similarity

This is an NLP problem and I was wondering how I should proceed. How difficult is the problem? Could I replace the word with synonyms and check that the grammar is correct? Replacing words with synonyms is probably the first thing to try, but be careful not to miss multiple words expressions and idioms. Also, make sure you choose a synonym with the same part of speech. they look for a good solution < ! > they view/stare/... for a good solution they work hard < ! > they job/task/… hard More complicated rephrasing is only possible if you use some level of grammatical analysis. You should at

In the field of Data Mining, is there a specific sub-discipline called 'Similarity'? If yes, what does it deal with. Any examples, links, references will be helpful. Also, being new to the field, I would like the community opinion on how closely related Data Mining and Artificial Intelligence are. Are they synonyms, is one the subset of the other? Thanks in advance for sharing your knowledge. Yin Zhu In the field of Data Mining, is there a specific sub-discipline called 'Similarity'? Yes. There is a specific subfield in data mining and machine learning called metric learning, which aims to

I Have an object with a set of parameters like: var obj = new {Param1 = 100; Param2 = 212; Param3 = 311; param4 = 11; Param5 = 290;} On the other side i have a list of object: var obj1 = new {Param1 = 1221 ; Param2 = 212 ; Param3 = 311 ; param4 = 11 ; Param5 = 290 ; } var obj3 = new {Param1 = 35 ; Param2 = 11 ; Param3 = 319 ; param4 = 211 ; Param5 = 790 ; } var obj4 = new {Param1 = 126 ; Param2 = 218 ; Param3 = 2 ; param4 = 6 ; Param5 = 190 ; } var obj5 = new {Param1 = 213 ; Param2 = 121 ; Param3 = 61 ; param4 = 11 ; Param5 = 29 ; } var obj7 = new {Param1 = 161 ; Param2 = 21 ; Param3 = 71 ;

/** * 相似度 * @param str1 * @param str2 */ public static float levenshtein(String str1,String str2) { int len1 = str1.length(); int len2 = str2.length(); int[][] dif = new int[len1 + 1][len2 + 1]; for (int a = 0; a <= len1; a++) { dif[a][0] = a; } for (int a = 0; a <= len2; a++) { dif[0][a] = a; } int temp; for (int i = 1; i <= len1; i++) { for (int j = 1; j <= len2; j++) { if (str1.charAt(i - 1) == str2.charAt(j - 1)) { temp = 0; } else { temp = 1; } dif[i][j] = min(dif[i - 1][j - 1] + temp, dif[i][j - 1] + 1, dif[i - 1][j] + 1); } } logger.debug("字符串[{}]与[{}]比较",str1,str2); logger.debug("差异步骤：

What's the best approach to comparing two images with php and the Graphic Draw (GD) Library ? This is the scenario: I have an image, and I want to find which image of a given set is the most similar to it. The most similar image is in fact the same image, not pixel perfect match but the same image. I've dramatised the difference between the two images with the number one on the example just to ease the understanding of what I meant. Even though it brought no consistent results, my approach was to reduce the images to 1px using the imagecopyresampled function and see how close the RGB values

I am doing a community website that requires me to calculate the similarity between any two users. Each user is described with the following attributes: age, skin type (oily, dry), hair type (long, short, medium), lifestyle (active outdoor lover, TV junky) and others. Can anyone tell me how to go about this problem or point me to some resources? George Dontas Another way of computing (in R ) all the pairwise dissimilarities (distances) between observations in the data set. The original variables may be of mixed types. The handling of nominal, ordinal, and (a)symmetric binary data is achieved