restart

How do I start again an external JavaFX program? Launch prevents this, even if the JavaFX program ended with Platform.Exit

由 坚强是说给别人听的谎言 提交于 2020-01-14 22:54:21
问题 From my MainProject (Java 8) i starts a JavaFX 8 Class. public void startFX() { if (isRestartPrintModul() == true) { fxMain.init(); } else { setRestartPrintModul(true); fxMain.main(new String[] {"ohne"}); } } This is my FXMain: package quality; import javafx.application.Application; import javafx.application.Platform; import javafx.event.ActionEvent; import javafx.scene.Scene; import javafx.scene.control.Button; import javafx.scene.layout.StackPane; import javafx.stage.Modality; import javafx

How do I start again an external JavaFX program? Launch prevents this, even if the JavaFX program ended with Platform.Exit

由 冷暖自知 提交于 2020-01-14 22:54:02
问题 From my MainProject (Java 8) i starts a JavaFX 8 Class. public void startFX() { if (isRestartPrintModul() == true) { fxMain.init(); } else { setRestartPrintModul(true); fxMain.main(new String[] {"ohne"}); } } This is my FXMain: package quality; import javafx.application.Application; import javafx.application.Platform; import javafx.event.ActionEvent; import javafx.scene.Scene; import javafx.scene.control.Button; import javafx.scene.layout.StackPane; import javafx.stage.Modality; import javafx

Bluecove : restart bluetooth stack programmatically

由 时光怂恿深爱的人放手 提交于 2020-01-14 19:30:50
问题 I'm trying to close bluetooth service, but Bluecove has bug on Connection close method (https://code.google.com/p/bluecove/issues/detail?id=90) and I am trying to do some workaround to restart service. I think restarting bluetooth stack will solve my problem. Can I do it programmatically? I'am using microsoft bluetooth stack. 回答1: Problem solved in this way. I restart the application, but firstly shut down bluecove manually. BlueCoveImpl.shutdown(); If I only restart application, bluecove

how to restart an application in qt?

由 做~自己de王妃 提交于 2020-01-14 09:42:07
问题 I do this works for restarting my game but program has error .I want to show a QDialog when user losses .In this QDilag i put two pushbutton for retry and exit.also i have a QDialog for beginning of game.Where is my mistake? (I read similar questions and do according these but yet i have problem) extern int const EXIT_CODE_REBOOT; mydialog_end::mydialog_end(QWidget *parent) : QDialog(parent { retry=new QPushButton(this); exit=new QPushButton(this); retry->setText("RETRY"); exit->setText("EXIT

how to restart an application in qt?

由 这一生的挚爱 提交于 2020-01-14 09:41:34
问题 I do this works for restarting my game but program has error .I want to show a QDialog when user losses .In this QDilag i put two pushbutton for retry and exit.also i have a QDialog for beginning of game.Where is my mistake? (I read similar questions and do according these but yet i have problem) extern int const EXIT_CODE_REBOOT; mydialog_end::mydialog_end(QWidget *parent) : QDialog(parent { retry=new QPushButton(this); exit=new QPushButton(this); retry->setText("RETRY"); exit->setText("EXIT

shell脚本之while for if 语句和编写计划任务

由 陌路散爱 提交于 2020-01-14 02:44:08
关于while循环： while do done 例如 1、关于内存的实时操作： （1） 、vim a.sh （2）、输入以下while循环 （3）、./a.sh执行脚本 2、自加一的操作： （1）、vim b.sh （2）、先赋值xyy=1，再输入当xyy<=10时，则输出xyy的值，并且执行加1的命令（即xyy++），直至等于10为止，最后输出每次的结果 （3）、./b.sh执行脚本 3、关于登录循环的操作： （1）、vim 2.sh （2）、请输入用户名和密码，如果匹配账号密码正确的话，则输出登录成功，如果账号密码不正确的话，则输出，账号和密码是错误的 （3）、./2.sh执行脚本 关于for语句： for i in { } do done 例如： 1、从1-100里取值，并将取到的值挨个输出： （1）、vim 3.sh （2）、in表示从{ }里面取值给i （3）、./3.sh执行脚本 2、可以ping IP地址，查看有哪些可以使用： （1）、vim 3.sh （2）、in表示从{ }里面取值给i （3）、./3.sh执行脚本 关于if语句 例如： 启动nginx服务 （1）、vim 4.sh （2）、chmod +x 4.sh（给4.sh可执行的权限） （3）、./4.sh执行脚本 关于编写任务计划：crontab命令编写 crontab命令编写计划任务 语　　法

CentOS6.5 下Nginx设置开机自启

由 点点圈 提交于 2020-01-13 04:51:16
1：在/etc/init.d/目录下创建 nginx 文件： vim /etc/init.d/nginx 2：进入后添加如下内容： #!/bin/sh # # nginx - this script starts and stops the nginx daemin # # chkconfig: - 85 15 # description: Nginx is an HTTP(S) server, HTTP(S) reverse # proxy and IMAP/POP3 proxy server # processname: nginx # config: /usr/local/nginx/conf/nginx.conf # pidfile: /usr/local/nginx/logs/nginx.pid # Source function library. . /etc/rc.d/init.d/functions # Source networking configuration. . /etc/sysconfig/network # Check that networking is up. [ " $NETWORKING " = "no" ] && exit 0 nginx = "/usr/local/nginx/sbin/nginx" prog = $( basename

apache virtual host and “Dynamic” Domains

由 可紊 提交于 2020-01-13 04:23:46
问题 I have a java application responding multiple domains and uses, for each domain, a specific apache virtual host. This because Apache is faster than tomcat, to serve static resources. The need is to do that at runtime, without restart apache configuration. To perform this action I'm using VirtualDocumentRoot directive, as described below: AddType text/html .html .shtml AddOutputFilter INCLUDES .html .shtml NameVirtualHost *:80 UseCanonicalName Off <VirtualHost *:80> ServerName domain.com

What could cause an Android activity to relaunch itself infinitely when returning from camera?

由 馋奶兔 提交于 2020-01-12 04:57:05
问题 I have a weird bug in my application that causes an activity to relaunch itself in an infinite loop when I'm returning from a camera application, after taking a picture. The UI flow is like this: Main Activity -> Accept Photo activity -> in onCreate() open camera with startActivityForResult() Camera screen -> take picture (or cancel) -> return to Accept Photo The Accept Photo screen is created completely and immediately stopped and recreated in an infinite loop The weird part is that it only

Dynamically update Apache config “allow from IP” without a restart/reload?

由 那年仲夏 提交于 2020-01-01 07:04:59
问题 My goal is to allow access to an Apache 2.2 forwarding proxy to the IPs of logged-in users only, while denying all other IPs. In the proxy virtual host, I've successfully included an "allow from" file that gets dynamically rewritten every time a user logs in or out of the site (adding the IP of logged-in users while deleting the IP of logged-out users). However, this requires a graceful restart/reload of Apache to take effect, and I'm looking to improve the performance if I can... because as
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