servlet

Jersey 2.x Security context does not work?

由 匿名 (未验证) 提交于 2019-12-03 02:31:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: While i am trying to create java jersey application authentication roles does not work for me. Java code :- package org.student.resource; import javax.annotation.security.PermitAll; import javax.annotation.security.RolesAllowed; import javax.ws.rs.GET; import javax.ws.rs.POST; import javax.ws.rs.Path; import javax.ws.rs.ext.Provider; @Path("/resource") @PermitAll public class Resource { @GET public String get(){ return "GET"; } @RolesAllowed("admin") @POST public String post(){ return "Post content."; } } Deployment descriptor :- <web-app

jar not loaded. See Servlet Spec 2.3, section 9.7.2. Offending class: javax/servlet/Servlet.class

由 匿名 (未验证) 提交于 2019-12-03 02:30:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am running a Maven project which is also a dynamic web project. I have used all spring libraries in maven. I created web.xml , but when I start my tomcat 7 server I am getting the following message: INFO: validateJarFile(C:\Users\mibvzd0\workspace\.metadata\.plugins\ org.eclipse.wst.server.core\tmp2\wtpwebapps\hapi_hl7\WEB-INF\lib\ servlet-api-2.4.jar) - jar not loaded. See Servlet Spec 2.3, section 9.7.2. Offending class: javax/servlet/Servlet.class I tried deleting the servlet from webapp/lib, but it didn't work. Let me know what should

javax.servlet.ServletException: Wrapper cannot find servlet class

由 匿名 (未验证) 提交于 2019-12-03 02:29:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have made a servlet from "Jasper Reports for Java Develper" (chapter 3) which will show Jasper Report on browser. The servlet look like below: public class FirstReportSendToBrowserServlet extends HttpServlet { //just implement doGet in the block protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // ... } } Then I compiled the servlet and put it into Tomcat. When I fire up tomcat, it works well. But the servlet doesn't work, I get the following exception: javax.servlet

java.lang.NoSuchMethodError: javax.ws.rs.core.Application.getProperties()Ljava/util/Map

由 匿名 (未验证) 提交于 2019-12-03 02:28:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am trying to deploy my first rest application using jersey 2.17 . I am using Maven, GlassFish 3.1.2.2 for deployment. Application runs in eclipse (tomcat), but gives following error when deploying through glassfish admin console. Error occurred during deployment: Exception while loading the app : java.lang.IllegalStateException: ContainerBase.addChild: start: org.apache.catalina.LifecycleException: org.apache.catalina.LifecycleException: java.lang.NoSuchMethodError: javax.ws.rs.core.Application.getProperties()Ljava/util/Map;. Please see

HTTP Status 500 - Servlet.init() for servlet Dispatcher threw exception

由 匿名 (未验证) 提交于 2019-12-03 02:26:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: When i'm trying to run this simple html form: <html> <head> <title>Enter a new Page</title> </head> <body> <div id="editPresPage"> <form action="editPresPage.do" method="post"> <label>Enter Page ID</label><input type="text" name="page_id"/> <label>Enter Header1</label><input type="text" name="h1"/> <label>Enter Header2</label><input type="text" name="h2"/> <label>Enter Header3</label><input type="text" name="h3"/> <label>Enter Header4</label><input type="text" name="h4"/> <label>Enter Page Text</label><input type="text" name="page_text"/>

Spring invokes wrong controller mapping

由 匿名 (未验证) 提交于 2019-12-03 02:26:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm building very basic mvc application with Spring. It has one controller that should invoke validation on request body. The problem is that if I define the mapping in web.xml it stops finding the right controller, but when I modify the servlet application context Spring star making some new bindings on the fly but this time annotation based validation is ignored. How can I controll mappings in web.xml while still invoking annotation based validation? Here are the details: The controller: @Controller @RequestMapping("/api") public class

websockets with Tomcat 8 and Spring 4 ClassCastException before handler is invoked

由 匿名 (未验证) 提交于 2019-12-03 02:20:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am trying to get a simple websocket to work to integrate into my application. However I have not been able to get it to work with the Spring API's, with a ClassCastException somewhere before my handler is invoked trying to convert a Tomcat type to a javax object. If I just use Tomcat directly without Spring (so the javax.websocket objects and annotations) it works perfectly, so I am really not sure why there is an issue with Spring. 08-May-2014 01:10:12.048 SEVERE [http-nio-8084-exec-88] org.apache.catalina.core.StandardWrapperValve.invoke

java.lang.ClassNotFoundException: org.springframework.core.io.Resource

由 匿名 (未验证) 提交于 2019-12-03 02:20:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm using spring 4.0.5, Hibernate 4.3.5 and JSF for web developpement in eclipse, and this is the content of my lib folder : When I run my project I get this error : java.util.concurrent.ExecutionException: org.apache.catalina.LifecycleException: Failed to start component [StandardEngine[Catalina].StandardHost[localhost].StandardContext[/EMaEval]] at java.util.concurrent.FutureTask.report(Unknown Source) at java.util.concurrent.FutureTask.get(Unknown Source) at org.apache.catalina.core.ContainerBase.startInternal(ContainerBase.java:1123) at

URL Pattern for servlet mapping in web.xml

由 匿名 (未验证) 提交于 2019-12-03 02:20:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I need a workaround with this URL mapping in web.xml to create URLs with a letter, followed by a "_" followed by any combination of alphanumeric characters. I want to map a servlet to something like this: /something_* Instead of: /something/* Using different "somethings" for different JSP's. Example: /search_Something-I-searched-for I tried using: <servlet-mapping> <servlet-name>MyServlet</servlet-name> <url-pattern>/something_*</url-pattern> </servlet-mapping> But this doesn't seem to work. This answer tells me I can't do this within web

Jetty throws “Missing content for multipart request” on multipart form request

由 匿名 (未验证) 提交于 2019-12-03 02:20:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm running Jetty 9 (jetty-9.0.5.v20130815) server with servlet-api 3.0.1 (javax.servlet:javax.servlet-api:3.0.1), my servlet is configured to accept multipart requests. web.xml - <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee" xmlns:c="http://java.sun.com/jsp/jstl/core" xmlns:fmt="http://java.sun.com/jsp/jstl/fmt" xmlns:web="http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee"> <servlet> <servlet-name>restapi<
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