smtplib

How to get line breaks in e-mail sent using Python's smtplib?

廉价感情. 提交于 2019-12-03 18:01:10
问题 I have written a script that writes a message to a text file and also sends it as an email. Everything goes well, except the email finally appears to be all in one line. I add line breaks by \n and it works for the text file but not for the email. Do you know what could be the possible reason? Here's my code: import smtplib, sys import traceback def send_error(sender, recipient, headers, body): SMTP_SERVER = 'smtp.gmail.com' SMTP_PORT = 587 session = smtplib.SMTP('smtp.gmail.com', 587)

Python Email Parsing Issue

旧街凉风 提交于 2019-12-03 17:50:25
问题 so I'm trying to write a script in python that logs into my gmail account and then tells me, soon in a GUI, what the message is. I will do a bit more stuff to the code later on to make it a bit program a bit more useful but right now I'm stuck on just being able to parse the raw information that I am getting. Here is my code: #Read Email Script import imaplib import email mail = imaplib.IMAP4_SSL('imap.gmail.com') mail.login('username@gmail.com', 'passwordgoeshere') mail.list() mail.select(

Cant send email via python using gmail - smtplib.SMTPException: SMTP AUTH extension not supported by server

有些话、适合烂在心里 提交于 2019-12-03 05:19:27
问题 I just want to send an email in python with an attachment import smtplib, os from email.MIMEMultipart import MIMEMultipart from email.MIMEBase import MIMEBase from email.MIMEText import MIMEText from email.Utils import COMMASPACE, formatdate from email import Encoders def send_mail(send_from, send_to, subject, text, files=[], server="localhost"): assert type(send_to)==list assert type(files)==list msg = MIMEMultipart() msg['From'] = send_from msg['To'] = COMMASPACE.join(send_to) msg['Date'] =

Sendmail Errno[61] Connection Refused

我是研究僧i 提交于 2019-12-03 05:01:06
问题 I've been trying to get my application to mail some outputted text to an email. For simplification I have isolated the script : import smtplib import sys import os SERVER = "localhost" FROM = os.getlogin() TO = [raw_input("To : ")] SUBJECT = "Message From " + os.getlogin() print "Message : (End with ^D)" TEXT = '' while 1: line = sys.stdin.readline() if not line: break TEXT = TEXT + line # Prepare actual message message = """\ From: %s To: %s Subject: %s %s """ % (FROM, ", ".join(TO), SUBJECT

Python TimeoutError: [WinError 10060] A connection attempt failed

ⅰ亾dé卋堺 提交于 2019-12-03 04:07:20
I am trying to make a python program that checks to see if the cost has changed or not for a website. However, every time I run the code it comes up with this python error below and then I can not access the site on any devices in the house for a period of time without is saying 'This site can’t be reached the site took too long to respond.' Even though it doesn't load for me the website is still working Code below try: from urllib.request import urlopen import smtplib import time except ImportError: # Fall back to Python 2's urllib2 from urllib2 import urlopen ufo = urlopen("https://www

python & smtplib: Is sending mail via gmail using oauth2 possible?

守給你的承諾、 提交于 2019-12-03 00:38:22
So I can login to and send mail through gmail using smtplib (using the script below), but I was just wondering if using oauth2 was an option like with imaplib? I didn't see anything on the smtplib documentation page about oauth and I haven't found anything googling. Thanks. #! /usr/bin/python import smtplib to = 'myemailaddress' gmail_user = 'myemailaddress' gmail_pwd = 'passwd' smtpserver = smtplib.SMTP("smtp.gmail.com",587) smtpserver.ehlo() smtpserver.starttls() smtpserver.ehlo smtpserver.login(gmail_user, gmail_pwd) header = 'To:' + to + '\n' + 'From: ' + gmail_user + '\n' + 'Subject

Sendmail Errno[61] Connection Refused

亡梦爱人 提交于 2019-12-02 17:27:40
I've been trying to get my application to mail some outputted text to an email. For simplification I have isolated the script : import smtplib import sys import os SERVER = "localhost" FROM = os.getlogin() TO = [raw_input("To : ")] SUBJECT = "Message From " + os.getlogin() print "Message : (End with ^D)" TEXT = '' while 1: line = sys.stdin.readline() if not line: break TEXT = TEXT + line # Prepare actual message message = """\ From: %s To: %s Subject: %s %s """ % (FROM, ", ".join(TO), SUBJECT, TEXT) # Send the mail server = smtplib.SMTP(SERVER) server.sendmail(FROM, TO, message) server.quit()

.sendmail function trying to convert to ASCII, do I have to convert?

陌路散爱 提交于 2019-12-02 08:56:19
So I'm trying to send an email using python but I can't as long as it converts it to ASCII, is there a way around this or do I need to find another function? File "/usr/lib/python3.6/smtplib.py", line 855, in sendmail msg = _fix_eols(msg).encode('ascii') UnicodeEncodeError: 'ascii' codec can't encode character '\u2019' in position 1562: ordinal not in range(128) Can I get around this or do I have convert? and how would i convert? Traditionally, SMTP requires the message you submit to be in ASCII. The problem is earlier in the process: The message you are trying to pass in should already have

Sending gmail using python failing

随声附和 提交于 2019-12-02 08:18:00
1. pip error I did pip install smtplib Then it says Could not find a version that satisfies the requirement smtplib (from versions: ) No matching distribution found for smtplib I confirmed that pip install youtube_dl works. So it's probably not a problem with pip. 2. Import error Anyways, the code I am running is import smtplib GMAIL_USERNAME = "something" GMAIL_PASSWORD = "something" recipient = "something" body_of_email = "body" email_subject = "ha" # The below code never changes, though obviously those variables need values. session = smtplib.SMTP('smtp.gmail.com', 587) session.ehlo()

Setting Return-Path with Python sendmail for a MIME message

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-01 20:03:25
Hi would like to set the "Return-Path" header for a MIME message I send with Python. Basically, I tried something like this : message = MIMEMultipart() message.add_header("Return-Path", "something@something.com") #... smtplib.SMTP().sendmail(from, to, message.as_string()) The message I receive have its "Return-Path" header set to the same content as the "From" one, even if I explicitly add "Return-Path" header. How can I set "Return-Path" header for a MIME message sent through smtplib's sendmail in Python ? Thanks in advance. Return-Path is set by the SMTP protocol, it's not derived from the