repeat

问题 This question already has answers here : Converting integer to string in Python (14 answers) Repeat string to certain length (13 answers) Closed 1 year ago . How do I print a number n times in Python? I can print 'A' 5 times like this: print('A' * 5) AAAAA but not 10, like this: print(10 * 5) 50 I want the answer to be 10 10 10 10 10 How do I escape the mathematical operation in print() ? I am not asking how to print the string '10' n times, I am asking how to print the number 10 n times. 回答1

问题 How do I repeat each element of a list n times and form a new list? For example: x=[1,2,3,4] n=3 Looking for: [1,1,1,2,2,2,3,3,3,4,4,4] 回答1: An inner argument to repeat is what I was looking for: repeat([1, 2, 3, 4], inner = 3) 回答2: Also list comprehension: x = [1,2,3,4] n = 3 result = [i for i in x for j in 1:n] 来源： https://stackoverflow.com/questions/60234868/how-to-repeat-elements-in-list-n-times

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 4 years ago . Improve this question I am looking for a function in Python where you give a string as input where a certain word has been repeated several times until a certain length has reached. The output would then be that word. The repeated word isn't necessary repeated in its whole and it

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 4 years ago . Improve this question I am looking for a function in Python where you give a string as input where a certain word has been repeated several times until a certain length has reached. The output would then be that word. The repeated word isn't necessary repeated in its whole and it

问题 I would like to run a function (make an api call) at fixed time everyday, say 10 am and 10 pm daily. What would be the cronjob equivalent in swift? I tried implementing Timer as: var dateComponents = DateComponents() dateComponents.timeZone = TimeZone(abbreviation: "NPT") dateComponents.hour = 10 dateComponents.minute = 00 let userCalendar = Calendar.current let myTime = userCalendar.date(from: dateComponents) let timer = Timer(fireAt: myTime!, interval: 0, target: self, selector: #selector

问题 I would like to run a function (make an api call) at fixed time everyday, say 10 am and 10 pm daily. What would be the cronjob equivalent in swift? I tried implementing Timer as: var dateComponents = DateComponents() dateComponents.timeZone = TimeZone(abbreviation: "NPT") dateComponents.hour = 10 dateComponents.minute = 00 let userCalendar = Calendar.current let myTime = userCalendar.date(from: dateComponents) let timer = Timer(fireAt: myTime!, interval: 0, target: self, selector: #selector

问题 I have this dataframe which includes nans: Date 0 7.0 1 8.0 2 9.0 3 10.0 4 11.0 5 12.0 6 1.0 7 2.0 8 3.0 9 4.0 10 5.0 11 6.0 ... 90 NaN 91 NaN The Date values are the month number, and I know that on the index 90 it is a 1 but I want to fill the other NaNs with 2, 3 etc until 12 then goes back to 1, 2 and so on. Lets say it just like in Excel, when you want to fill a column, you put the first values then select them and slide all the way and it fills automatically. Any ideas ? Thanks ! 回答1:

问题 In DCG how do you implement : zero-or-more, zero-or-one , one-or-more occurrences ? I'm talking about the following in pseudo code : sentence --> word+ float --> int+, ['.'], int+ nilORa --> a? nilORaaaa --> a* 回答1: You use the or-nondeterminism offered by the clause set of a predicate (or, in this case, the set of DCG productions for the same DCG "nonterminal" - the DCG production is an alternative notation for a Horn clause) Move the production that should be performed first to the top. For

问题 This question already has answers here : How to duplicate Python dataframe one by one? (5 answers) Closed 2 years ago . My pandas dataframe looks like this: Person ID ZipCode Gender 0 12345 882 38182 Female 1 32917 271 88172 Male 2 18273 552 90291 Female I want to replicate every row 3 times like: Person ID ZipCode Gender 0 12345 882 38182 Female 0 12345 882 38182 Female 0 12345 882 38182 Female 1 32917 271 88172 Male 1 32917 271 88172 Male 1 32917 271 88172 Male 2 18273 552 90291 Female 2

问题 This question already has answers here : How to duplicate Python dataframe one by one? (5 answers) Closed 2 years ago . My pandas dataframe looks like this: Person ID ZipCode Gender 0 12345 882 38182 Female 1 32917 271 88172 Male 2 18273 552 90291 Female I want to replicate every row 3 times like: Person ID ZipCode Gender 0 12345 882 38182 Female 0 12345 882 38182 Female 0 12345 882 38182 Female 1 32917 271 88172 Male 1 32917 271 88172 Male 1 32917 271 88172 Male 2 18273 552 90291 Female 2