scope

问题 Let's say I have a stored procedure with this in its body: EXEC 'INSERT INTO ' + quotename(@table) ' blah...' SELECT IDENT_CURRENT('' + @table + '') Is IDENT_CURRENT() guaranteed to get the identity of that row INSERTed in the EXEC? IDENT_CURRENT() "returns the last identity value generated for a specific table in any session and any scope", but the scope is different within the EXEC than the stored procedure, right? I want to make sure that if the stored procedure is being called multiple

问题 While looking into ES6 arrow functions' documentation on Mozilla documentation, I got to know that Arrow functions applies all the rules of strict mode, except one as described in the link var f = () => { 'use strict'; return this}; var g = function () { 'use strict'; return this;} console.log(f()); //prints Window console.log(g()); // prints undefined //we can test this in firefox! But, Babel.js is transpiling the arrow function code to ES5 code that returns undefined rather than Window

问题 There are two script files with the following script //parent.lua function scope() local var = "abc" require "child" end //child.lua print(var) This way, child.lua will print a nil value because the scope in parent.lua does not expose its local features to the module. I thought it would, since the require directive is stated within this scope and after the declaration of var. My desire is to practically wholly inject all the lines of the child into the parent. The child script is just

问题 My confusion comes from "C++ Primer 5th edition" section 13.3, page 518. Very careful readers may wonder why the using declaration inside swap does not hide the declarations for the HasPtr version of swap . I tried to read its reference but still did not understand why. Could anyone explain it a little bit please? Thanks. Here is the code sample of the question. Assume class Foo has a member named h , which has type HasPtr . void swap(HasPtr &lhs, HasPtr &rhs) {...} void swap(Foo &lhs, Foo

问题 I have a UI that displays data from a user table like FirstName, LastName, Email,etc. Now i want to create a search bar along with scope buttons that filters data depending on the scope button clicked. I have 2 scope buttons, FirstName and LastName. By default FirstName button is selected. Below is how I add my data to a mutablearray, userData = [[NSMutableArray alloc] init]; for (NSDictionary *tmpDic in response) { [userData addObject: [NSString stringWithFormat: @"%@ %@", [tmpDic

问题 I am trying to represent some data taken from database in a table. I am using jersey as back-end and I have tested it in Postman that it works. The problem is I cannot display my data in the table in front-end, when I use AngularJS. It only shows me a blank table, without data at all. I am pretty new to AngularJS and I really want anyone of you to help me find the problem with my piece of code below. list_main.js angular.module('app', []) .controller('ctrl', function($scope, $http){ $scope

问题 A few months back I read this article about not using ng-controller and adopted the idea behind it: that angular apps should be sets of components working together. The basic idea was that you would use isolate scope directives with their own controllers like this: .directive('myAppContestantList', function() { return { scope: {}, templateUrl: 'my_app_contestant_list.html', replace: true, controller: 'ContestantListCtrl', controllerAs: 'ctrl' }; }) .controller('ContestantListCtrl', function()

问题 I am really struggling in my efforts over the past 2+ years to try to learn how to use pundit. I am trying to write scoped policies, so that different users can receive objects based on the scope class that they fit into. I have asked several questions on the same topic previously, but I'm not getting any closer to a solution. My recent questions are: here, here, here, here, here and here. There are several others but these give the general picture, that I am struggling with the fundamentals

问题 I am new to perl and was confused with perl scoping rules after I wrote below code snippet: #!/usr/bin/perl my $i = 0; foreach $i(5..10){ print $i."\n"; } print "Outside loop i = $i\n"; I expected output to be like : 5 6 7 8 9 10 Outside loop i = 10 But its giving : 5 6 7 8 9 10 Outside loop i = 0 So the variable $i value is not changing after the loop exits. Whats going on in here? 回答1: According to the perldoc information regarding foreach loops: here The foreach loop iterates over a normal

问题 I was trying out some simple JS code. I was aware that we should use var keyword to declare a loop variable inside the loop say for loop to avoid global variable declaration. However I realized that the loop variable exists after the execution of the loop too: var a = [1, 2, 3, 4, 5, 6]; for (var i = 0; i < a.length; i++) document.write(a[i]); //123456 document.write(i); //6 This is not inline (in fact it does not need to be, I know) with how loop variable of for loop in Object Oriented