simpledateformat

问题 I am aware that parse() can be used for knowing if the valid date conforms to a specific format. But that throws exception in case of a failure. I wanted just to verify if the date is of a specific format. Especially I need a boolean result from this comparison. How to achieve that in Java? 回答1: I am wondering why nobody here knows following standard validation using ParsePosition . Programming based on exception logic is more or less evil. SimpleDateFormat sdf = new SimpleDateFormat("MM/dd

问题 yy = 15 (year), D = 150 (day of year), HH = 10 (hour) Date myDateWrong = new SimpleDateFormat("yyDHH").parse("1515010"); Date myDateTrue = new SimpleDateFormat("yyD").parse("15150"); myDateTrue is right: 30/05/2015. myDateWrong must be 30/05/2015 10:00:00 but it seem that 28/07/2015 18:00:00. Whats the problem in here? 回答1: I'm going to guess that the wrongDate took a single digit for the month (as you specified) and then took the rest of the digits for the hour (much as it took the rest of

问题 This question already has answers here : Java: Date from unix timestamp (10 answers) Converting Long to Date in Java returns 1970 (11 answers) android timestamp parsing gone wrong(always in 1970) (4 answers) Closed 1 year ago . I want to convert 1574348400 value to date format using code: public class Main { public Main() { long value = 1574348400; String dateString = new SimpleDateFormat("EEEE dd MMMM, yyyy").format(new Date(value)); System.out.println("Formated time: " + dateString); }

问题 I am following the below code to create a Date object on specified dateTime with a specified Timezone. Note: I haven't set any timezone for jvm; But testing this code with different linux server timezones. String date = "20121225 10:00:00"; String timeZoneId = "Asia/Calcutta"; TimeZone timeZone = TimeZone.getTimeZone(timeZoneId); DateFormat dateFormatLocal = new SimpleDateFormat("yyyyMMdd HH:mm:ss z"); //This date object is given time and given timezone java.util.Date parsedDate =

问题 How can I parse a string like this using some DateFormat? Wednesday, 24th July As far as I can tell there's nothing in SimpleDateFormat . 回答1: try this String str = "Wednesday, 24th July"; str = str.replaceAll("(\\d\\d)..", "$1") + " " + Calendar.getInstance().get(Calendar.YEAR); Date date = new SimpleDateFormat("EEEE, dd MMMM yyyy", Locale.US).parse(str); 回答2: Any literals that are not part of the DateFormat parser can be placed between ' . Like 'th', 'T','nd','st' 回答3: Best idea I have on

问题 private void showdataTable_btnActionPerformed(java.awt.event.ActionEvent evt) { try { DateFormat df = new SimpleDateFormat("YYYY-mm-dd'T'HH:MM:ss'Z'"); //set date format String set = df.format(dateChoos1.getDate()); //add value to set BasicDBObject whereQuery = new BasicDBObject(); whereQuery.put("datetimes", set); //where date via set(date) DBCursor cursor = table.find(whereQuery); while (cursor.hasNext()) { DBObject obj = cursor.next(); String ip_address = (String) obj.get("ip_address");

问题 This question already has answers here : “EEE MMM dd HH:mm:ss ZZZ yyyy” date format to java.sql.Date (2 answers) java.util.Date is generating a wrong date? (3 answers) Closed 1 year ago . When we convert the date from yyyy-MM-dd'T'HH:mm:ssXXX to YYMMDD date is invalid. Say.. If the date is 2019-02-27T12:52:58.249Z then the converted date is generated as "190258" 回答1: The issue is because of 'D' in the input format. D represents Day of the year - so when we give 2019-02-27 it adds the 31 days

问题 I have this code I would like to know why it returns correct date Festival f= (Festival) festival.get(0); Date d=f.getSDate(); System.out.println(d.getYear()); System.out.println(d.getMonth()); System.out.println(d.getDate()); SimpleDateFormat df = new SimpleDateFormat("dd/MM/yyyy"); // define your format. String formattedDate = df.format(d); System.out.println("New Date To Show::"+formattedDate); the output is this 2019 2 27 New Date To Show::27/03/3919 回答1: Try to use this : Date date=new

问题 I have found that SimpleDateFormat::parse(String source)'s behavior is (unfortunatelly) defaultly set as lenient: setLenient(true). By default, parsing is lenient: If the input is not in the form used by this object's format method but can still be parsed as a date, then the parse succeeds. If I set the leniency to false , the documentation said that with strict parsing, inputs must match this object's format. I have used paring with SimpleDateFormat without the lenient mode and by mistake, I

问题 This question already has answers here : How to parse dates in multiple formats using SimpleDateFormat (12 answers) Java LocalDateTime.parse with millisecond precision but optional microsecond precision (1 answer) How to check validity of Date String? (4 answers) Closed 5 months ago . There can be two different date time formats as shown below. The second variant has milliseconds time. 2020-09-07T16:15:42Z 2020-09-09T11:41:58.5152Z Currently i am using this way to parse the date. Is there a