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问题 var result = parseFloat($('.lot2').text()) / parseFloat($('span.Price').text()); $('.result').text(result); }); How can I convert selected values from comma separated values to dot separated values? There is this function str.replace, but I don't know how to put it in the function. 回答1: How can I convert selected values from comma separated values to dot separated values? From that, I take it that the values you get from $('.lot2').text() and $('span.Price').text() will use , as the decimal

问题 This question already has answers here : Split a column of concatenated comma-delimited data and recode output as factors (2 answers) Closed 3 years ago . I have run a survey using Google Forms. I downloaded the response dataset as a spreadsheet, but unfortunately when it comes to multiple choice, multiple anwsers responses, the data looks something like this: Q1 Q2 Q3 1 "A, B ,C" S 2 "C, D" T 1 "A, C, E" U 3 "D" V 2 "B, E" Z I would like to have it in a form similar to the below: Q1 Q2 Q2A

问题 I have this script that was maked by another memeber of stackoverflow but I need to put a comma separator for thousands numbers. How I can do that? (function($) { $.fn.currencyInput = function() { this.each(function() { var wrapper = $("<div class='currency-input' />"); $(this).wrap(wrapper); $(this).before("<span class='currency-symbol'>$</span>"); $(this).change(function() { var min = parseFloat($(this).attr("min")); var max = parseFloat($(this).attr("max")); var value = this.valueAsNumber;

问题 I do a lot of file parsing, which involves parsing data types like decimal. To help make the code more readable, I've been using the following method: public static decimal? ToDecimal(this string data) { decimal result; if (decimal.TryParse(data, NumberStyles.Integer | NumberStyles.AllowDecimalPoint, CultureInfo.InvariantCulture, out result)) return result; return null; } This works fine for decimals which are represented with a full-stop/period as the decimal separator. However, I'd like

问题 I am currently building a word-template for a report. In this report are used red separators as part of the design. The separators are basically just images of red, curved lines. Instead of copy and pasting these separators when needing them, is there a way to store the image somewhere in the document, allowing it to be inserted with just the click of a button in the ribbon? My first bet would be to create a macro somehow that would insert the image, however that would require the image to be

问题 I have this sample code: let locale = Locale(identifier: "en_US") print("Language code: \(locale.languageCode ?? "nil")") print("Region code: \(locale.regionCode ?? "nil")") print("Decimal separator: \(locale.decimalSeparator ?? "nil")") Using en_US in this example (English as language and USA as region) makes the Locale’s decimal separator a . because this is the decimal separator in the specified region "USA": Language code: en Region code: US Decimal separator: . Using Locale(identifier:

问题 I have this sample code: let locale = Locale(identifier: "en_US") print("Language code: \(locale.languageCode ?? "nil")") print("Region code: \(locale.regionCode ?? "nil")") print("Decimal separator: \(locale.decimalSeparator ?? "nil")") Using en_US in this example (English as language and USA as region) makes the Locale’s decimal separator a . because this is the decimal separator in the specified region "USA": Language code: en Region code: US Decimal separator: . Using Locale(identifier:

来源： https://stackoverflow.com/questions/61148561/how-can-i-parse-the-command-line-with-semicolons

问题 I want my tick labels to be formatted according to the German style, with the comma as the decimal separator and the period/point as the thousands separator. The following code works for the decimal separator on the x-axis, but does not do anything for the y-axis. import numpy as np import matplotlib.pyplot as plt import locale # Set to German locale to get comma decimal separater locale.setlocale(locale.LC_NUMERIC, "deu_deu") plt.ticklabel_format(useLocale=True) # evenly sampled time at

问题 So the question is pretty simple and it's in the title. I want to remove the line separator in SwiftUI iOS 14. Previously, I was using UITableView().appearance().separatorStyle = .none and that used to do the job in iOS 13. Now however, it doesn't work. Any update or idea on how to make it work. Thanks:) 回答1: Here is a demo of possible solution. Tested with Xcode 12b. List { ForEach(0..<3) { _ in VStack { Text("Hello, World!").padding(.leading) } .frame(maxWidth: .infinity, maxHeight: