replace

问题 I import an SQL file to my database but there is something wrong. All punctuation at the end of a sentence/phrase have extra space. Example: This is a sentence . This , as you can see , is a problem . Do it ! Should be: This is a sentence. This, as you can see, is a problem. Do it! To correct, I am planning to run SQL commands on phpMyAdmin in this context UPDATE book SET content = REPLACE(content,' .','.'); UPDATE book SET content = REPLACE(content,' ,',','); UPDATE book SET content =

问题 The overhead in looping through the string and replacing double spaces with single ones is taking too much time. Is a faster way of trying to replace multi spacing in strings with a single whitespace? I've been doing it like this, but it's just way too long and wasteful: str1 = "This is a foo bar sentence with crazy spaces that irritates my program " def despace(sentence): while " " in sentence: sentence = sentence.replace(" "," ") return sentence print despace(str1) 回答1: look at this In [1]:

问题 How do I do to change the first occurrence of a word in a string? Example: $a = "Yo! **Hello** this is the first word of Hello in this sentence"; to $b = "Yo! **Welcome** this is the first word of Hello in this sentence"; 回答1: This works, although a bit inefficient: $a = "Yo! **Hello** this is the first word of Hello in this sentence"; $a = preg_replace('/Hello/', 'Welcome', $a, 1); The other popular answer: $b = str_replace('Hello', 'Welcome', $a, 1); does not work. The fourth argument of

问题 re.sub('a(b)','d','abc') yields dc , not adc . Why does re.sub replace the entire capturing group, instead of just capturing group'(b)'? 回答1: Because it's supposed to replace the whole occurrence of the pattern: Return the string obtained by replacing the leftmost non-overlapping occurrences of the pattern in string by the replacement repl. If it were to replace only some subgroup, then complex regexes with several groups wouldn't work. There are several possible solutions: Specify pattern in

问题 I am using this code which is a batch find and replace macro. It finds and replaces the words in the document by reading the replacement words from another document (text.docx). This works absolutely fine when there are a handful of changes (i.e. less than 1 page). However, I hope to use this macro on documents that are 10-20 pages. When I use it, the word document just immediately crashes (starts not responding) and has to be forced to quit. Does anyone have any tips on what can be done to

问题 Is there any way to replace range of numbers wih single numbers in a character string? Number can range from n-n, most probably around 1-15, 4-10 ist also possible. the range could be indicated with a) - a <- "I would like to buy 1-3 cats" or with a word b) for example: to, bis, jusqu'à b <- "I would like to buy 1 jusqu'à 3 cats" The results should look like "I would like to buy 1,2,3 cats" I found this: Replace range of numbers with certain number but could not really use it in R. 回答1:

问题 Is there any way to replace range of numbers wih single numbers in a character string? Number can range from n-n, most probably around 1-15, 4-10 ist also possible. the range could be indicated with a) - a <- "I would like to buy 1-3 cats" or with a word b) for example: to, bis, jusqu'à b <- "I would like to buy 1 jusqu'à 3 cats" The results should look like "I would like to buy 1,2,3 cats" I found this: Replace range of numbers with certain number but could not really use it in R. 回答1:

问题 I have a dataframe df_in like so: import pandas as pd dic_in = {'A':['aa','aa','bb','cc','cc','cc','cc','dd','dd','dd','ee'], 'B':['200','200','200','400','400','500','700','700','900','900','200'], 'C':['da','cs','fr','fs','se','at','yu','j5','31','ds','sz']} df_in = pd.DataFrame(dic_in) I would like to investigate the 2 columns A and B in the following way. I 2 consecutive rows[['A','B']] are equal then they are assigned a new value (according to a specific rule which i am about to describe

问题 I want to replace the nth char in the original string. I can access the nth char from the string by using chars[i] , but when I assign a value to chars[i] , I get an error. package main import "fmt" func main() { var chars = "abcdef" fmt.Println(string(chars[3])) chars[3] = "z" // is not working } 回答1: This is happening because chars is actually a string and is immutable. If you declared it appropriately (as a byte slice) then you can assign to it as you're attempting. Here's an example;

问题 I need to split a string by commas, but I have a problem with this case: TEXT EXAMPLE (THIS IS (A EXAMPLE, BUT NOT WORKS, FOR ME)), SECOND , THIRD I would like to split and get: var[0] = "TEXT EXAMPLE (THIS IS (A EXAMPLE, BUT NOT WORKS, FOR ME))" var[1] = "SECOND" var[2] = "THIRD" Thank you 回答1: You can use this negative lookahead based regex: ,(?!(?:[^(]*\([^)]*\))*[^()]*\)) This regex is finding a comma with an assertion that makes sure comma is not in parentheses. This is done using a