servlet

java.lang.NoClassDefFoundError: javax/ws/rs/core/Configuration

匿名 (未验证) 提交于 2019-12-03 08:46:08
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am implementing rest easy web service and i am using jboss 4.0 but i am getting following exception... java.lang.NoClassDefFoundError: javax/ws/rs/core/Configuration my web.xml is <?xml version="1.0" encoding="UTF-8"?> <web-app id="WebApp_ID" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <display-name>RestfulWebService</display-name> <welcome-file-list> <welcome-file>index.html<

URL of a Jersey Application using ResourceConfig without web.xml

匿名 (未验证) 提交于 2019-12-03 08:46:08
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I migrated from web.xml to totally Java configuration using ResourceConfig with Jersey 2.7 and deploying on Tomcat 7. After that I am not able to reach the services anymore by using the same urls that I was using with the web.xml approach. I don't understand how the ResourceConfig is affecting the paths. My previous web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi

Integrating Jetty with RESTEasy

匿名 (未验证) 提交于 2019-12-03 08:39:56
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Any links on how to integrate Jetty and RESTEasy? I am kinda stuck trying to configure RESTEasy with Jetty together....and there seems to be no credible help on the web. public static void main(String[] args) throws Exception { Server server = new Server(8080); WebAppContext context = new WebAppContext(); context.setDescriptor("../WEB-INF/web.xml"); context.setResourceBase("../src/webapp"); context.setContextPath("/"); context.setParentLoaderPriority(true); server.setHandler(context); server.start(); server.join(); } My Web.xml is copied

error: No validator could be found for type: java.time.LocalDate

匿名 (未验证) 提交于 2019-12-03 08:36:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm working on a project that uses bean validation (Hibernate Validator 5.1.3.Final). My bean has a attribute with the @Past annotation. @Past(message = "A data deve estar no passado.") private LocalDate dataAbertura; But, when the validation occurs I get the following exception: 21:46:12,424 ERROR [io.undertow.request] (default task-35) UT005023: Exception handling request to /financeiro/clientes/pessoafisica: javax.servlet.ServletException: javax.validation.UnexpectedTypeException: HV000030: No validator could be found for type: java.time

LifecycleProcessor not initialized - call &#039;refresh&#039; before invoking lifecycle methods via the context

匿名 (未验证) 提交于 2019-12-03 08:35:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am new in spring security I have been done everything in tutorial, but i got this exception. I have a simple Spring Security + JSF web app: web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" version="3.1"> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/security-config.xml</param-value> </context

How to invoke a servlet without mapping in web.xml?

匿名 (未验证) 提交于 2019-12-03 08:35:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: How to invoke a simple servlet using the following URL: http://localhost:8080/servlet/MyServlet I placed it in the folder: tomcat\webapps\ROOT\WEB-INF\classes I've read there is no need to mention the servlet in web.xml. I did the same. Still, I'm unable to invoke it. 回答1: I've read there is no need to mention the servlet in web.xml. You're probably confusing with the legacy Tomcat-builtin InvokerServlet which was present in older versions of Apache Tomcat (and still mentioned in poor and outdated tutorials/books). It indeed allowed to

validateJarFile(servlet-api.jar) - jar not loaded in tomcat using eclipse [duplicate]

匿名 (未验证) 提交于 2019-12-03 08:35:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This question already has an answer here: Error: Servlet Jar not Loaded… Offending class: javax/servlet/Servlet.class 6 answers [Tomcat] validateJarFile(servlet-api.jar) - jar not loaded. Offending class: javax/servlet/Servlet.class org.apache.catalina.loader.WebappClassLoader validateJarFile INFO: validateJarFile(\WEB-INF\lib\servlet-api.jar) - jar not loaded. See Servlet Spec 2.3, section 9.7.2. Offending class: javax/servlet/Servlet.class. I googled for this,I got to know that I am using servlet-api.jar in my project WEB-INF/lib, and also

Sping MVC不使用任何注解处理(jQuery)Ajax请求(基于XML配置)

假装没事ソ 提交于 2019-12-03 08:15:50
1. Spring Spring框架是一个轻量级的解决方案,是一个潜在的一站式商店,用于构建企业就绪的应用程序。 Spring框架是一个Java平台,为开发Java应用程序提供全面的基础架构支持。Spring处理基础结构,因此您可以专注于应用程序。Spring使您能够从“普通的Java对象”(POJO)构建应用程序,并将企业服务非侵入性地应用于POJO。此功能适用于Java SE编程模型以及全部和部分Java EE 。但是,Spring是模块化的,允许您仅使用所需的那些部分,而不必引入其余部分。您可以将IoC容器与顶部的任何Web框架一起使用,但也可以仅使用 Hibernate集成代码或JDBC抽象层。Spring框架支持声明式事务管理,通过RMI或Web服务对逻辑的远程访问以及用于持久化数据的各种选项。它提供了功能全面的MVC框架,并使您能够将AOP透明地集成到软件中。 Spring被设计为非侵入式的,这意味着您的域逻辑代码通常不依赖于框架本身。在您的集成层(例如数据访问层)中,将存在对数据访问技术和Spring库的某些依赖关系。但是,将这些依赖项与其余代码库隔离起来应该很容易。Spring的两大核心特征:IoC(控制反转),AOP(面向切面编程)。IoC作用:把对象的控制权交给容器管理。AOP作用:面向切面编程(比如日志打印),底层使用动态代理实现。

web-简单总结

青春壹個敷衍的年華 提交于 2019-12-03 08:15:12
1. MyBatis 说出你所了解的持久层(ORM)框架 mybatis,hibernate,jpa,jooq object relationship mapping 建立java 对象与关系型数据库之间的映射关系 mybatis 是轻量级的 orm,hibernate 是重量级的(用注解方式建立orm关系,很多sql由框架生成) jpa 是一套接口,hibernate 同时也作为 jpa 2)什么是 MVC,你的项目中哪里体现了 MVC 模型(model) - 数据,domain,java bean 视图(view) - 数据的展现方式,jsp 控制器(controller) - 把模型和视图联系在一起,对应着 servlet 3)梳理一下 MyBatis 的使用步骤 pom.xml 中添加 mybatis 依赖 resources/mybatis-config.xml 配置文件(配置数据库连接和映射关系) 提供 xml mapper 或 接口 映射 (都是通过这些映射管理 sql 语句) 使用 mybatis 的api 执行增删改查 4)列举 MyBatis 中重要的接口,它们分别是干什么的? SqlSessionFactory (接口) - 创建 sqlsession 的 SqlSessionFactoryBuilder (类) - 创建工厂对象 SqlSession (接口

HTTP Status 403 - Access to the requested resource has been denied (CSS blocked?)

匿名 (未验证) 提交于 2019-12-03 07:50:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have been trying to secure my project. I have a log in page that authenticates with an LDAP server and if not right it pulls up an error page etc. I have now just added <auth-constraint> <!-- Currently causing a 403, looks like stoping .css files --> <role-name>*</role-name> </auth-constraint> to my web.xml , to make sure the users are authenticated before they can view any page, however it seems to be blocking my .css file, Ithink as now the log in page does not display any css at all, and is just white basic, and when I press submit I