scanf

How to fix infinite loops when user enters wrong data type in scanf()?

一笑奈何 提交于 2020-06-17 05:29:08
问题 C beginner here. For the program below, whenever the user inputs a character or a string it enters an infinite loop. How would you fix this while still using scanf? And what would be the better methods of writing this program rather than using scanf? Thanks to those who will answer. #include <stdio.h> #include <ctype.h> int main() { int rounds = 5; do { printf("Preferred number of rounds per game. ENTER NUMBERS ONLY: "); scanf("%d", &rounds); } while(isdigit(rounds) == 0); return 0; } 回答1: I

How to fix infinite loops when user enters wrong data type in scanf()?

浪子不回头ぞ 提交于 2020-06-17 05:29:06
问题 C beginner here. For the program below, whenever the user inputs a character or a string it enters an infinite loop. How would you fix this while still using scanf? And what would be the better methods of writing this program rather than using scanf? Thanks to those who will answer. #include <stdio.h> #include <ctype.h> int main() { int rounds = 5; do { printf("Preferred number of rounds per game. ENTER NUMBERS ONLY: "); scanf("%d", &rounds); } while(isdigit(rounds) == 0); return 0; } 回答1: I

How to fix infinite loops when user enters wrong data type in scanf()?

烂漫一生 提交于 2020-06-17 05:29:06
问题 C beginner here. For the program below, whenever the user inputs a character or a string it enters an infinite loop. How would you fix this while still using scanf? And what would be the better methods of writing this program rather than using scanf? Thanks to those who will answer. #include <stdio.h> #include <ctype.h> int main() { int rounds = 5; do { printf("Preferred number of rounds per game. ENTER NUMBERS ONLY: "); scanf("%d", &rounds); } while(isdigit(rounds) == 0); return 0; } 回答1: I

Using scanf to read in certain amount of characters in C?

倾然丶 夕夏残阳落幕 提交于 2020-06-08 04:30:09
问题 I am having trouble accepting input from a text file. My program is supposed to read in a string specified by the user and the length of that string is determined at runtime. It works fine when the user is running the program (manually inputting the values) but when I run my teacher's text file, it runs into an infinite loop. For this example, it fails when I am taking in 4 characters and his input in his file is "ABCDy". "ABCD" is what I am supposed to be reading in and 'y' is supposed to be

How to see the size of the incoming floating point number?

本秂侑毒 提交于 2020-06-01 07:36:28
问题 The user writes a number to the input, it is stored in a string. How can I check if this number is included in size in the float type or does it need a double ? 回答1: Unless your floating point numbers are huge or extremely small, i.e. out of the range spanning -3.4E38 to 3.4E38, a float 32 will store anything you throw at it in terms of size but not accuracy. As such, the real issue is how many significant digits you need in order to minimize rounding errors. I recommend you to read https:/

Missed scanf and function goes on without it. If I add a space still doesn't work

纵然是瞬间 提交于 2020-06-01 05:09:02
问题 #include <stdio.h> struct mychar { char value; struct mychar *nextPtr; }; typedef struct mychar Mychar; void instructions(); void append(Mychar **, char ); void printlist(Mychar *); int main(){ instructions(); Mychar *startPtr = NULL; unsigned int choice; char newchar; do { scanf("%d",&choice); switch (choice) { case 1: printf("\nWrite the character you want to add."); printf("\n> "); scanf(" %c", &newchar); append(&startPtr, newchar); printlist(startPtr); break; case 2: break; default:

Missed scanf and function goes on without it. If I add a space still doesn't work

那年仲夏 提交于 2020-06-01 05:07:46
问题 #include <stdio.h> struct mychar { char value; struct mychar *nextPtr; }; typedef struct mychar Mychar; void instructions(); void append(Mychar **, char ); void printlist(Mychar *); int main(){ instructions(); Mychar *startPtr = NULL; unsigned int choice; char newchar; do { scanf("%d",&choice); switch (choice) { case 1: printf("\nWrite the character you want to add."); printf("\n> "); scanf(" %c", &newchar); append(&startPtr, newchar); printlist(startPtr); break; case 2: break; default:

Missed scanf and function goes on without it. If I add a space still doesn't work

末鹿安然 提交于 2020-06-01 05:07:14
问题 #include <stdio.h> struct mychar { char value; struct mychar *nextPtr; }; typedef struct mychar Mychar; void instructions(); void append(Mychar **, char ); void printlist(Mychar *); int main(){ instructions(); Mychar *startPtr = NULL; unsigned int choice; char newchar; do { scanf("%d",&choice); switch (choice) { case 1: printf("\nWrite the character you want to add."); printf("\n> "); scanf(" %c", &newchar); append(&startPtr, newchar); printlist(startPtr); break; case 2: break; default:

Reading input from getchar() giving unexpected results

喜夏-厌秋 提交于 2020-05-31 11:45:23
问题 I have a function which reads PIN from terminal and stores PIN and PIN length in the variables passed. On the first call to the function I get expected PIN and PIN length entered. However, during the second call to this function the first character is omitted. /* * Function : read_pin(char *pin,int *pin_len) * Description : Read entered PIN and stores PIN in pin and pin length in pin_len */ int read_pin(unsigned char *pin,unsigned int *pin_len) { int err = EXIT_SUCCESS; char ch; fflush(stdout

Reading input from getchar() giving unexpected results

回眸只為那壹抹淺笑 提交于 2020-05-31 11:44:03
问题 I have a function which reads PIN from terminal and stores PIN and PIN length in the variables passed. On the first call to the function I get expected PIN and PIN length entered. However, during the second call to this function the first character is omitted. /* * Function : read_pin(char *pin,int *pin_len) * Description : Read entered PIN and stores PIN in pin and pin length in pin_len */ int read_pin(unsigned char *pin,unsigned int *pin_len) { int err = EXIT_SUCCESS; char ch; fflush(stdout