scope

问题 I'm happy a bit of a variable scoping problem. Maybe I just need more coffee... Here's my (simplified) code - this is in CodeIgniter 2: class Agent extends CI_Controller { public function __construct() { parent::__construct(); $this->load->model('agent_model'); // Get preliminary data that will be often-used in Agent functions $user = $this->my_auth_library->get_user(); $agent = $this->agent_model->get_agent($user->id); } public function index() { $this->template->set('info', $this->agent

问题 marsApp.filter("transformSensorStatus", function($scope) { return function(input, options) { var sensorReading = ( input ? ( input / 1000) : 0); var sensorLowLimit = (options["lowLimit"] ? (options["lowLimit"] / 1000) : 0); var sensorHighLimit = (options["highLimit"] ? (options["highLimit"] / 1000) : 0); var curStat; switch (sensorReading) { case 255: case 254: case 253: curStat = generateStateInnerHtml(sensorReading); break; default: curStat = generateStateInnerHtml(options["sensorStatus"]);

问题 marsApp.filter("transformSensorStatus", function($scope) { return function(input, options) { var sensorReading = ( input ? ( input / 1000) : 0); var sensorLowLimit = (options["lowLimit"] ? (options["lowLimit"] / 1000) : 0); var sensorHighLimit = (options["highLimit"] ? (options["highLimit"] / 1000) : 0); var curStat; switch (sensorReading) { case 255: case 254: case 253: curStat = generateStateInnerHtml(sensorReading); break; default: curStat = generateStateInnerHtml(options["sensorStatus"]);

问题 I expected to be able to use a namespace alias in a class declaration but get a compiler syntax error. struct MyClass { namespace abc = a_big_namespace; void fn() { abc::test(); } }; The only way I can get it to work is to put the alias in every function. void fn() { namespace abc = a_big_namespace; abc::test(); } Additionally I would like to be able to use the alias for function parameters. I haven't found a work-around for that. void fn(abc::testType tt) { abc::test(tt); } Is there a way to

问题 When I compile this snippet with func1 I get an error about referencing output before assignment, which seems reasonable to me: def func1(): output += 1 output = 0 func1() print(output) But when I compile this snippet with func2 I don't get an error, which seems unreasonable to me. def func2(): output.append(1) output = [] func2() print(output) Thoughts? Thanks in advance and sorry if this is a duplicate. I didn't didn't see this particular question addressed in similarly titled posts when

问题 I'm currently learning javascript scope and was just wondering whether it is possible to access a non-global shadowed variable in javascript? i.e. in the example below, the variable a that equal to 10 in the aFunc function var a = 1; function aFunc(){ var a = 10; function innerFunc(){ var a = 100; console.log("innerFunc a = " + a); console.log("is it possible to access outer function's a variable?"); console.log("global a = " + window.a); } innerFunc(); } aFunc(); ps - I understand naming

问题 I'm currently learning javascript scope and was just wondering whether it is possible to access a non-global shadowed variable in javascript? i.e. in the example below, the variable a that equal to 10 in the aFunc function var a = 1; function aFunc(){ var a = 10; function innerFunc(){ var a = 100; console.log("innerFunc a = " + a); console.log("is it possible to access outer function's a variable?"); console.log("global a = " + window.a); } innerFunc(); } aFunc(); ps - I understand naming

问题 I was wondering what exactly happens when I do this: $my_variable = 'foo'; function whatever(){ $my_variable = 'bar'; global $my_variable; } I know that, within the scope of the function $my_variable is now 'foo'. What's going on internally? When I do $my_variable = 'bar'; inside my function, I've created a local variable. When I do global $my_variable; on the next line what exactly happens? The local one is automatically deleted? 回答1: Up until the global is processed, the function will be

问题 I see many Java examples using dependency injection with private fields without a public setter like this: public SomeClass { @Inject private SomeResource resource; } But that is a bad idea when the injection should be performed manually for example in unit tests. There are several possibilities to solve this: add a public setter: setSomeResource(SomeResource r) make the field public make the field package protected I'd like to avoid the setter, since nothing really happens in it. So I'd

问题 I'm working through the 'Ruby On Rails 3 Essential Training' and have received a problem when using name scopes. When finding records and using queries withing the Rails console everything went smoothly until I tried to use a name scope in my subject.rb file. This is my code in the subject.rb file. Class Subject < ActiveRecord::Base scope :visible, where(:visible => true) end I saved the .rb file and restarted my Rails console but when I run from my rails console: subjects = Subject.visible I