runtime

Android runtime permission for system apps

匿名 (未验证) 提交于 2019-12-03 01:47:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Question about Android runtime permissions. AFAIK, android grant dangerous permission at runtime. I reset my phone, then adb pull /data/system/users/0/runtime-permissions.xml, I found android.ui.system has already granted many dangerous permissions. can anybody tell me how it does? 回答1: The mechanism to insert Runtime permission into the /data/system/users/0/runtime-permissions.xml file by user confirmation dialog for Dangerous permission level, is for third party applications, and This is not relevant for built-in applications. For built-in

Runtime Error NZEC

匿名 (未验证) 提交于 2019-12-03 01:44:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: import java.util.Scanner; public class FindSmallestPalindrome { public static void main(String args[]){ Scanner s = new Scanner(System.in); //System.out.println("Enter the number"); int testCase = s.nextInt(),i=1; long st; StringBuilder str = new StringBuilder(); while(i <= testCase){ st = s.nextLong(); st +=1; while(st <= 1000000000){ str.append(st); //System.out.println("str="+str); if(str.reverse().toString().equals(st+"")){ //System.out.println("str inside="+str); System.out.println(st); break; } str.delete(0,str.length()); st++; /

Apache flink - Mini cluster - Windowing operator execution problem

匿名 (未验证) 提交于 2019-12-03 01:41:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This turned out to be the problem for below question Apache flink - job simple windowing problem - java.lang.RuntimeException: segment has been freed - Mini Cluster problem So I wanted to ask by giving specific detail. Adding a very simple windowing operator to job causes below error in MINI CLUSTER ENVIRONMENT: Caused by: java.lang.RuntimeException: segment has been freed at org.apache.flink.streaming.runtime.io.RecordWriterOutput.emitWatermark(RecordWriterOutput.java:123) at org.apache.flink.streaming.runtime.tasks.OperatorChain

Error: ConnectFailure (Connection refused)

匿名 (未验证) 提交于 2019-12-03 01:40:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have the xamarin.forms application for which i am trying to connect localhost from PC to Iphone simulator in mac,Iam using the Ip address for connecting, private string Uri = "http://192.168.0.16:62271/";//Windows Ip address:localhost port number private string GetDishesUrl = "api/DishDetails/GetDishDetails?id=5"; try{ var httpClient = new HttpClient(); httpClient.BaseAddress = new Uri(Uri); var response = await httpClient.GetAsync(new Uri(Uri + GetDishesUrl)); var stringAsync = await response.Content.ReadAsStringAsync(); if (response

Check GCC version in runtime

匿名 (未验证) 提交于 2019-12-03 01:38:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I need to find out the available (installed in the system) GCC version (Major and minor) inside the execution of a c program (in runtime). Meaning, programatically extract the version of the available gcc (same as if I was in a shell and typed gcc --version, but in a c program). The __GNUC__ and __GNUC_MINOR__ are only useful in compile time and I've found the gnu_get_libc_version() function from gnu/libc_version.h , but it only gets me the libc version and I need the GCC version. If there is something similar for GCC it would be great... I

java Runtime process - check if waiting for input

匿名 (未验证) 提交于 2019-12-03 01:38:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I wish to create a process using java's runtime: for example. Process proc = Runtime.getRuntime().exec("cmd"); Then, I want to somehow wait for the process until it is in 'ready for input' state, which will verify it has finished all of its work. Anyway on how to do it? One thing that is possible is echoing "---finished---" and checking if this line was written using the stdin of the process. But I dislike the idea. Is there any better (more formal) approach to do this? By the way, I need this effect as I descriobed it. I want to wait before

Airflow dynamic tasks at runtime

匿名 (未验证) 提交于 2019-12-03 01:38:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Other questions about 'dynamic tasks' seem to address dynamic construction of a DAG at schedule or design time. I'm interested in dynamically adding tasks to a DAG during execution. from airflow import DAG from airflow.operators.dummy_operator import DummyOperator from airflow.operators.python_operator import PythonOperator from datetime import datetime dag = DAG('test_dag', description='a test', schedule_interval='0 0 * * *', start_date=datetime(2018, 1, 1), catchup=False) def make_tasks(): du1 = DummyOperator(task_id='dummy1', dag=dag) du2

“why the runtime exception is un-recoverable?”

匿名 (未验证) 提交于 2019-12-03 01:36:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: In the Java documentation, I saw the definition " If a client can reasonably be expected to recover from an exception, make it a checked exception. If a client cannot do anything to recover from the exception, make it an unchecked exception " Unchecked Exceptions ― The Controversy I don't understand clearly the concept "recover from", what does it means? And, based on this definition, why NumberFormatException cannot recover? I think when this exception occurs, we can ask the user provide the other valid string to continue the

How to reuse tensorflow after cudaDeviceReset() in C++?

匿名 (未验证) 提交于 2019-12-03 01:36:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am working on a large cuda app in C++ that runs various models and needs to completely release all GPU memory or the other operations will fail. I am able to release all the memory after closing all tf sessions and running cudaDeviceReset(). But afterwards I cannot run any new tensorflow code and session creation will return nullptrs. I tried cudaDeviceSynchronize() before and after thinking that would help but no luck. I figured the call to InitMain would re-initialize tensorflow but it seems not to if I call again after the reset. Is

Runtime complexity of getting the length of a string in different representations

匿名 (未验证) 提交于 2019-12-03 01:36:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: In Swift 2, given a string s , what's the runtime complexity of these statements: s.characters.count s.endIndex s.utf8.count s.utf16.count s.unicodeScalars.count Also, if I know a string contains alphabets only, what's the most efficient way of getting the n-th character? 回答1: OK, I'm trying to answer my own question. Feel free to correct me if I'm wrong. s.characters.count // O(N) s.endIndex // O(1) s.utf8.count // O(N) s.utf16.count // O(N) s.unicodeScalars.count // O(N) Apple's documentation on CollectionType.count says "Complexity: O(1)