reverse

ReverseParentheses - Codefights

江枫思渺然 提交于 2019-11-30 05:30:51
I'm having a really tough time solving this problem with JavaScript You are given a string s that consists of English letters, punctuation marks, whitespace characters and brackets. It is guaranteed that the brackets in s form a regular bracket sequence. Your task is to reverse the strings in each pair of matching parenthesis, starting from the innermost one. Example For string "s = a(bc)de" the output should be reverseParentheses(s) = "acbde". Input/Output [time limit] 4000ms (js) [input] string s A string consisting of English letters, punctuation marks, whitespace characters and brackets.

How does this code work to reverse bits in number?

只愿长相守 提交于 2019-11-30 05:18:45
unsigned reverse_bits(unsigned input) { //works on 32-bit machine input = (input & 0x55555555) << 1 | (input & 0xAAAAAAAA) >> 1; input = (input & 0x33333333) << 2 | (input & 0xCCCCCCCC) >> 2; input = (input & 0x0F0F0F0F) << 4 | (input & 0xF0F0F0F0) >> 4; input = (input & 0x00FF00FF) << 8 | (input & 0xFF00FF00) >> 8; input = (input & 0x0000FFFF) << 16 | (input & 0xFFFF0000) >> 16; return input; } how does this work? Suppose I have a hand of 8 cards: 7 8 9 10 J Q K A How can we reverse them? One way is to swap adjacent pairs: 8 7 10 9 Q J A K Then, swap adjacent groups of 2: exchange 8 7 and 10

How to find the main function's entry point of elf executable file without any symbolic information?

对着背影说爱祢 提交于 2019-11-30 05:08:35
I developed a small cpp program on platform of Ubuntu-Linux 11.10. Now I want to reverse engineer it. I am beginner. I use such tools: GDB 7.0, hte editor, hexeditor . For the first time I made it pretty easy. With help of symbolic information I founded the address of main function and made everything I needed. Then I striped ( --strip-all ) executable elf-file and I have some problems. I know that main function starts from 0x8960 in this program. But I haven't any idea how should I find this point without this knowledge. I tried debug my program step by step with gdb but it goes into __libc

reversing z-index based from page render order

冷暖自知 提交于 2019-11-30 04:53:58
Example Markup: <div class="wrapper"> <h2>Trigger</h2> <div>This is some content</div> </div> <div class="wrapper"> <h2>Trigger</h2> <div>This is some content</div> </div> <div class="wrapper"> <h2>Trigger</h2> <div>This is some content</div> </div> Example CSS: .wrapper {z-index: 1} .wrapper div {display: none; position: absolute;} Via javascript (jQuery) I'm attaching a click event to each h2 that will then switch the content div to display: block. The intent is that these are expandable blocks of content that will overlap anything else on the page. The catch is that I'd like the first one

Python Reverse Find in String

流过昼夜 提交于 2019-11-30 04:19:55
I have a string and an arbitrary index into the string. I want find the first occurrence of a substring before the index. An example: I want to find the index of the 2nd I by using the index and str.rfind() s = "Hello, I am 12! I like plankton but I don't like Baseball." index = 34 #points to the 't' in 'but' index_of_2nd_I = s.rfind('I', index) #returns = 36 and not 16 Now I would expect rfind() to return the index of the 2nd I (16) but it returns 36. after looking it up in the docs I found out rfind does not stand for reverse find. I'm totally new to Python so is there a built in solution to

android - reverse the order of an array

99封情书 提交于 2019-11-30 04:10:35
I have an array of objects. Is it possible to make a new array that is a copy of this array, but in reverse order? I was looking for something like this. // my array ArrayList<Element> mElements = new ArrayList<Element>(); // new array ArrayList<Element> tempElements = mElements; tempElements.reverse(); // something to reverse the order of the array You can do this in two steps: ArrayList<Element> tempElements = new ArrayList<Element>(mElements); Collections.reverse(tempElements); Simple approach without implementing anything. ArrayList<YourObject> oldlist = new ArrayList<YourObject>();

c# Trying to reverse a list

半世苍凉 提交于 2019-11-30 00:12:50
public class CategoryNavItem { public int ID { get; set; } public string Name { get; set; } public string Icon { get; set; } public CategoryNavItem(int CatID, string CatName, string CatIcon) { ID = CatID; Name = CatName; Icon = CatIcon; } } public static List<Lite.CategoryNavItem> getMenuNav(int CatID) { List<Lite.CategoryNavItem> NavItems = new List<Lite.CategoryNavItem>(); -- Snipped code -- return NavItems.Reverse(); } The reverse doesn't work: Error 3 Cannot implicitly convert type 'void' to 'System.Collections.Generic.List<Lite.CategoryNavItem>' Any ideas why this might be? Try: NavItems

Django reverse() for JavaScript

偶尔善良 提交于 2019-11-29 23:04:08
In my project I have a lot of Ajax methods, with external client-side scripts (I don't want to include JavaScript into templates!) and changing URLs is kind of pain for me because I need to change URLs in my Ajax calls manually. Is there is some way to emulate the behavior of {% url %} templatetag in JavaScript? For example, print urlpatterns starting with ^ajax and later in scripts replace patterns with their actual values? That's what on my mind, and my question is - are there any common practices to do things like that? Maybe some reusable applications? Also I will be happy to read any

Python: How exactly can you take a string, split it, reverse it and join it back together again?

坚强是说给别人听的谎言 提交于 2019-11-29 22:57:35
How exactly can you take a string, split it, reverse it and join it back together again without the brackets, commas, etc. using python? >>> tmp = "a,b,cde" >>> tmp2 = tmp.split(',') >>> tmp2.reverse() >>> "".join(tmp2) 'cdeba' or simpler: >>> tmp = "a,b,cde" >>> ''.join(tmp.split(',')[::-1]) 'cdeba' The important parts here are the split function and the join function . To reverse the list you can use reverse() , which reverses the list in place or the slicing syntax [::-1] which returns a new, reversed list. Do you mean like this? import string astr='a(b[c])d' deleter=string.maketrans('()[]'

What's “better” the reverse method or the reversed built-in function?

风格不统一 提交于 2019-11-29 17:14:15
问题 What is typically regarded as more Pythonic/better/faster to use, the reverse method or the reversed built-in function? Both in action: _list = list(xrange(4)) print _list rlist = list(reversed(_list)) print rlist _list.reverse() print _list 回答1: Depends on whether you want to reverse the list in-place (i.e. change the list) or not. No other real difference. Often using reversed leads to nicer code. 回答2: foo.reverse() actually reverses the elements in the container. reversed() doesn't