sorm

How to model an entity with many children in Sorm?

由 微笑、不失礼 提交于 2019-12-18 05:14:20
问题 I have a Workspace and Document entities, with the idea that a workspace can contain zero, one, or more documents. My first approach to model this was: case class Workspace(name: String, documents: Seq[Document]) but this will not scale well since my workspaces may contain many documents. Fortunately, my business requirement allow me to treat workspaces and documents separately (in the sense that when I have a workspace, there is no reason or invariant that forces me to consider all documents

SORM: How can I declare foreign keys?

由 送分小仙女□ 提交于 2019-12-10 13:45:01
问题 I'm very interested in SORM, but when I try to use it I bump into problem. Suppose I have two entities: case class User(login: String, firstName: String, lastName: String) case class UserSite(userId: Int, name: String, url: String) How can I declare foreign key relation UserSite.userId -> User.id? I see class ForeignKey, but there are no any example of using it. Thank you. 回答1: A very nice opportunity to exhibit the powers of SORM. As indicated in the Features of SORM, it abstracts away from

Fetch object by plain SQL query with SORM

由 不问归期 提交于 2019-12-10 03:19:02
问题 Is it possible to fetch items by plain SQL query instead of building query by DSL using SORM? For example is there an API for making something like val metallica = Db.query[Artist].fromString("SELECT * FROM artist WHERE name = ?", "Metallica").fetchOne() // Option[Artist] instead of val metallica = Db.query[Artist].whereEqual("name", "Metallica").fetchOne() // Option[Artist] 回答1: Since populating an entity with collections and other structured values involves fetching data from multiple

How can I create a different entity type using the original entity id in sorm?

由 孤者浪人 提交于 2019-12-08 07:56:33
问题 I have the following classes: case class Product( title : String, description: String, contract: Contract) case class Contract(contractType: ContractType, price: Int ) case class ContractType(description: String) and these DTOs: case class ProductDto(id: Long, title: String, description: String, contractType: ContractTypeDto, price: Int) case class ContractTypeDto(id: Long, description: String) I need to create a method that returns the list of products but with the data filled in DTOs,

Using SORM with Play Framework 2.3.8

由 一曲冷凌霜 提交于 2019-12-07 02:32:24
问题 I am going through the Video introduction to Play Framework and, but I am stuck creating a DB object with SORM because the import fails. I tried to add the dependencies in plugins.sbt , and relaunched activator, but it seems that activator cannot find the dependencies and I get and I get an unresolved error : addSbtPlugin("org.sorm-framework" % "sorm" % "0.3.14") addSbtPlugin("com.h2database" % "h2" % "1.4.181") I got the versions from the Yvis repository. I also tried other versions with no

Using SORM with Play Framework 2.3.8

由 陌路散爱 提交于 2019-12-05 08:12:10
I am going through the Video introduction to Play Framework and, but I am stuck creating a DB object with SORM because the import fails. I tried to add the dependencies in plugins.sbt , and relaunched activator, but it seems that activator cannot find the dependencies and I get and I get an unresolved error : addSbtPlugin("org.sorm-framework" % "sorm" % "0.3.14") addSbtPlugin("com.h2database" % "h2" % "1.4.181") I got the versions from the Yvis repository . I also tried other versions with no better luck. should be add as libraryDependencies += "org.sorm-framework" % "sorm" % "0.3.16" in build

Using SORM with Play Framework causes reflection exceptions to be thrown

由 半城伤御伤魂 提交于 2019-12-04 01:44:41
问题 I've been trying to get SORM working with Play Framework 2.2-SNAPSHOT as well as 2.1.1. Currently I'm trying to run a minimalistic sample application that I created in order to track down the issue more easily. Unfortunately the error message I receive doesn't help me at all. val appDependencies = Seq( "org.sorm-framework" % "sorm" % "0.3.8", "com.h2database" % "h2" % "1.3.168" ) # Database configuration # db.default.driver=org.h2.Driver db.default.url="jdbc:h2:mem:play" # db.default.user=sa

How to use SORM framework with Play Framework?

由 半世苍凉 提交于 2019-12-02 00:42:02
问题 I find SORM very Interesting and promising but I cant find a way to Integrate It with play any guides? 回答1: Install Play >= 2.1.0. Generate a project using Play's guides Add appropriate SORM's and chosen database's dependencies to the generated project/Build.scala , e.g.: val appDependencies = Seq( "org.sorm-framework" % "sorm" % "0.3.8", "com.h2database" % "h2" % "1.3.168" ) In the same file make sure that your project depends on the same Scala version, on which SORM depends (for SORM 0.3.8

How to use SORM framework with Play Framework?

由 大城市里の小女人 提交于 2019-12-01 22:27:37
I find SORM very Interesting and promising but I cant find a way to Integrate It with play any guides? Nikita Volkov Install Play >= 2.1.0. Generate a project using Play's guides Add appropriate SORM's and chosen database's dependencies to the generated project/Build.scala , e.g.: val appDependencies = Seq( "org.sorm-framework" % "sorm" % "0.3.8", "com.h2database" % "h2" % "1.3.168" ) In the same file make sure that your project depends on the same Scala version, on which SORM depends (for SORM 0.3.8 it's Scala 2.10.1): val main = play.Project(appName, appVersion, appDependencies).settings(

Using SORM with Play Framework causes reflection exceptions to be thrown

由 谁说我不能喝 提交于 2019-12-01 09:07:46
I've been trying to get SORM working with Play Framework 2.2-SNAPSHOT as well as 2.1.1. Currently I'm trying to run a minimalistic sample application that I created in order to track down the issue more easily. Unfortunately the error message I receive doesn't help me at all. val appDependencies = Seq( "org.sorm-framework" % "sorm" % "0.3.8", "com.h2database" % "h2" % "1.3.168" ) # Database configuration # db.default.driver=org.h2.Driver db.default.url="jdbc:h2:mem:play" # db.default.user=sa # db.default.password="" case class Car( brand: String, wheels: Int ) object Db extends Instance( Seq(
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