sax

How would you read an XML file using sax and convert it to a lxml etree.iterparse element? To provide an overview of the problem, I have built an XML ingestion tool using lxml for an XML feed that will range in the size of 25 - 500MB that needs ingestion on a bi-daily basis, but needs to perform a one time ingestion of a file that is 60 - 100GB's. I had chosen to use lxml based on the specifications that detailed a node would not exceed 4 -8 GB's in size which I thought would allow the node to be read into memory and cleared when finished. An overview if the code is below elements = etree

Streaming xml-parsers like SAX and StAX are faster and more memory efficient than parsers building a tree-structure like DOM-parsers. SAX is a push parser, meaning that it's an instance of the observer pattern (also called listener pattern). SAX was there first, but then came StAX - a pull parser, meaning that it basically works like an iterator. You can find reasons why to prefer StAX over SAX everywhere, but it usually boils down to: "it's easier to use". In the Java tutorial on JAXP StAX is vaguely presented as the middle between DOM and SAX: "it's easier than SAX and more efficient than

Im developing a Java aplication that reads an excel xlsb file using Apache POI, but I got an exception while reading it, my code is as follows: import java.io.IOException; import java.io.InputStream; import org.apache.poi.xssf.eventusermodel.XSSFReader; import org.apache.poi.xssf.model.SharedStringsTable; import org.apache.poi.xssf.usermodel.XSSFRichTextString; import org.apache.poi.openxml4j.exceptions.InvalidFormatException; import org.apache.poi.openxml4j.exceptions.OpenXML4JException; import org.apache.poi.openxml4j.opc.Package; import org.xml.sax.Attributes; import org.xml.sax

I've got a custom contentHandler (called XMLHandler), I've been to a lot of sites via Google and StackOverflow that detail how to set that up. What I do not understand is how to USE it. Xml.parse(...,...) returns nothing, because it is a void method. How do I access my parsed XML data? I realize this question is probably trivial, but I've been searching for (literally) hours and have found no solution. Please help. String result = fetchData(doesntmatter); Xml.parse(result, new XMLHandler()); Here is one example i hope it will be usefull to understand "SAXParser" package test.example; import

somewhat related to: libxml2 from java yes, this question is rather long-winded - sorry. I kept is as dense as I felt possible. I bolded the questions to make it easier to peek at before reading the whole thing. Why is sax parsing faster than dom parsing? The only thing I can come up with is that w/ sax you're probably ignoring the majority of the incoming data, and thus not wasting time processing parts of the xml you don't care about. IOW - after parsing w/ SAX, you can't recreate the original input. If you wrote your SAX parser so that it accounted for each and every xml node (and could

I'm trying to migrate one of my classes which uses DOM parsing with lots of XPath expressions to SAX parsing. DOM Parsing was good for me but some of the files i try to parse are too big and they cause server timeouts. I want to reuse the XPath with the SAX parsing but i'm not sure if it is possible and if not possible could you please help me because i have no idea how the following code will be when i use only SAX : Document doc = bpsXml.getDocument(); String supplierName = BPSXMLUtils.getXpathString(doc, "/Invoice/InvoiceHeader/Party[@stdValue='SU']/Name/Name1"); String language =