shapely

In my Anaconda 2.2 64bit with Python 3.4.3 the following line works well: import shapely But the following line: from shapely.geometry.polygon import Polygon returns the following error: OSError: [WinError 126] The specified module could not be found What am I missing? EDIT I tried with iNotebook, idle.exe and Eclipse. They all use Anaconda (the only Python installation on my computer) and they all show the same error. If I type from shapely.geometry import Polygon in Eclipse, then I click on Polygon , then I press F3 , Eclipse is able to open the module C:\Anaconda3\Lib\site-packages\shapely

I'm converting a Shapely MultiPolygon to a PatchCollection, and first colouring each Polygon like so: # ldn_mp is a MultiPolygon cm = plt.get_cmap('RdBu') num_colours = len(ldn_mp) fig = plt.figure() ax = fig.add_subplot(111) minx, miny, maxx, maxy = ldn_mp.bounds w, h = maxx - minx, maxy - miny ax.set_xlim(minx - 0.2 * w, maxx + 0.2 * w) ax.set_ylim(miny - 0.2 * h, maxy + 0.2 * h) ax.set_aspect(1) patches = [] for poly in ldn_mp: colour = cm(1. * len(filter(poly.contains, points)) / num_colours) patches.append(PolygonPatch(poly, fc=colour, ec='#555555', lw=0.2, alpha=1., zorder=1)) pc =

I have a set of LineStrings which are intersected by other LineStrings and I want to split the LineString into separate segments at these intersection points. I have a solution but I don't think it's the best approach. Let's say we are dealing with one LineString: >>> import shapely >>> from shapely.geometry import * >>> import geopandas as gpd >>> >>> MyLine=LineString([(0,0),(5,0),(10,3)]) >>> MyLine <shapely.geometry.linestring.LineString object at 0x1277EEB0> >>> And 2 lines that intersect this LineString: >>> IntersectionLines=gpd.GeoSeries([LineString([(2,1.5),(3,-.5)]), LineString([(5,

If I have a shapely multiline object that contains many lines whose total length each is 50km (when traced from the origin), and I want to interpolate along the multiline every X meters (let's say 100m), returning shapely point objects every 100m, how can I achieve this? Here is what I have so far, but it only returns one distinct point (when I know it should return several thousand, as tested in ArcMap): points = [] for x in range(100,50000,100): x,y = multiline.interpolate(x).xy xy = (x[0],y[0]) points.append(xy) trim = list(set(points)) And here is what trim contains: [(-90.5864707030599,

I have saved string representations of some Shapely Polygons: 'POLYGON ((51.0 3.0, 51.3 3.61, 51.3 3.0, 51.0 3.0))' Is there some fast way of directly converting it back to the Polygon type? Or do I need to manually parse the strings to create Polygon objects? ewcz Shapely can directly parse this : import shapely.wkt P = shapely.wkt.loads('POLYGON ((51.0 3.0, 51.3 3.61, 51.3 3.0, 51.0 3.0))') print(P) 来源： https://stackoverflow.com/questions/51855917/shapely-polygon-from-string