setinterval

JavaScript setTimeout() won't wait to Execute?

淺唱寂寞╮ 提交于 2019-11-26 13:52:20
Consider the following example: <script type="text/javascript"> function alertBox(){ alert('Hello World!'); } function doSomething(){ setInterval(alertBox(), 5000); //This is for generic purposes only }; function myFunction(){ setTimeout(doSomething(),3000); }; myFunction(); </script> What is it that causes this to execute IMMEDIATELY , rather than waiting the 3 seconds set, as well as only executing the alert ONCE , rather than at the scheduled 5 second intervals? Thanks for any help you can provide! Mason alertBox() Doesn't this look like an immediate function call? Try passing the function

How to stop “setInterval” [duplicate]

时间秒杀一切 提交于 2019-11-26 12:16:54
问题 This question already has answers here : Stop setInterval call in JavaScript (12 answers) Closed 4 years ago . How do I stop and start setInterval ? Suppose I have a textarea . I want to stop setInterval on focus and restart setInterval on blur (with jQuery). 回答1: You have to store the timer id of the interval when you start it, you will use this value later to stop it, using the clearInterval function: $(function () { var timerId = 0; $('textarea').focus(function () { timerId = setInterval

Do something every x minutes in Swift

我的梦境 提交于 2019-11-26 11:39:49
How can I run a function every minute? In JavaScript I can do something like setInterval , does something similar exist in Swift? Wanted output: Hello World once a minute... Unheilig var helloWorldTimer = NSTimer.scheduledTimerWithTimeInterval(60.0, target: self, selector: Selector("sayHello"), userInfo: nil, repeats: true) func sayHello() { NSLog("hello World") } Remember to import Foundation. Swift 4: var helloWorldTimer = Timer.scheduledTimer(timeInterval: 60.0, target: self, selector: #selector(ViewController.sayHello), userInfo: nil, repeats: true) @objc func sayHello() { NSLog("hello

Calculating Page Load Time In JavaScript

六眼飞鱼酱① 提交于 2019-11-26 11:31:52
I am trying to make a webpage that, when it starts loading, uses an Interval to start a timer. When the page fully loads, it stops the timer, but 99% of the time i get time measurements of 0.00 or 0.01 even if it takes longer. Occasionally, it says something that makes more sense like .28 or 3.10 at some times. Here is the code if it helps: var hundredthstimer = 0; var secondplace = 0; function addinc(){ hundredthstimer += 1; if (inctimer == 100){ hundredthstimer = 0; secondplace += 1; } } var clockint = setInterval(addinc, 10); function init(){ var bconv1 = document.getElementById(

Will setInterval drift?

一笑奈何 提交于 2019-11-26 11:23:22
This is a pretty simple question really. If I use setInterval(something, 1000) , can I be completely sure that after, say, 31 days it will have triggered "something" exactly 60*60*24*31 times? Or is there any risk for so called drifting? Here's a benchmark you can run in Firefox: var start = +new Date(); var count = 0; setInterval(function () { console.log((new Date() - start) % 1000, ++count, Math.round((new Date() - start)/1000)) }, 1000); First value should be as close to 0 or 1000 as possible (any other value shows how "off the spot" the timing of the trigger was.) Second value is number

Is setInterval CPU intensive?

拥有回忆 提交于 2019-11-26 10:59:57
问题 I read somewhere that setInterval is CPU intensive. I created a script that uses setInterval and monitored the CPU usage but didn\'t notice a change. I want to know if there is something I missed. What the code does is check for changes to the hash in the URL (content after #) every 100 milliseconds and if it has changed, load a page using AJAX. If it has not changed, nothing happens. Would there be any CPU issues with that. 回答1: I don't think setInterval is inherently going to cause you

How to clearInterval with unknown ID?

橙三吉。 提交于 2019-11-26 09:37:15
问题 Say someone (evil) has set us a timer with setInterval , but we don\'t know its ID (we don\'t have the reference to the object, that setInterval is returning, nor its value) (function(){ setInterval(function(){console.log(\'pwned\')}, 10000) })(); Is there a way, how to clear it? Is it possible to acces the timer some other way? Or at least in particular browser/javascript engine? David Flanagan touches similar topic his big JSTDG. setInterval() method, use in malicious code key in the index

Will setInterval cause browsers to hang?

元气小坏坏 提交于 2019-11-26 09:12:20
问题 A couple years ago I was warned against using setInterval for long periods of time as it supposedly would cause the browser to hang if the called function ran longer than the designated interval, and would then not be able to catch up: setInterval( function(){ foo = \'bar_\' + i++; }, 1 ); Now, I\'m aware that adding lots of code in a loop could cause the browser to hang anyway , and that blocking code like alert , prompt , and confirm will stop the code in it\'s tracks, but is there any good

Postponing functions in python

谁说胖子不能爱 提交于 2019-11-26 08:49:49
In JavaScript I am used to being able to call functions to be executed at a later time, like this function foo() { alert('bar'); } setTimeout(foo, 1000); This does not block the execution of other code. I do not know how to achieve something similar in Python. I can use sleep import time def foo(): print('bar') time.sleep(1) foo() but this will block the execution of other code. (Actually in my case blocking Python would not be a problem in itself, but I would not be able to unit test the method.) I know threads are designed for out-of-sync execution, but I was wondering whether something

How to use setInterval function within for loop

痞子三分冷 提交于 2019-11-26 08:13:20
问题 I\'m trying to run multiple timers given a variable list of items. The code looks something like this: var list = Array(...); for(var x in list){ setInterval(function(){ list[x] += 10; console.log(x + \"=>\" + list[x] + \"\\n\"); }, 5 * 1000); } The problem with the above code is that the only value being updated is the item at the end of the list, multiplied by the number of items in the list. Can anyone offer a solution and some explanation so I know why it\'s behaving this way? 回答1: So, a