replace

问题 I am stuck in a situation where I have a list and I want to change subnet /21 to /24 . x = ['192.168.8.1/21', '192.168.4.36/24', '192.168.47.54/16'] for a in x: if "21" in (a[-2:]): print(a) else: print("carry on") Now it's printing right values but how I can change the values of a[-2:] 21 to 24 I fail to understand. Output: 192.168.8.1/21 carry on carry on 回答1: You cannot change a part of a string as strings are immutable. But you can replace the string with a corrected version. x = ['192

问题 I have dictionary and created Pandas using cars = pd.DataFrame.from_dict(cars_dict, orient='index') and sorted the index (columns in alphabetical order cars = cars.sort_index(axis=1) After sorting I noticed the DataFrame has NaN and I wasn't sure if the really np.nan values? print(cars.isnull().any()) and all column shows false. I have tried different method to convert those "NaN" values to zero which is what I want to do but non of them is working. I have tried replace and fillna methods and

问题 I have dictionary and created Pandas using cars = pd.DataFrame.from_dict(cars_dict, orient='index') and sorted the index (columns in alphabetical order cars = cars.sort_index(axis=1) After sorting I noticed the DataFrame has NaN and I wasn't sure if the really np.nan values? print(cars.isnull().any()) and all column shows false. I have tried different method to convert those "NaN" values to zero which is what I want to do but non of them is working. I have tried replace and fillna methods and

问题 Here is he link: https://www.freecodecamp.org/learn/javascript-algorithms-and-data-structures/intermediate-algorithm-scripting/pig-latin. By using replace and regex: I have captured c , but I want to set it at the end of onsonant plus ay using the replace function in JavaScript Here is my code: function translatePigLatin(str) { let regEx=/([bcd-fgh-klmn-pqrst-vwxyz])/i console.log(str.replace(regEx, '$1,')) } translatePigLatin("consonant"); 回答1: See if that's what you want function

问题 I'm trying to replace some characters in a string with their uppercase/lowercase equivalents in Atom Editor. Let’s say I have the string: some:test:sequence and want the result: Some:Test:Sequence I’m aware of things like \u$1 and \l$1 , but they do not work in Atom, as Atom is using JS-style RegEx. The JS-RegEx solutions I found, however, always involve calling a function (see example here), which is not possible in Atom, afaik. Does anyone know if there is a way to achieve this? I also don

问题 In a file called sample.txt , I have the following text: Once there is a tortoise and a rabbit. The rabbit was fast, tortoise was slow. Rabbit used to mock the tortoise. Once the rabbit challenged the tortoise for a race. Tortoise accepted rabbit’s request. Rabbit was overconfident. Rabbit thought to win the race. Rabbit ran fast. Then rabbit got tired. Rabbit wanted to take rest. So rabbit slept under the tree. Tortoise kept going and won the race. How to replace every second occurrence of

问题 Modifying a Perl script , i got this: $var =~ s,/$,,; it seems to be a regex pattern, but i was expecting to found "/" (or "|") instead of "," as separator. So the question is: when and why one should use in a regex pattern "/" or "|" or ","? 回答1: In Perl, in the substitution operator, as well as many other operators, you can substitute the delimiter for almost any punctuation character, such as s#/$## s=/$== s!/$!! Which one to use when is a matter of what you need at the time. Preferably

问题 Modifying a Perl script , i got this: $var =~ s,/$,,; it seems to be a regex pattern, but i was expecting to found "/" (or "|") instead of "," as separator. So the question is: when and why one should use in a regex pattern "/" or "|" or ","? 回答1: In Perl, in the substitution operator, as well as many other operators, you can substitute the delimiter for almost any punctuation character, such as s#/$## s=/$== s!/$!! Which one to use when is a matter of what you need at the time. Preferably

问题 I have the following string and list 'changewords'. I would like to replace the '{word from list} \n' with '{word from list}:' I don't want to replace all instances of '\n'. string = "Foo \n value of something \n Bar \n Another value \n" changewords = ["Foo", "Bar"] Desired Output: 'Foo: value of something \n Bar: Another value \n' I have tried the following for i in changewords: tem = re.sub(f'{i} \n', f'{i}:', string) tem Output: 'Foo \n value of something \n Bar: Another value \n' and

问题 I have the following string and list 'changewords'. I would like to replace the '{word from list} \n' with '{word from list}:' I don't want to replace all instances of '\n'. string = "Foo \n value of something \n Bar \n Another value \n" changewords = ["Foo", "Bar"] Desired Output: 'Foo: value of something \n Bar: Another value \n' I have tried the following for i in changewords: tem = re.sub(f'{i} \n', f'{i}:', string) tem Output: 'Foo \n value of something \n Bar: Another value \n' and