serializable

How to make a class serializable without Serializable attibute in .net

由 人盡茶涼 提交于 2019-12-10 18:37:33
问题 I have one debugger visualizer for seeing list of class object in the form of data table. But the limitation for the code is that the class should be serializable i.e. should be marked as [Serializable] and if the class is not marked Serializable then the debugger crashes. So, can anybody tell me how to make a class Serializable at run time if the class is not marked Serializable. 回答1: If a class is not marked [Serializable] , you can try serialization using SerializationSurrogate 回答2: You

Getting rid of the comment above Eclipse-generated serialVersionUID

由 限于喜欢 提交于 2019-12-10 12:28:44
问题 This has become a pet peeve of mine. I write a class, and implement Serializible . Then eclipse warns me that I don't have a serialVersionUID , so I select " Add generated serialVersionUID " or " Add default serialVersionUID " and I end up with something like this: /** * */ private static final long serialVersionUID = 4049849541314027178L; Most of the time I don't want to add a comment, so I have to go and delete the comment. I would rather the default be no comment, but I've looked through

undefined method `serializable_hash' for String

由 徘徊边缘 提交于 2019-12-09 08:33:37
问题 i'm trying to_json in the following way @own_events.as_json(:include => {:created_date => {},:attendees => {}, :user => {}, :start_times => {}, :end_times =>{}} ) and created_date is a method like that def created_date self.created_at.strftime('%d/%m/%Y %H:%M:%S') end cause i need the created_at without the TZD .. but there is an error NoMethodError (undefined method `serializable_hash' for "14/04/2014 16:04:07":String): 回答1: :include is used to include associations in the json, usually has

Use parcelable to store item as sharedpreferences?

由 可紊 提交于 2019-12-09 05:04:32
问题 I have a couple objects, Location, in my app stored in an ArrayList and use parcelable to move these between activities. The code for the object looks like this: public class Location implements Parcelable{ private double latitude, longitude; private int sensors = 1; private boolean day; private int cloudiness; /* Måste ha samma ordning som writeToParcel för att kunna återskapa objektet. */ public Location(Parcel in){ this.latitude = in.readDouble(); this.longitude = in.readDouble(); this

Parcelable encounteredClassNotFoundException reading a Serializable object

由 廉价感情. 提交于 2019-12-09 02:17:29
I've implemented a class that implements Serializable object. public class SaveMe implements Serializable { private static final long serialVersionUID = 1L; private String someValue1; private String someValue2; } But whenever I try to use it in a Bundle, I get this exception: Parcelable encounteredClassNotFoundException reading a Serializable object at android.os.Parcel.readSerializable(Parcel.java:1951) at android.os.Parcel.readValue(Parcel.java:1822) at android.os.Parcel.readMapInternal(Parcel.java:2008) at android.os.Bundle.unparcel(Bundle.java:208) at android.os.Bundle.getString(Bundle

DTO implementation of Serializable interface

由 两盒软妹~` 提交于 2019-12-08 06:09:31
问题 Is it mandatory to implement Serialize for Java DTO/Model objects? If so why? If not whats the impact on performance etc? 回答1: A DTO is normally a Data Transfer Object. It doesn't have to use Java Serialization, but if it doesn't it needs to follow some other convention. Its not a matter of performance as if you are using Java Serialization it most likely has to be Serializable (or Externalizable which is still Serializable) 回答2: Not if you're not saving them to a file or sending them across

Parcelable encounteredClassNotFoundException reading a Serializable object

由 ╄→尐↘猪︶ㄣ 提交于 2019-12-08 05:31:50
问题 I've implemented a class that implements Serializable object. public class SaveMe implements Serializable { private static final long serialVersionUID = 1L; private String someValue1; private String someValue2; } But whenever I try to use it in a Bundle, I get this exception: Parcelable encounteredClassNotFoundException reading a Serializable object at android.os.Parcel.readSerializable(Parcel.java:1951) at android.os.Parcel.readValue(Parcel.java:1822) at android.os.Parcel.readMapInternal

Android - Problem with the Serializable interface

由 吃可爱长大的小学妹 提交于 2019-12-07 18:29:58
问题 I have been using the Serializable interface to pass an object from one activity to another. I am using putExtra on the sender side and getSerializable on the receiver side. Everything works fine but I have received (for the first time) the following error report: java.lang.RuntimeException: Parcelable encountered IOException reading a Serializable object I don't understand why this exception has been generated since I am using getSerializable and not getParcelable . I know that I should

Why does the serialVersionUID field exist?

由 梦想的初衷 提交于 2019-12-07 15:10:19
问题 It has baffled me from the launch of the Serializable interface why I have to incorporate this field in all of my classes. I understand that this interface needs a unique identifier to mark the class but why cant they generate this at run-time. For instance they could generate it using an MD5 hash of the fully-qualified class name or a similar methodology used to handle duplicates in their rare occurrence (Which is, I'm sure, what eclipse does when asked to generate the id anyway). So what I

Java serialization library without need of no-arg constructors and implementation of Serializable

由 你。 提交于 2019-12-07 13:18:42
问题 Is there is any way in java-world to serialize without need of no-arg constructors and implementation of Serializable? 回答1: JBoss Serialization is a drop-in replacement for standard java serialization, which does not require you to implement java.io.Serializable . Other than that (and the fact that it's much faster), it's the same as the standard serialization mechanism (it even uses the same ObjectInput and ObjectOutput interfaces. P.S. It has no dependency on other JBoss stuff, it's just
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