repeat

R - delete consecutive (ONLY) duplicates

落爺英雄遲暮 提交于 2019-12-01 03:56:45
问题 I need to eliminate rows from a data frame based on the repetition of values in a given column, but only those that are consecutive. For example, for the following data frame: df = data.frame(x=c(1,1,1,2,2,4,2,2,1)) df$y <- c(10,11,30,12,49,13,12,49,30) df$z <- c(1,2,3,4,5,6,7,8,9) x y z 1 10 1 1 11 2 1 30 3 2 12 4 2 49 5 4 13 6 2 12 7 2 49 8 1 30 9 I would need to eliminate rows with consecutive repeated values in the x column, keep the last repeated row, and maintain the structure of the

TestNG retryAnalyzer only works when defined in methods @Test, does not work in class' @Test

亡梦爱人 提交于 2019-12-01 00:41:55
This works as supposed, test fails (due to haltTesting()) and is repeated 2x public class A0001_A0003Test extends TestControl { private Kunde kunde = Kunde.FR_WEHLITZ; @Test(retryAnalyzer = TestRepeat.class, groups = {TestGroups.FAILED}, description = "verify adress") public void testkundenDaten_Angaben() throws Exception { bifiTestInitial(); testActions.selectKunde(kunde); haltTesting(); } } but because i have multiple tests in one class, i defined the repeatAnalyzer on class level @Test(retryAnalyzer = TestRepeat.class) public class A0001_A0003Test extends TestControl { private Kunde kunde =

Can't do shell script with a repeat with i from 1 to n loop

三世轮回 提交于 2019-11-30 23:46:47
This works (prints, for example, “3 arguments”): to run argv do shell script "echo " & (count argv) & " arguments" end run This doesn't (prints only “Argument 3: three”, and not the previous two arguments): to run argv do shell script "echo " & (count argv) & " arguments" repeat with i from 1 to (count argv) do shell script "echo 'Argument " & i & ": " & (item i of argv) & "'" end repeat end run In both cases, I'm running the script using osascript on Mac OS X 10.5.5. Example invocation: osascript 'Script that takes arguments.applescript' Test argument three I'm not redirecting the output, so

How to create missing value for repeated measurement data?

和自甴很熟 提交于 2019-11-30 23:08:52
I have a data set that not every subject’s observations were observed at the exact same time points, but I want to turn it in to a data set that every one’s observations were observed at the exact same time points (so that I can use it in SAS proc traj). For example, suppose I have dataset "m": id <- c(1,1,1,1,2,2,3,3,3) age <- c(2,3,4,5,3,6,2,5,8) IQ <- c(3,4,5,4,6,5,3,8,10) m <- data.frame(id,age,IQ) > m id age IQ 1 1 2 3 2 1 3 4 3 1 4 5 4 1 5 4 5 2 3 6 6 2 6 5 7 3 2 3 8 3 5 8 9 3 8 10 > unique(age) [1] 2 3 4 5 6 8 I want to turn m to m2. But I can only do that manually. id2 <- c(1,1,1,1,1,1

CSS: Repeat Table Header after Page Break (Print View)

落花浮王杯 提交于 2019-11-30 18:06:17
I have html table for printing with repeat header and footer. Everything works, document to break automatically. But now i would like to break page after any element. I use to css property page-break-after and set it to always. Yes, its works, but i got another problem. Page after break dont repeat header and footer of table. What is wrong? Browsers: IE8. Print styles: table thead {display: table-header-group;} table tfoot { display: table-footer-group;} table tbody { display: table-row-group;} .page-break { page-break-after:always;} Html code: <table> <thead> <tr> <th>...</th> </tr> </thead>

How to write a function that can calculate power in Java. No loops

点点圈 提交于 2019-11-30 16:06:34
问题 I've been trying to write a simple function in Java that can calculate a number to the nth power without using loops. I then found the Math.pow(a, b) class... or method still can't distinguish the two am not so good with theory. So i wrote this.. public static void main(String[] args) { int a = 2; int b = 31; System.out.println(Math.pow(a, b)); } Then i wanted to make my own Math.pow without using loops i wanted it to look more simple than loops, like using some type of Repeat I made a lot of

How to write a function that can calculate power in Java. No loops

北战南征 提交于 2019-11-30 15:44:44
I've been trying to write a simple function in Java that can calculate a number to the nth power without using loops. I then found the Math.pow(a, b) class... or method still can't distinguish the two am not so good with theory. So i wrote this.. public static void main(String[] args) { int a = 2; int b = 31; System.out.println(Math.pow(a, b)); } Then i wanted to make my own Math.pow without using loops i wanted it to look more simple than loops, like using some type of Repeat I made a lot of research till i came across the commons-lang3 package i tried using StringUtils.repeat So far I think

gem ice_cube for reccurence events

感情迁移 提交于 2019-11-30 15:35:08
I have simple Event model (title, date, user) And I created Events Calendar by months (gem 'watu_table_builder'). I need the feature to create repeating events. I figured out that I may use gem ice_cube for it. But it is not clear for me. I added to model: class Event < ActiveRecord::Base #require 'ice_cube' include IceCube belongs_to :user validates :title, :presence => true, :length => { :minimum => 5 } validates :shedule, :presence => true def self.events_and_repeats(date) @events = Event.where(shedule:date.beginning_of_month..date.end_of_month) # Here I need to figure out what is events

regex repeated character count

五迷三道 提交于 2019-11-30 14:28:18
问题 If I have a set of characters like "abcdefghij" and using this characters, I generate random a password using this characters. A generated password can have, for example, 6 characters. How to validate a password using regex so that tho neighbor characters are not identical and a character does not repeat more that twice? 回答1: You could use something like: /^ (?:(.) (?!\1) # neighbor characters are not identical (?!(?>.*?\1){2}) # character does not occur more than twice )* \z/x Perl quoting,

How can I return multiple identical rows based on a quantity field in the row itself?

自闭症网瘾萝莉.ら 提交于 2019-11-30 12:42:46
I'm using oracle to output line items in from a shopping app. Each item has a quantity field that may be greater than 1 and if it is, I'd like to return that row N times. Here's what I'm talking about for a table product_id, quanity 1, 3, 2, 5 And I'm looking a query that would return 1,3 1,3 1,3 2,5 2,5 2,5 2,5 2,5 Is this possible? I saw this answer for SQL Server 2005 and I'm looking for almost the exact thing in oracle. Building a dedicated numbers table is unfortunately not an option. I've used 15 as a maximum for the example, but you should set it to 9999 or whatever the maximum quantity