rep

I have a data frame with 1666 rows. I would like to add a column with a repeating sequence of 1:5 to use with cut() to do cross validation. It would look like this: Y x1 x2 Id1 1 .15 3.6 1 0 1.1 2.2 2 0 .05 3.3 3 0 .45 2.8 4 1 .85 3.1 5 1 1.01 2.9 1 ... ... ... ... I've tried the following 2 ways but get an error message as it seems to only add numbers in increments of the full seq() argument: > tr2$Id1 <- rep(seq(1,5,1), (nrow(tr2)/5)) Error in `$<-.data.frame`(`*tmp*`, "Id", value = c(1, 2, 3, 4, 5, 1, 2, : replacement has 1665 rows, data has 1666 > tr2$Id1 <- rep(seq(1,5,1), (nrow(tr2)/5) +

How to assign more than one value for "each" argument in "rep" function in R? A trivial example, where each value in a vector is 3-times repeated in a row: a <- seq(2,6,2) rep (a,each = 3) However, if I add more than one value in "each" argument in order to change the number of repetition of each value, it doesn't work properly: rep (a, each = c(2,4,7)) How to solve it? Thank you in advance. well, depending on what you think the output should be, I'm guessing you want the times= parameter rep (a, times=c(2,4,7)) # [1] 2 2 4 4 4 4 6 6 6 6 6 6 6 See ?rep for the difference 来源： https:/