resolve

How does Unity.Resolve know which constructor to use?

霸气de小男生 提交于 2019-11-28 18:36:43
Given a class with several constructors - how can I tell Resolve which constructor to use? Consider the following example class: public class Foo { public Foo() { } public Foo(IBar bar) { Bar = bar; } public Foo(string name, IBar bar) { Bar = bar; Name = name; } public IBar Bar { get; set; } public string Name { get; set; } } If I want to create an object of type Foo using Resolve how will Resolve know which constructor to use? And how can I tell it to use the right one? Let's say I have a container with an IBar registered - will it understand that it should favor the constructor taking IBar?

How to manually add a path to be resolved in eslintrc

天大地大妈咪最大 提交于 2019-11-28 17:30:46
问题 I have a folder in my project main that I am resolving like a module. For instance import x from 'main/src' imports main/src/index.js . This is done through webpack's resolve alias configuration. An issue I am having is getting rid of the errors via eslint. I know eslint provides a webpack resolve plugin, however, I've been having trouble getting it to work. I suspect it is because I am on webpack 2 and using es6 in my webpack config files. Is there a manual way to write a resolve setting

Git resolve conflict using --ours/--theirs for all files

China☆狼群 提交于 2019-11-28 13:52:37
问题 Is there a way to resolve conflict for all files using checkout --ours and --theirs ? I know that you can do it for individual files but couldn't find a way to do it for all. 回答1: Just grep through the working directory and send the output through the xargs command: grep -lr '<<<<<<<' . | xargs git checkout --ours or grep -lr '<<<<<<<' . | xargs git checkout --theirs How this works: grep will search through every file in the current directory (the . ) and subdirectories recursively (the -r

How to load Angular-translate before any UI is displayed with ui-router resolve

那年仲夏 提交于 2019-11-28 06:32:46
问题 I used angular-translate for i18n. I want to use $translatePartialLoader service to modular language key as lazy load. Also I want to use ui-router resolve option for this. Now How to do this? Is possible add a code sample for me? Thanks 回答1: I find solutions and solve my problem. In config: $translatePartialLoaderProvider.addPart('index'); $translateProvider .useSanitizeValueStrategy(null) .fallbackLanguage('en-us') .registerAvailableLanguageKeys(['en-us','pt-br'], { 'en_*': 'en-us', 'pt_*':

Angular 7+: HMR (Hot Module Replacement) does not work if any route-resolve involved

被刻印的时光 ゝ 提交于 2019-11-27 18:12:28
问题 HMR (Hot Module Replacement) is a great functionality, that works properly if no "Route-resolve" (see below) is present. If I remove resolve here: { path: 'new', component: BookNewComponent, data: { breadcrumb: 'book.new.breadcrumb' }, resolve: { staticData: StaticDataResolve } }, HMR is working again. If resolve exists -> HMR reloads the whole app instead of a specific component. How can I solve this problem? 来源: https://stackoverflow.com/questions/55355133/angular-7-hmr-hot-module

Getting variable by name in C#

孤人 提交于 2019-11-27 15:06:50
Is there a way to get the value of a variable just by knowing the name of it, like this: double temp = (double)MyClass.GetValue("VariableName"); When I normally would access the variable like this double temp = MyClass.VariableName; You could use reflection . For example if PropertyName is a public property on MyClass and you have an instance of this class you could: MyClass myClassInstance = ... double temp = (double)typeof(MyClass).GetProperty("PropertyName").GetValue(myClassInstance, null); If it's a public field : MyClass myClassInstance = ... double temp = (double)typeof(MyClass).GetField

How does Unity.Resolve know which constructor to use?

坚强是说给别人听的谎言 提交于 2019-11-27 11:31:26
问题 Given a class with several constructors - how can I tell Resolve which constructor to use? Consider the following example class: public class Foo { public Foo() { } public Foo(IBar bar) { Bar = bar; } public Foo(string name, IBar bar) { Bar = bar; Name = name; } public IBar Bar { get; set; } public string Name { get; set; } } If I want to create an object of type Foo using Resolve how will Resolve know which constructor to use? And how can I tell it to use the right one? Let's say I have a

Angularjs ui-router. How to redirect to login page

老子叫甜甜 提交于 2019-11-27 02:58:05
I have 4 states: dashboard , dahboard.main , dashboard.minor , login . dashboard is abstract and it is a parent state for .minor and .main states. Below is my code: .state('dashboard', { url: "/dashboard", abstract: true, templateUrl: "views/dashboard.html", resolve: { auth: function ($q, authenticationSvc) { var userInfo = authenticationSvc.getUserInfo(); if (userInfo) { return $q.when(userInfo); } else { return $q.reject({ authenticated: false }); } } }, controller: "DashboardCtrl", data: { pageTitle: 'Example view' } }) .state('dashboard.main', { url: "", templateUrl: "views/main.html",

Getting variable by name in C#

≡放荡痞女 提交于 2019-11-26 17:01:05
问题 Is there a way to get the value of a variable just by knowing the name of it, like this: double temp = (double)MyClass.GetValue("VariableName"); When I normally would access the variable like this double temp = MyClass.VariableName; 回答1: You could use reflection. For example if PropertyName is a public property on MyClass and you have an instance of this class you could: MyClass myClassInstance = ... double temp = (double)typeof(MyClass).GetProperty("PropertyName").GetValue(myClassInstance,

Angularjs ui-router. How to redirect to login page

隐身守侯 提交于 2019-11-26 10:17:59
问题 I have 4 states: dashboard , dahboard.main , dashboard.minor , login . dashboard is abstract and it is a parent state for .minor and .main states. Below is my code: .state(\'dashboard\', { url: \"/dashboard\", abstract: true, templateUrl: \"views/dashboard.html\", resolve: { auth: function ($q, authenticationSvc) { var userInfo = authenticationSvc.getUserInfo(); if (userInfo) { return $q.when(userInfo); } else { return $q.reject({ authenticated: false }); } } }, controller: \"DashboardCtrl\",