servlets

问题 I want to stream a video to my IPad via the HTML5 video tag with tapestry5 (5.3.5) on the backend. Usually the serverside framework shouldn't even play a role in this but somehow it does. Anyway, hopefully someone here can help me out. Please keep in mind that my project is very much a prototype and that what I describe is simplified / reduced to the relevant parts. I would very much appreciate it if people didn't respond with the obligatory "you want to do the wrong thing" or security

问题 This question already has answers here : java.lang.NoClassDefFoundError: javax/servlet/http/HttpServletRequest (4 answers) Closed 3 years ago . I get the following error: 06/08/2011 02:56:33 org.apache.catalina.core.StandardWrapperValve invoke SEVERE: Servlet.service() for servlet UploadTheme threw exception java.lang.NoClassDefFoundError: javax/servlet/http/HttpServletRequest at org.apache.commons.fileupload.servlet.ServletRequestContext.getContentType(ServletRequestContext.java:73) at org

问题 This is a quick question but I couldn't find a quick answer. Now I have a servlet BaseServlet, when user request any of the url below: host host/ host/BaseServlet It should always refer to the same servlet and redirect to the homepage. When I set @WebServlet({"/BaseServlet", ""}) Only host/ host/BaseServlet works If I set @WebServlet({"/BaseServlet", "", "/"}) The BaseServlet will be requested constantly in loop ... Why? Edit: BaseServlet does a forward to the index.html hid in WEB-INF folder

问题 I'm getting two very odd errors when opening a project. If I open the landing page and keep refreshing it, the error messages alternate between the two below. Either I get this: org.apache.jasper.JasperException: /WEB-INF/pages/LandingPage.jsp (line: 2, column: 0) The absolute uri: http://www.springframework.org/security/tags cannot be resolved in either web.xml or the jar files deployed with this application Or this: HTTP Status 500 - java.lang.ClassNotFoundException: org.apache.jsp.WEB

问题 How do I compile and run a servlet from the Command Prompt? I got an error when I tried to compile using Apache Tomcat 6.0.16. What is the exact command I should be using? 回答1: How do I compile and run a servlet from the Command Prompt? For the first part of the question, you'll need to put the servlet API on you classpath: javac -cp $TOMCAT_HOME/lib/servlet-api.jar *.java For the second part, what you are trying to achieve is a bit unclear. A Servlet is intended to be packaged in a WAR and

问题 I'm building a java servlet to respond to some HTML form. Here is the simple test form: <FORM action="http://somesite.com/prog/adduser" method="post"> <P> <LABEL for="firstname">First name: </LABEL> <INPUT type="text" id="firstname"><BR> <LABEL for="lastname">Last name: </LABEL> <INPUT type="text" id="lastname"><BR> <LABEL for="email">email: </LABEL> <INPUT type="text" id="email"><BR> <INPUT type="radio" name="sex" value="Male"> Male<BR> <INPUT type="radio" name="sex" value="Female"> Female

问题 I'm building a java servlet to respond to some HTML form. Here is the simple test form: <FORM action="http://somesite.com/prog/adduser" method="post"> <P> <LABEL for="firstname">First name: </LABEL> <INPUT type="text" id="firstname"><BR> <LABEL for="lastname">Last name: </LABEL> <INPUT type="text" id="lastname"><BR> <LABEL for="email">email: </LABEL> <INPUT type="text" id="email"><BR> <INPUT type="radio" name="sex" value="Male"> Male<BR> <INPUT type="radio" name="sex" value="Female"> Female

问题 Is there a way to re-initialize the spring beans dynamically ? On app startup I Initialize spring beans through ContextLoaderListener in web.xml. My use case is that at runtime there could be a case where new property files were loaded into memory(via Apache commons configuration) and I want to reinitialize the beans so that this can take into affect without having to restart. Any pointers on this is appreciated. 回答1: Was able to solve it by having the class implement ApplicationContextAware

问题 Hi I am using basic authentication method for protecting some pages in my Webapp. Which have a specified url pattern as follows: <url-pattern>/Important/*</url-pattern> <auth-method>BASIC</auth-method> Now the problem is if the user logs in the normal way using a login form .The data is posted to my servlet which validates the username and password and then proceeds further. Is there a way that i could setRemoteUser in this servlet , because the authentication input appears again once the

问题 Hi I am using basic authentication method for protecting some pages in my Webapp. Which have a specified url pattern as follows: <url-pattern>/Important/*</url-pattern> <auth-method>BASIC</auth-method> Now the problem is if the user logs in the normal way using a login form .The data is posted to my servlet which validates the username and password and then proceeds further. Is there a way that i could setRemoteUser in this servlet , because the authentication input appears again once the