shuffle

Scramble each digit of the int a and print out the biggest possible integer

给你一囗甜甜゛ 提交于 2021-02-05 12:34:30
问题 I’m stuck here. Do I just keep making new strings and turn them to int or us there a faster better way? public void biggest(int a){ int random; String aS = String.valueOf(a); int ah=9; if (a<10) System.out.println(a); for(int i= 0;i<aS.length();i++){ String firstNum = aS.substring(i,i+1); for (int j = ah; j > Integer.parseInt(firstNum); j--){ System.out.println(ah); } } } ``` 回答1: There's no need to use conversion to String in this case, you can get the digits from the input number by getting

Adding a Simple Button in java, but java is not allowing me to

我怕爱的太早我们不能终老 提交于 2021-02-04 18:08:30
问题 Ok so from my stand point my code is pretty decent enough to get a passing grade but I am having trouble adding a simple refresh/shuffle button. NOT USING the aids of JOptionPane. Eclipse doesnt seem to recognize that I have created the button which doesnt make sense at all for me because its telling me something about a Node which the Button is in fact a node and it is created. But when I go into another class and add another button with the 3 line example it simply works. But when I move it

How do I shuffle a Javascript Array ensuring each Index is in a new position in the new Array?

孤者浪人 提交于 2021-02-04 17:07:40
问题 I have an Array of Objects, like so. var usersGoing = [ { user: 0 }, { user: 1 }, { user: 2 }, { user: 3 }, { user: 4 } ]; I need to shuffle this Array so that no Object remains in the same index as when it was instantiated, like so: [ { user: 3 }, { user: 2 }, { user: 4 }, { user: 0 }, { user: 1 } ] It is IMPERATIVE that the resulting array be sorted in this manner, as each of these user Objects will be assigned to a different user Object. I have tried a few different sorting algorithms,

How do I shuffle a Javascript Array ensuring each Index is in a new position in the new Array?

江枫思渺然 提交于 2021-02-04 17:07:35
问题 I have an Array of Objects, like so. var usersGoing = [ { user: 0 }, { user: 1 }, { user: 2 }, { user: 3 }, { user: 4 } ]; I need to shuffle this Array so that no Object remains in the same index as when it was instantiated, like so: [ { user: 3 }, { user: 2 }, { user: 4 }, { user: 0 }, { user: 1 } ] It is IMPERATIVE that the resulting array be sorted in this manner, as each of these user Objects will be assigned to a different user Object. I have tried a few different sorting algorithms,

How do I shuffle a Javascript Array ensuring each Index is in a new position in the new Array?

蹲街弑〆低调 提交于 2021-02-04 17:07:12
问题 I have an Array of Objects, like so. var usersGoing = [ { user: 0 }, { user: 1 }, { user: 2 }, { user: 3 }, { user: 4 } ]; I need to shuffle this Array so that no Object remains in the same index as when it was instantiated, like so: [ { user: 3 }, { user: 2 }, { user: 4 }, { user: 0 }, { user: 1 } ] It is IMPERATIVE that the resulting array be sorted in this manner, as each of these user Objects will be assigned to a different user Object. I have tried a few different sorting algorithms,

Shuffling a Set of Rows in VBA

若如初见. 提交于 2021-02-04 14:17:48
问题 I am new with VBA so I am having some problems sorting this out. I have a set of rows which I have to record a macro to shuffle ALL rows. That is, there must be no rows left unchanged after I run the macro. And the thing is, this set of values is not a single column. There are several columns which must be taken into account. Shuffling has to be made without changing the entire row, and the shuffle has to occur for all of the columns. A very simple example: Values before shuffle: A 1 B 2 C 3

Efficient sse shuffle mask generation for left-packing byte elements

人盡茶涼 提交于 2021-02-04 06:19:05
问题 What would be an efficient way to optimize the following code with sse ? uint16_t change1= ... ; uint8_t* pSrc = ... ; uint8_t* pDest = ... ; if(change1 & 0x0001) *pDest++ = pSrc[0]; if(change1 & 0x0002) *pDest++ = pSrc[1]; if(change1 & 0x0004) *pDest++ = pSrc[2]; if(change1 & 0x0008) *pDest++ = pSrc[3]; if(change1 & 0x0010) *pDest++ = pSrc[4]; if(change1 & 0x0020) *pDest++ = pSrc[5]; if(change1 & 0x0040) *pDest++ = pSrc[6]; if(change1 & 0x0080) *pDest++ = pSrc[7]; if(change1 & 0x0100) *pDest

How to lightly shuffle a list in python

不打扰是莪最后的温柔 提交于 2021-01-29 16:47:45
问题 I have this issue where I would like to shuffle a list, but only do so slightly. Say, I want only a small number of elements to be moved. Is there a simple way to get this done? Right now the best I can think of is building my own method be hand, but is there some way to use the random library to do this for me? 回答1: to show what some of these solutions are doing I find it helps to run a monte-carlo algorithm many times and look at the distribution first a tidied up version of @meta4's

Java perfect shuffle using arrays

喜欢而已 提交于 2021-01-29 16:25:35
问题 I need to create a program that uses arrays that shuffles a deck back into order. I am supposed to cut the original deck of 52 in half and place the cards in a new pile by alternately placing cards from either pile. The original order 1,2,3,4....49,50,51,52 should come out in the order 1,27,2,28,3...26,52. public static void main(String[] args) { int[] array = new int[52]; int[] top = new int[26]; int[] bottom = new int[26]; for(int i=0; i < 52; i++) { array[i] = i+1; } for(int i = 0; i < 26;

Shuffle list with empty (or None) elements [closed]

时光怂恿深爱的人放手 提交于 2021-01-29 04:52:22
问题 Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . Improve this question I've got some list of lists and it values can be empty [] or NoneType lst = [[[]], [1, None], 2, [[], 3], 4] And I need to randomise them. To get [[1, None], 4, 2, [[], 3], [[]]] , for example. But if I use shuffle(lst) I've got an exception: TypeError: