[已解决]报错: TypeError: sequence item 0: expected str instance, int found
今天敲小例子,报了错 TypeError: sequence item 0: expected str instance, int found 小例子 list1=[1,'two','three',4] print(' '.join(list1)) 以为会打印 1 two three 4 结果报了错 Traceback (most recent call last): File "<pyshell#27>", line 1, in <module> print(" ".join(list1)) TypeError: sequence item 0: expected str instance, int found 上网查了资料,说list包含数字,不能直接转化成字符串。 解决办法: print(" ".join('%s' %id for id in list1)) 即遍历list的元素,把他转化成字符串。这样就能成功输出1 two three 4结果了。 from: https://blog.csdn.net/laochu250/article/details/67649210 来源: oschina 链接: https://my.oschina.net/u/4396922/blog/4303368