length;i++) { temp[a[i]]++

Sort an array of objects in Java

风流意气都作罢 提交于 2020-01-24 15:05:40
问题 I am working on a report module that shows the time spent and number of tasks. The values are set in the Java Bean and the bean object is stored in a array.I am using separate queries to get time and number of tasks.Now i have to sort the array based on time and number of tasks. The code below compares only Strings: if (!list.isEmpty()) { Collections.sort(list, new Comparator<Project>() { @Override public int compare(Project p1, Project p2) { return p1.getName().compare(p2.getName()); } }); }

Best way to reorder a list realtime in React-Redux?

柔情痞子 提交于 2020-01-24 13:42:46
问题 I'm currently build an app that have a realtime list. the view of list as bellow picture: This list will be updated realtime, when one of these actions is trigger: A message is updated, the updated_time will be changed Receive new message Receive unread status of message So I want to sort this list base on two conditions: All unRead_message allways at the top All message should be sorted by updated_time DESC (newest first), except unread_message always in prioty. The data of this list is

Best way to reorder a list realtime in React-Redux?

℡╲_俬逩灬. 提交于 2020-01-24 13:42:09
问题 I'm currently build an app that have a realtime list. the view of list as bellow picture: This list will be updated realtime, when one of these actions is trigger: A message is updated, the updated_time will be changed Receive new message Receive unread status of message So I want to sort this list base on two conditions: All unRead_message allways at the top All message should be sorted by updated_time DESC (newest first), except unread_message always in prioty. The data of this list is

How do you set the Collation for a SPARQL query?

試著忘記壹切 提交于 2020-01-24 13:22:25
问题 I am a Java developer working with a MarkLogic database. A key function of my code is its capacity to dynamically generate 4-6 SPARQL queries and run them via HTTP GET requests. The results of each are added together and then returned. I now need these results sorted consistently. Since I am paging the results of each query (using the LIMIT and OFFSET statements) each query has its own ORDER BY statement. Without embedding sorting into the queries the pages of results will be returned out of