rotation

问题 I have an issue, in my leaflet map I've created a triangle from polygon: var polygon = L.polygon([ [parseFloat(decimal_lat),parseFloat(decimal_lon)], [parseFloat(decimal_lat) + 1, parseFloat(decimal_lon) - 1], [parseFloat(decimal_lat) + 1, parseFloat(decimal_lon) + 1] ], { color:'green' }); polygon.addTo(map); and I want to rotate this polygon around Point[decimal_lon, decimal_lat] . But I'm not able to solve it.. I've created DEMO, where I'm rotating polynom the same I want to rotate my

问题 I am working on a game that rotates an object on the z axis. I need to limit the total rotation to 80 degrees. I tried the following code, but it doesn't work. minAngle = -40.0f and maxAngle = 40.0f Vector3 pos = transform.position; pos.z = Mathf.Clamp(pos.z, minAngle, maxAngle); transform.position = pos; 回答1: The code you posted clamps the z position. What you want is to use transform.rotation void ClampRotation(float minAngle, float maxAngle, float clampAroundAngle = 0) { //clampAroundAngle

问题 I am working on a game that rotates an object on the z axis. I need to limit the total rotation to 80 degrees. I tried the following code, but it doesn't work. minAngle = -40.0f and maxAngle = 40.0f Vector3 pos = transform.position; pos.z = Mathf.Clamp(pos.z, minAngle, maxAngle); transform.position = pos; 回答1: The code you posted clamps the z position. What you want is to use transform.rotation void ClampRotation(float minAngle, float maxAngle, float clampAroundAngle = 0) { //clampAroundAngle

问题 I have a table that looks something like this: <table><tbody> <tr><td>a</td><td>1</td></tr> <tr><td>b</td><td>2</td></tr> <tr><td>c</td><td>3</td></tr> <tr><td>d</td><td>4</td></tr> <tr><td>e</td><td>5</td></tr> <tr><td>f</td><td>6</td></tr> <tr><td>g</td><td>7</td></tr> </tbody></table> I need it to get to something like this: <table><tbody> <tr> <td>a</td><td>b</td><td>c</td><td>d</td> <td>e</td><td>f</td><td>g</td> </tr> <tr> <td>1</td><td>2</td><td>3</td><td>4</td> <td>5</td><td>6</td><td

问题 I have a menu item with an icon (imagine for example a clock with a single lancet), I would like to make its icon rotate indefinitely. How could I manage this effect? Thank you. 回答1: Add a file res/layout/iv_refresh.xml (replace ic_launcher with your custom icon): <?xml version="1.0" encoding="utf-8"?> <ImageView xmlns:android="http://schemas.android.com/apk/res/android" style="@android:style/Widget.ActionButton" android:layout_width="wrap_content" android:layout_height="wrap_content" android

问题 I'm trying to upload a base64 encoded image and save after decoding it. Image is getting uploaded and saved, and I can access it using a URL and everything..but the image gets rotated by 90 degrees anti-clockwise and I have no idea WHY!! The place where I get the encoded data is fine, as putting it in <img /> works fine! function saveImageData($base64Data) { $base64_decoded = base64_decode($base64Data); $im = imagecreatefromstring($base64_decoded); if ($im !== false) { $imagepath = '/public

问题 I have come across some very unexpected (and incredibly frustrating) functionality while trying to restore the state of a list of CheckBox es after a screen rotation. I figured I first would try to give a textual explanation without the code, in case someone is able to determine a solution without all the gory details. If anyone needs more details I can post the code. I have a scrolling list of complex View s that contain CheckBox es. I have been unsuccessful in restoring the state of these

问题 I am trying to use Python to resize picture. With my camera, files are all written is landscape way. The exif information handle a tag to ask the image viewer to rotate in a way or another. Since most of the browser doesn't understand this information, I want to rotate the image using this EXIF information and keeping every other EXIF information. Do you know how I can do that using Python ? Reading the EXIF.py source code, I found something like that : 0x0112: ('Orientation', {1: 'Horizontal

问题 I am trying to use Python to resize picture. With my camera, files are all written is landscape way. The exif information handle a tag to ask the image viewer to rotate in a way or another. Since most of the browser doesn't understand this information, I want to rotate the image using this EXIF information and keeping every other EXIF information. Do you know how I can do that using Python ? Reading the EXIF.py source code, I found something like that : 0x0112: ('Orientation', {1: 'Horizontal

问题 I want my circle image (ImageView) to rotate as the user touch and drag it. If the user drags it to the right, it should spin right and vice versa. Like when you spin a DJ disc, if you know what i mean. I've played around a bit with OnTouchListener and RotateAnimation but i'm getting nowhere. Any ideas? 回答1: Let's assume you have ImageView mCircle which you want to rotate. You have to use RotateAnimation to rotate it. In OnTouch method determine the angle where user's finger is. For example,