servlets

问题 I have three simple HttpServlet classes in my JSP project, "LoginServlet", "LogoutServlet" and "ProfileServlet". LoginServlet: log in user by setting "name" attribute to session LogoutServlet: log out user and invalidate session ProfileServlet: display user welcome info if user has logged in The last two servlets are as below that I reckon are problematic. @SuppressWarnings("serial") public class LogoutServlet extends HttpServlet { protected void doGet(HttpServletRequest request,

问题 I have three simple HttpServlet classes in my JSP project, "LoginServlet", "LogoutServlet" and "ProfileServlet". LoginServlet: log in user by setting "name" attribute to session LogoutServlet: log out user and invalidate session ProfileServlet: display user welcome info if user has logged in The last two servlets are as below that I reckon are problematic. @SuppressWarnings("serial") public class LogoutServlet extends HttpServlet { protected void doGet(HttpServletRequest request,

问题 type Exception report message Servlet execution threw an exception description The server encountered an internal error that prevented it from fulfilling this request. exception javax.servlet.ServletException: Servlet execution threw an exception root cause java.lang.NoClassDefFoundError: org/apache/commons/lang/exception/NestableRuntimeException java.lang.ClassLoader.defineClass1(Native Method) java.lang.ClassLoader.defineClassCond(Unknown Source) java.lang.ClassLoader.defineClass(Unknown

问题 type Exception report message Servlet execution threw an exception description The server encountered an internal error that prevented it from fulfilling this request. exception javax.servlet.ServletException: Servlet execution threw an exception root cause java.lang.NoClassDefFoundError: org/apache/commons/lang/exception/NestableRuntimeException java.lang.ClassLoader.defineClass1(Native Method) java.lang.ClassLoader.defineClassCond(Unknown Source) java.lang.ClassLoader.defineClass(Unknown

问题 I want to use 3.0 servlet-api with Jetty 8. Currently 2.4 servlet-api is defined in my web.xml. And in the webdefault.xml 2.5 servlet-api is defined. Someone else set this up so they very well might have done something wrong. Which servlet-api version am I actually using? 2.4 or 2.5? I have 3.0 already in my classpath. What do I need to change in web.xml and/or webdefault.xml to get it working? Thank you in advance. 回答1: You normally don't provide the Servlet API yourself. This is normally to

问题 In Tomcat 7, I want my welcome page (index.html) to load when I access localhost:8080/. Right now, I have to go to the webapp context, localhost:8080/MyWebApp. Is there a folder in Tomcat to place pages that are not part of a webapp? I'm confused how this works... EDIT: I notice that the web.xml for the Server in Eclipse has a servlet called "default" which is mapped to "/"... I wonder if I have to change something here? EDIT2: I found this: http://wiki.apache.org/tomcat/HowTo#How_do_I

问题 In Tomcat 7, I want my welcome page (index.html) to load when I access localhost:8080/. Right now, I have to go to the webapp context, localhost:8080/MyWebApp. Is there a folder in Tomcat to place pages that are not part of a webapp? I'm confused how this works... EDIT: I notice that the web.xml for the Server in Eclipse has a servlet called "default" which is mapped to "/"... I wonder if I have to change something here? EDIT2: I found this: http://wiki.apache.org/tomcat/HowTo#How_do_I

问题 I have 2 webapps running at two contexts: c1, c2 (both immediately after the root). I put a startupListener in c1 to share a variable, and another one in c2 to retrieve it. My startuplistener in c1 is: public void contextInitialized(ServletContextEvent sce) { HashMap <String,Object> database ; //some code to init database ServletContext context = sce.getServletContext().getContext("/c1"); if (context!=null) { context.setAttribute("crossContext", true); context.setAttribute("cache", database);

问题 Apparently brackets are not allowed in URI paths. I'm not sure if this is a Tomcat problem but I'm getting request with paths that contains ] . In otherwords request.getRequestURL() == "http://localhost:8080/a]b" request.getRequestURI() == "/a]b" BTW getRequestURL() and URI are generally escaped ie for http://localhost:8080/a b request.getRequestURL() == "http://localhost:8080/a%20b" So if you try to do: new URI("http://localhost:8080/a]b") new URI(request.getRequestURL()) It will fail with a

问题 i am aiming to create an Excel file for the user to download via apache poi. I have this code in my servlet: protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // create a workbook , worksheet Workbook wb = new HSSFWorkbook(); Sheet sheet = wb.createSheet("MySheet"); CreationHelper createHelper = wb.getCreationHelper(); // Create a row and put some cells in it. Rows are 0 based. Row row = sheet.createRow((short)0); Cell cell =