sax

问题 I have been trying to use the SAX parser on Android to display some xml that is the result of a query to a DB. I get the right answer from the DB, but when I want to parse the xml and dump the content into a Text view, the ExampleHandler (ParsedExampleDataSet) returns an Object with an empty string. I have been trying to trace where the problem is but it eludes me. So far I know the data is parsed correctly in the characters method, I managed to print the content out to the Log file, but I

问题 I'm using the Android SAX parser to search for entries in a rather large (6MB) XML file. I'm basically using a derivative of the code shown in listing 8 here. The question I have is how do I stop parsing once my match has been found? The code shown continues parsing through the end of the file but I want to stop before then. Is this possible or do I need to use something other than SAX (e.g. XmlPullParser?) 回答1: Generate an ArithmeticException and catch it ! if (condition) { int a=1; a/=0; }

问题 I have a timer which checks for new XML files on the file system and parses them. XML files can get large(5GB), so i am using sax parser. To increase the productivity, i wrote a multithreading programm with executer service. XML files can belong to different sources. For each source is being a thread created and in this thread XML files parsed which belong to the source. In every thread a new SaxParserFactory and for every XML file a new SaxParser created. The problem is that different parser

问题 I must parse an XML from URL in Java with SAX parser. I didn't find an example on the internet about this topic. All of them are reading an XML from local. Is there an example that xml has nested tags and parsing from url in Java? 回答1: Refer this example java snippet String webServiceURL="web service url or document url here"; URL geoLocationDetailXMLURL = new URL(webServiceURL); URLConnection geoLocationDetailXMLURLConnection = geoLocationDetailXMLURL.openConnection();

问题 I'm trying to use XML::SAX to modify parts of an XHTML document, however all my attempts have failed. Here is what I'm trying to do: #!/usr/bin/perl package MyHandler; use strict; use warnings; use base qw(XML::SAX::Base); use Data::Dumper; sub start_element { my $self = shift; my $data = shift; if( $data->{LocalName} eq 'span') { $data->{LocalName} = 'naps'; } $self->SUPER::start_element($data); # GOOD (and easy) ! #print Dumper($data); } 1; #============================ #Main programm #====

问题 I am trying to parse an xml using digester . My XML <root> <Employee> <Id>1</Id> <FirstName>Charles</FirstName> <LastName>Madigen</LastName> <Location>Louisiana</Location> <Skill>Accountant</Skill> </Employee> </root> My Employee class public class Employee { private int empId; private String fName; private String lName; private String location; private String skill; public Employee(int empId, String fName, String lName, String location, String skill) { this.empId = empId; this.fName = fName;

问题 I would like to use SAX/DOM parser in this below code to read a xml in HttpWebResponse instead of using XmlSerializer. Please help me how to do it? HttpWebRequest request = WebRequest.Create(requestURI) as HttpWebRequest; request.Credentials = _cred; WebResponse response = request.GetResponse(); XmlSerializer ser = new XmlSerializer(typeof(MyXMLClass)); myXMLClassObj = ser.Deserialize(response.GetResponseStream()) as MyXMLClass; 回答1: HttpWebRequest request = WebRequest.Create(requestURI) as

问题 I'm trying to get Spring data JPA to work. I'm using the version 1.8.2.RELEASE . <!-- Spring Data JPA --> <dependency> <groupId>org.springframework.data</groupId> <artifactId>spring-data-jpa</artifactId> <version>1.8.2.RELEASE</version> </dependency> I'm also added Spring dependencies using version 4.1.9.RELEASE : spring-core spring-beans spring-context spring-context-support spring-tx spring-jdbc spring-orm Finally, I added Hibernate dependencies using version 5.0.5.Final : hibernate-core

问题 I have a couple of gigantic XML files (10GB-40GB) that have a very simple structure: just a single root node containing multiple row nodes. I'm trying to parse them using SAX in Python, but the extra processing I have to do for each row means that the 40GB file takes an entire day to complete. To speed things up, I'd like to use all my cores simultaneously. Unfortunately, it seems that the SAX parser can't deal with "malformed" chunks of XML, which is what you get when you seek to an

问题 Need help on how to add an xml node at a desired position in the xml. For Example: Original xml <Errors xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="errors.xsd"> <Service Name="SYSTEM" Range="0-0299"> <Type Name="System"> <Error Name="ERROR1"> <Code>0001</Code> <Description>error1</Description> </Error> <Error Name="ERROR_OTHER"> <Code>0</Code> <Description>error error</Description> </Error> <Error Name="ERROR2"> <Code>0002</Code> <Description>error2<